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Re: If (3 - x)^(1/2) = x^(1/2) + 3, then x^2 = [#permalink]
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Bunuel wrote:
If \(\sqrt{3-x}= \sqrt{x} + 3\), then \(x^2=\)

(A) 1
(B) 3
(C) 2 − 3x
(D) 3x − 1
(E) 3x − 9


Let's square each side of the given equation:

\(\Rightarrow\) (√(3 - x))^2 = (√x + 3)^2

\(\Rightarrow\) 3 - x = x + 6√x + 9

\(\Rightarrow\) -6 - 2x = 6√x

\(\Rightarrow\) -3 - x = 3√x

Let's square each side of the equation again:

\(\Rightarrow\) (-3 - x)^2 = (3√x)^2

\(\Rightarrow\) 9 + 6x + x^2 = 9x

\(\Rightarrow\) x^2 = 3x - 9

Answer: E
GMAT Club Bot
Re: If (3 - x)^(1/2) = x^(1/2) + 3, then x^2 = [#permalink]
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