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A bakery keeps flour in two storehouses. The stock in the first storeh
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02 Oct 2020, 07:20
02 Oct 2020, 07:20
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A bakery keeps flour in two storehouses. The stock in the first storehouse decreased by 20% since yesterday, whereas the stock in the second storehouse increased by 20% since yesterday. If each storehouse now contains 12 tons of flour, then what is the change of the stock in total since yesterday?
A. 2 ton decrease
B. 1 ton decrease
C. The stocks haven't changed.
D. 1 ton increase
E. 2 ton increase
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A. 2 ton decrease
B. 1 ton decrease
C. The stocks haven't changed.
D. 1 ton increase
E. 2 ton increase
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Keep it simple. Keep it blank
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Re: A bakery keeps flour in two storehouses. The stock in the first storeh
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02 Oct 2020, 09:05
02 Oct 2020, 09:05
Top Contributor
Let the first store house have x tons of stock.
After a 20% increase the stock is now 12 tons, i.e \(x * \frac{120}{100} = 12\)
x = 10 tons
Let the 2nd store house have y tons of stock.
After a 20% decrease the stock is now 12 tons, i.e \(y * \frac{80}{100} = 12\)
y = 15 tons
Total Initial Stock = 10 + 15 = 25 tons
Total Final Stock = 12 + 12 = 24 tons
Therefore there is a decrease of 1 ton.
Option B
Arun Kumar
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After a 20% increase the stock is now 12 tons, i.e \(x * \frac{120}{100} = 12\)
x = 10 tons
Let the 2nd store house have y tons of stock.
After a 20% decrease the stock is now 12 tons, i.e \(y * \frac{80}{100} = 12\)
y = 15 tons
Total Initial Stock = 10 + 15 = 25 tons
Total Final Stock = 12 + 12 = 24 tons
Therefore there is a decrease of 1 ton.
Option B
Arun Kumar
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Re: A bakery keeps flour in two storehouses. The stock in the first storeh
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02 Oct 2020, 09:10
02 Oct 2020, 09:10
Expert Reply
At one storehouse, the stock increased by 20%, so was multiplied by 1.2, and ended up being 12 tons. If it started with x tons, we have 1.2x = 12, and x = 10.
At the other storehouse, the stock decreased by 20%, so was multiplied by 0.8, and ended up being 12 tons. If it started with y tons, we have 0.8y = 12, and y = 15.
So originally there were 10+15 = 25 tons of flour, and now there are 12+12 = 24 tons of flour, and there has been a 1 ton decrease overall.
At the other storehouse, the stock decreased by 20%, so was multiplied by 0.8, and ended up being 12 tons. If it started with y tons, we have 0.8y = 12, and y = 15.
So originally there were 10+15 = 25 tons of flour, and now there are 12+12 = 24 tons of flour, and there has been a 1 ton decrease overall.
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Re: A bakery keeps flour in two storehouses. The stock in the first storeh
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02 Oct 2020, 10:52
02 Oct 2020, 10:52
globaldesi wrote:
A bakery keeps flour in two storehouses. The stock in the first storehouse decreased by 20% since yesterday, whereas the stock in the second storehouse increased by 20% since yesterday. If each storehouse now contains 12 tons of flour, then what is the change of the stock in total since yesterday?
A. 2 ton decrease
B. 1 ton decrease
C. The stocks haven't changed.
D. 1 ton increase
E. 2 ton increase
A. 2 ton decrease
B. 1 ton decrease
C. The stocks haven't changed.
D. 1 ton increase
E. 2 ton increase
I. \(\frac{12}{80}*100 = 15\)
II. \(\frac{12}{120}*100 = 10\)
Total stock earlier is \(15 + 10 = 25\), Stock now is \(12*2 = 24\), Thus, Difference is 1 ton (Decrease), Answer is (B)
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Re: A bakery keeps flour in two storehouses. The stock in the first storeh
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05 Oct 2020, 07:43
05 Oct 2020, 07:43
Expert Reply
globaldesi wrote:
A bakery keeps flour in two storehouses. The stock in the first storehouse decreased by 20% since yesterday, whereas the stock in the second storehouse increased by 20% since yesterday. If each storehouse now contains 12 tons of flour, then what is the change of the stock in total since yesterday?
A. 2 ton decrease
B. 1 ton decrease
C. The stocks haven't changed.
D. 1 ton increase
E. 2 ton increase
A. 2 ton decrease
B. 1 ton decrease
C. The stocks haven't changed.
D. 1 ton increase
E. 2 ton increase
Solution:
Let x and y be the original number of tons of flour in the first and second storehouses, respectively. We can create the equations:
1.2x = 12
and
0.8y = 12
Solving the first equation, we have x = 12/1.2 = 10 and solving the second equation, we have y = 12/0.8 = 15. Therefore, the total amount of flour in the two storehouses was 10 + 15 = 25 tons originally. Since that total is 12 + 12 = 24 tons now, we see that the total amount of flour is decreased by 1 ton.
Answer: B
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Re: A bakery keeps flour in two storehouses. The stock in the first storeh
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05 Oct 2020, 08:08
05 Oct 2020, 08:08
Expert Reply
Let the initial stock in the first warehouse be 'x' and the second warehouse be 'y'.
After a 20% decrease since yesterday[first warehouse] and the 20% increase since yesterday[second warehouse], it has 12 tons of flour
Current stock: x + y = 12 + 12 = 24
=> (x +y) * \(\frac{80 }{ 100}\) * \(\frac{120 }{ 100}\) = 24
=> x + y = \(\frac{(24 * 100 * 100) }{ (80 * 120)}\)
Previous stock: x + y = 25
1-ton decrease.
Answer B
After a 20% decrease since yesterday[first warehouse] and the 20% increase since yesterday[second warehouse], it has 12 tons of flour
Current stock: x + y = 12 + 12 = 24
=> (x +y) * \(\frac{80 }{ 100}\) * \(\frac{120 }{ 100}\) = 24
=> x + y = \(\frac{(24 * 100 * 100) }{ (80 * 120)}\)
Previous stock: x + y = 25
1-ton decrease.
Answer B
Re: A bakery keeps flour in two storehouses. The stock in the first storeh
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28 Mar 2023, 13:47
28 Mar 2023, 13:47
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Re: A bakery keeps flour in two storehouses. The stock in the first storeh [#permalink]
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