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# ps

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Intern
Joined: 17 Dec 2006
Posts: 39

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28 Jan 2009, 06:04
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seems easy but I have a problem with it
"Peter, Martin and John each try independently to solve a problem. if their individual probabilities for success are 1/4, 1/2 and 5/8 respectively, what is the probability that Peter and Martin, but not John will solve the problem?
a) 11/8
b) 7/8
c) 9/64
d) 5/64
e) 3/64

Manager
Joined: 27 Apr 2008
Posts: 110

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28 Jan 2009, 06:15
1
KUDOS
E

(1/4)*(1/2)*(1-5/8)=3/64
Intern
Joined: 17 Dec 2006
Posts: 39

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28 Jan 2009, 07:11
oh my God!!!
thanks a lot
Re: ps   [#permalink] 28 Jan 2009, 07:11
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