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If (3 - x)^(1/2) = x^(1/2) + 3, then x^2 = 05 Oct 2021, 03:15
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E
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Difficulty:

85% (hard)

Question Stats:

54% (02:52) correct 46% (02:57) wrong based on 84 sessions

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If \(\sqrt{3-x}= \sqrt{x} + 3\), then \(x^2=\)

(A) 1
(B) 3
(C) 2 − 3x
(D) 3x − 1
(E) 3x − 9
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E
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If (3 - x)^(1/2) = x^(1/2) + 3, then x^2 = 05 Oct 2021, 06:19
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Option E is the correct answer.
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If (3 - x)^(1/2) = x^(1/2) + 3, then x^2 = 20 Jul 2022, 08:14
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If \(\sqrt{3-x}= \sqrt{x} + 3\), then \(x^2=\)

(A) 1
(B) 3
(C) 2 − 3x
(D) 3x − 1
(E) 3x − 9
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If (3 - x)^(1/2) = x^(1/2) + 3, then x^2 = 20 Jul 2022, 22:50
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Bunuel
If \(\sqrt{3-x}= \sqrt{x} + 3\), then \(x^2=\)

(A) 1
(B) 3
(C) 2 − 3x
(D) 3x − 1
(E) 3x − 9

Let's square each side of the given equation:

\(\Rightarrow\) (√(3 - x))^2 = (√x + 3)^2

\(\Rightarrow\) 3 - x = x + 6√x + 9

\(\Rightarrow\) -6 - 2x = 6√x

\(\Rightarrow\) -3 - x = 3√x

Let's square each side of the equation again:

\(\Rightarrow\) (-3 - x)^2 = (3√x)^2

\(\Rightarrow\) 9 + 6x + x^2 = 9x

\(\Rightarrow\) x^2 = 3x - 9

Answer: E
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