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# Probability hard question by MIT professor walter Lewin

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Intern
Joined: 05 Sep 2012
Posts: 6
Probability hard question by MIT professor walter Lewin  [#permalink]

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07 Jun 2017, 04:53
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There are 1000 lotteries
each lottery has 1000 tickets
each lottery has 1 prize
You buy 1 ticket in each of 1000 lotteries thus u end up with 1000 tickets

Q what is the probability that you win at least 3 prizes.

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Intern
Joined: 05 Sep 2012
Posts: 6
Re: Probability hard question by MIT professor walter Lewin  [#permalink]

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07 Jun 2017, 04:56
question is on youtube by name "Second (more difficult) Lottery Problem" could not post link as i am new not allowed.
Math Expert
Joined: 02 Aug 2009
Posts: 7102
Re: Probability hard question by MIT professor walter Lewin  [#permalink]

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07 Jun 2017, 05:04
1
There are 1000 lotteries
each lottery has 1000 tickets
each lottery has 1 prize
You buy 1 ticket in each of 1000 lotteries thus u end up with 1000 tickets

Q what is the probability that you win at least 3 prizes.

would be better if you provide choices..

otherwise this can be solved by finding chances of winning none, 1 or 2 prizes and then subtract from ONE..
winning NONE = $$\frac{999}{1000}^1000$$
winning 1= 1/1000 * (999/1000)^999 * 1000C1
and so on...
now ans = 1- $$\frac{999}{1000}^1000$$-1/1000 * (999/1000)^999 * 1000C1-1/1000 * 1/1000 * (999/1000)^998 * 1000C2
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Location: India
Concentration: General Management, Entrepreneurship
GPA: 3.8
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Re: Probability hard question by MIT professor walter Lewin  [#permalink]

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07 Jun 2017, 05:26
There are 1000 lotteries
each lottery has 1000 tickets
each lottery has 1 prize
You buy 1 ticket in each of 1000 lotteries thus u end up with 1000 tickets

Q what is the probability that you win at least 3 prizes.

Probability of winning a lottery = 1/1000
probability of not winning a lottery = 999/1000

probability of winning none = (999/1000)^1000
Probability of winning 1 lottery = 1000 C1 *(999/1000)^999 * 1/1000=(999/1000)^999
Probability of winning 2 lotteries = 1000 C2 * (999/1000)^998 * 1/1000^2 = (999/1000)^999/2

So probability of winning at least 3 prizes = 1- (999/1000)^1000 - (999/1000)^999- (999/1000)^999/2
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Re: Probability hard question by MIT professor walter Lewin  [#permalink]

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07 Jun 2017, 05:27
1
question is on youtube by name "Second (more difficult) Lottery Problem" could not post link as i am new not allowed.

Kindly post the part of the link leaving https , youtube etc..

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This discussion does not meet community quality standards. It has been retired.

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Re: Probability hard question by MIT professor walter Lewin  [#permalink]

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10 Aug 2018, 22:09
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: Probability hard question by MIT professor walter Lewin &nbs [#permalink] 10 Aug 2018, 22:09
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