Bunuel wrote:
Tom drives from town A to town B, driving at a constant speed of 60 miles per hour. From town B Tom immediately continues to town C. The distance between A and B is twice the distance between B and C. If the average speed of the whole journey was 36 mph, then what is Tom's speed driving from B to C in miles per hour?
A. 12
B. 20
C. 24
D. 30
E. 36
Since we will be finding ratios we can set the distance from A to B as 60 mi (and travel time in the first part would be 1 h), the distance from B to C as 30 mi. Then set the speed from B to C as x (travel time would be \(\frac{30\text{ mi} }{ x\text{ mph}}\) in the second part), the average speed would be:
\(\frac{\text{Total Distance}}{\text{Total Time}} = 36\)
\(\frac{60 + 30}{\frac{60}{60} + \frac{30}{x}} = 36\)
\(\frac{90}{36} = 1 + \frac{30}{x} = \frac{5}{2}\)
\(\frac{30}{x} = \frac{3}{2}\)
\(x = 20\)
Ans: B
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