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Manager
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Joined: 22 Jul 2014
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Concentration: General Management, Finance
GMAT 1: 670 Q48 V34
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Magoosh GMAT Instructor
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Manager
Manager
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Re: Two friends A and B leave point A and point B simultaneously and trave [#permalink]
Dear Mike

Sorry.
I have edited the question now.

And thanks for the explanation :-D
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Re: Two friends A and B leave point A and point B simultaneously and trave [#permalink]
Let x per minute be the speed of A and y per minute be the speed of B.
After meeting at a point, A travels for 32 mins and B travels for 50 mins. So distance covered by each of them post point of crossing
A= 32x and B=50y
The distance covered by A and B before they cross each would be distance covered by B and A post crossing respectively.
Therefore distance covered by B before he meets A= 32x
Time taken by B cover 32x distance= 32x/y mins
Therefore total time taken by B= 32x/y + 50 mins ................. I

We need to find value of x in terms of y to arrive at final answer.
Total distance= 32x+50y
Combined speed of A and B= x+y
Therefore time taken before A and B meet en-route= (32x+50y)/(x+y)
Time taken by B reach destination after meeting A= 50 mins
Total travel time for B= [(32x+50y)/(x+y)]+50 mins ...................II

Equate I and II
32x/y+50= [(32x+50y)/(x+y)]+50
(32x+50y)/y=(82x+100y)/(x+y)
32x^2+50xy+32xy+50y^2=82xy+100y^2
32x^2+82xy-82xy+50y^2-100y^2=0
32x^2-50y^2=0
32x^2=50y^2
16x^2=25y^2
Taking square root.. (since x and y denote speed, square root can't be negative)
4x=5y
y=4x/5 ............ III

substitute in I
=32x/(4x/5) + 50
=32x*5/4x + 50
=40+50
=90 mins

Ans=B
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Re: Two friends A and B leave point A and point B simultaneously and trave [#permalink]
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let t=time to meeting
start with equation between two ratios:
t/t+32=50/t+50
t^2=1600
t=40
40+50=90
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Re: Two friends A and B leave point A and point B simultaneously and trave [#permalink]
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Re: Two friends A and B leave point A and point B simultaneously and trave [#permalink]
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