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David has 26 coins in a jar, and all the coins are dimes and nickels.

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Bunuel
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David has 26 coins in a jar, and all the coins are dimes and nickels. [#permalink] New post   18 Feb 2020, 02:16
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David has 26 coins in a jar, and all the coins are dimes and nickels. How many nickels are in the jar?

(1) David spent part of the money on a soft drink.
(2) The value of the coins is $1.85.
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Re: David has 26 coins in a jar, and all the coins are dimes and nickels. [#permalink] New post   18 Feb 2020, 02:28
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David has 26 coins in a jar, and all the coins are dimes and nickels. How many nickels are in the jar?

(1) David spent part of the money on a soft drink.
(2) The value of the coins is $1.85.

1 Dime = 10 cents = 0.1$
1 Nickel = 5 cents = 0.05$

St1) clearly NOT SUFFICIENT
St2) let the number of Dime coins = D
and number of Nickel coins = N

As per Question D+N= 26
As per St2, 0.1D+0.05N= 1.85

We have two equations and 2 variables, hence we can find the value of D & N

SUFFICIENT.

Answer B
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Re: David has 26 coins in a jar, and all the coins are dimes and nickels. [#permalink] New post   18 Feb 2020, 02:36
1) - Irrelevant
2) Correct : Only one case is possible , 11 dimes & 15 nickels

so B)
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Re: David has 26 coins in a jar, and all the coins are dimes and nickels. [#permalink] New post   18 Feb 2020, 03:17
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From the Problem you get the following

A+B=26

From point b you get

0.1*A+0.05*B=26

you have 2 equiations with 2 unknows and you get the numbers
A=11 and B=15

Thus the answer is B
(b) is enough
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Re: David has 26 coins in a jar, and all the coins are dimes and nickels. [#permalink] New post   18 Feb 2020, 03:59
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Dime= 10cents, d nos.
Nickel= 5cents, n nos.
d+n=26

(1) David spent part of the money on a soft drink.
This statement is not useful to determine how many nickels are in the jar.
NOT SUFFICIENT

(2) The value of the coins is $1.85. --> 185 = 10d + 5n
Two known equations are sufficient to determine that d=11 and n=15.
SUFFICIENT

FINAL ANSWER IS (B)

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Re: David has 26 coins in a jar, and all the coins are dimes and nickels. [#permalink] New post   18 Feb 2020, 04:40
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Quote:
David has 26 coins in a jar, and all the coins are dimes and nickels. How many nickels are in the jar?

(1) David spent part of the money on a soft drink.
(2) The value of the coins is $1.85.


d + n = 26

Question: n = ?

Statement 1: Davind spent some money

No information about the money available and money spent hence

NOT SUFFICIENT

Statement 2: Value of coins = $1.85

i.e. 10d + 5n = 185
also we know that d+n = 26
Solving teh two equation we get n = 15

SUFFICIENT

Answer: Option B

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David has 26 coins in a jar, and all the coins are dimes and nickels. [#permalink] New post   Updated on: 19 Feb 2020, 08:41
given dime+nickel = 26
find nickel
#1
David spent part of the money on a soft drink.
insufficient clearly as no info know
#2
The value of the coins is $1.85
.01d+.05n=1.85
d+n=26
sufficient

IMO B ; sufficient

David has 26 coins in a jar, and all the coins are dimes and nickels. How many nickels are in the jar?

(1) David spent part of the money on a soft drink.
(2) The value of the coins is $1.85.

Originally posted by Archit3110 on 18 Feb 2020, 08:13.
Last edited by Archit3110 on 19 Feb 2020, 08:41, edited 1 time in total.
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Re: David has 26 coins in a jar, and all the coins are dimes and nickels. [#permalink] New post   18 Feb 2020, 18:47
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Quote:
David has 26 coins in a jar, and all the coins are dimes and nickels. How many nickels are in the jar?

(1) David spent part of the money on a soft drink.
(2) The value of the coins is $1.85.


(1) insufic

(2) sufic
d+n=26
10d+5n=185
10(26-n)+5n=185
260-10n+5n
260-5n=185
5n=260-185=75
n=75/5=15

Ans (B)
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Re: David has 26 coins in a jar, and all the coins are dimes and nickels. [#permalink] New post   18 Feb 2020, 22:04
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David has 26 coins in a jar, and all the coins are dimes and nickels. How many nickels are in the jar?

(1) David spent part of the money on a soft drink.
(2) The value of the coins is $1.85.
From statement (1), nothing can be determined, Insufficient.

From statement (2), Let, number of nickels = n
And number of dimes = 26-n
Now, n/100 + (26 – n)/10 = 1.85, Sufficient.
Answer: B
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Re: David has 26 coins in a jar, and all the coins are dimes and nickels. [#permalink] New post   19 Feb 2020, 00:04
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David has 26 coins in a jar, and all the coins are dimes and nickels. How many nickels are in the jar?

(Statement1): David spent part of the money on a soft drink.
Clearly insufficient

(Statement2): The value of the coins is $1.85.
10d + 5n = 185
d+ n= 26
—> 10(26 —n) + 5n = 185
260 —10n + 5n = 185
5n= 75
—> n= 15
Sufficient

The answer is B

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Re: David has 26 coins in a jar, and all the coins are dimes and nickels. [#permalink]
19 Feb 2020, 00:04
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Bunuel
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