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probability

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Intern
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Joined: 02 Jun 2009
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probability [#permalink]

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New post 02 Jun 2009, 03:48
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M = {-6, -5, -4, -3, -2}
T = {-2, -1, 0, 1, 2, 3}

If an integer is to be randomly selected from set M above and an integer is to be randomly selected from set T above, what is the probability that the product of the two integers will be negative?

A. 0
B. 1/3
C. 2/5
D. 1/2
E. 3/5

Kudos [?]: 8 [0], given: 0

Senior Manager
Senior Manager
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Joined: 16 Jan 2009
Posts: 354

Kudos [?]: 239 [0], given: 16

Concentration: Technology, Marketing
GMAT 1: 700 Q50 V34
GPA: 3
WE: Sales (Telecommunications)
Re: probability [#permalink]

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New post 03 Jun 2009, 12:14
what is the probability that the product of the two integers will be negative....

for the product to be negative , one of the two terms should be positive and the other negative.
Since there is no positive term in M , it will always provide the -ve term in the product.
FOr the balance we will choose only positive terms from T.

sample space = 5*6 = 30
no of favourable outcomes = 5C1 * 3C1= 5*3 = 15

prob = 15 / 30 = 1/2
IMO D
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Lahoosaher

Kudos [?]: 239 [0], given: 16

Senior Manager
Senior Manager
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Joined: 15 Jan 2008
Posts: 278

Kudos [?]: 49 [0], given: 3

Re: probability [#permalink]

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New post 04 Jun 2009, 02:25
actually, the problem is a lot simpler than it looks..

As exactly half of the numbers in the second set are positive, therby contributing to the final -ve product.

hence the probability will be 1/2.

Kudos [?]: 49 [0], given: 3

Intern
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Joined: 12 May 2009
Posts: 46

Kudos [?]: 3 [0], given: 1

Location: Mumbai
Re: probability [#permalink]

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New post 04 Jun 2009, 04:30
IMO D;
Answer 1/2

(Possible outcomes/Total outcomes)

Kudos [?]: 3 [0], given: 1

Re: probability   [#permalink] 04 Jun 2009, 04:30
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