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Re: Can √ 9 be √ (-3^2)? [#permalink]
Dear Mike Mc Garry,

I have modified the 7th line of my original post, in which I omitted an important aspect (see text in blue).

X=-3 ---> √((-3)^2) = √9 = 3 (**)

Nonetheless, your response was very useful and cleared away all my doubts.

Thank you so much!
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Re: Can √ 9 be √ (-3^2)? [#permalink]
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EBITDA wrote:
On a certain book I read that √ 9 can never be √ (-3^2) (**), because we can only put a number equal to or greater than 0 within a root of even index. Hence, √ 9 can only be √ (3^2).

However, on a different page of this same book, I also read the following:

Is it true that √X^2 = X?

Which develops as follows:

X=3 ---> √(3^2) = √9 = 3
X=-3 ---> √((-3)^2) = √9 = 3 (**)

Concluding that: √(X^2) = |X|

Mi question is: Don't notes marked with (**) contradict each other? Which one is correct?

May be I am missing something...

I would really appreciate that you would share your thoughts on this.

Thank you so much.


One thing I might add:

\(\sqrt{(-3)^2} = \sqrt{9}\) is fine.
The point is that when you take the square root of 9, that is only 3.
\(\sqrt{9} = 3\) only

You may find this post useful: https://www.gmatclub.com/forum/veritas-prep-resource-links-no-longer-available-399979.html#/2016/05 ... oots-gmat/
Here I discuss the reason why square root of 9 can only be 3.
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Re: Can √ 9 be √ (-3^2)? [#permalink]
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