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Tom will cultivate bacteria. The number of bacteria he will cultivate

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srij13
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Tom will cultivate bacteria. The number of bacteria he will cultivate [#permalink] New post   26 May 2019, 23:43
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Tom will cultivate bacteria. The number of bacteria he will cultivate after one day is 150 percent of that of the previous day. The total number of bacteria is 4,725 after 2 days. What is the value of the original number of bacteria on the first day?

A. 1,200 B. 1,500 C. 1,600 D. 1,800 E. 2,100
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Re: Tom will cultivate bacteria. The number of bacteria he will cultivate [#permalink] New post   27 May 2019, 01:46
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srij13 wrote:
Tom will cultivate bacteria. The number of bacteria he will cultivate after one day is 150 percent of that of the previous day. The total number of bacteria is 4,725 after 2 days. What is the value of the original number of bacteria on the first day?

A. 1,200 B. 1,500 C. 1,600 D. 1,800 E. 2,100


Each day he will cultivate 150% of the number of the previous day.

So say he has x bacteria on 24th May, 12 midnight.
He will have (150/100)x bacteria on 25th May, 12 midnight.
And (150/100*(150/100)x bacteria on 26th may, 12 midnight.

So after two days, he has (150/100)*(150/100)x = 4725 bacteria

x = 2100

So original number of bacteria (beginning of the day) on the first day = 2100

Answer (E)
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Re: Tom will cultivate bacteria. The number of bacteria he will cultivate [#permalink] New post   26 May 2019, 23:48
Can someone tell me how the equation comes out for the above question? What I did -
x= No of bacteria on day one
1.5x= No of bacteria on day two

Adding them together x + 1.5x = 4725

But this seems wrong.

Please Help!!! Bunuel
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Re: Tom will cultivate bacteria. The number of bacteria he will cultivate [#permalink] New post   26 May 2019, 23:53
srij13 wrote:
Can someone tell me how the equation comes out for the above question? What I did -
x= No of bacteria on day one
1.5x= No of bacteria on day two

Adding them together x + 1.5x = 4725

But this seems wrong.

Please Help!!! Bunuel


I'm getting 1350.
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Tom will cultivate bacteria. The number of bacteria he will cultivate [#permalink] New post   Updated on: 27 May 2019, 00:14
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srij13 wrote:
Tom will cultivate bacteria. The number of bacteria he will cultivate after one day is 150 percent of that of the previous day. The total number of bacteria is 4,725 after 2 days. What is the value of the original number of bacteria on the first day?

A. 1,200 B. 1,500 C. 1,600 D. 1,800 E. 2,100


Initially = x
Total After day 1= x + 1.5x = 2.5x
Total After day 2= 1.5(2.5x) = 3.375x

So 3.375x = 4725
—> x = 1400

After first day = 1.5x = 2100

IMO E

Posted from my mobile device

Originally posted by CareerGeek on 27 May 2019, 00:06.
Last edited by CareerGeek on 27 May 2019, 00:14, edited 2 times in total.
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Re: Tom will cultivate bacteria. The number of bacteria he will cultivate [#permalink] New post   27 May 2019, 00:09
Dillesh4096 wrote:
srij13 wrote:
Tom will cultivate bacteria. The number of bacteria he will cultivate after one day is 150 percent of that of the previous day. The total number of bacteria is 4,725 after 2 days. What is the value of the original number of bacteria on the first day?

A. 1,200 B. 1,500 C. 1,600 D. 1,800 E. 2,100


Initially = x
On day 1 = 1.5x
After day 1= x + 1.5x = 2.5x
After day 2= 1.5(2.5x) = 3.375x

So 3.375x = 4725
—> x = 1400

On first day = 1.5x = 2100

IMO E

Posted from my mobile device


Aren't you counting 3 days?

VeritasKarishma please help.
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Re: Tom will cultivate bacteria. The number of bacteria he will cultivate [#permalink] New post   01 Jul 2019, 03:48
srij13 wrote:
Tom will cultivate bacteria. The number of bacteria he will cultivate after one day is 150 percent of that of the previous day. The total number of bacteria is 4,725 after 2 days. What is the value of the original number of bacteria on the first day?

A. 1,200 B. 1,500 C. 1,600 D. 1,800 E. 2,100



If the right answer is E and the value of the original number of bacteria on the first day is 2100, that means that a number of bacterias on the 2nd day is 2100*1,5+2100=5250, but not 4725.
Can somebody explain this?

The way I see it:
x - bacterias on day 0
x+1,5x - bacterias on day 1
(x+1,5x)*1,5 = 4725 - bacterias on day 2

so let's find x

1,5x+2,25x=4725
3,75x=4725
x=1260 - this is on day 0, but we need on day 1, so
1260+1,5*1260=3150

Where am I wrong?

Thank you for help
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Re: Tom will cultivate bacteria. The number of bacteria he will cultivate [#permalink] New post   03 Apr 2023, 17:04
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Re: Tom will cultivate bacteria. The number of bacteria he will cultivate [#permalink]
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