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Re: Quant Question of the Day Chat
[#permalink]
30 Apr 2024, 00:31
30 Apr 2024, 00:31
8Harshitsharma wrote:
Because each person after A is doing a "fraction" of the remaining work by the person immediately before. What you said would be true if A,B,C are independently working on the same task. Example if you will, if A,B,C work "together" to create a house, then the method you propose is applicable. However, if A works on the house first and completes 2/3 of it and then B works on the remaining house = (1-2/3) and completes a fraction of the remaining house 1/5*(1-2/3) so remaining house is whatever B has left (1-1/5)*(1-2/3), and then C comes in to complete his fraction of the house which is 1/4, so finally remaining portion of the house in absolute terms is (1-1/4)(1-1/5)(1-2/3)
Hloo. I’m still confused. In the question above, Shouldn’t the remaining work of B after A has done his 2/3rd of the work be, 1-(1/5*(1-2/3)? and not (1-1/5)*(1-2/3) ?
Re: Quant Question of the Day Chat
[#permalink]
30 Apr 2024, 00:39
30 Apr 2024, 00:39
PrabhatKC wrote:
Hloo. I’m still confused. In the question above, Shouldn’t the remaining work of B after A has done his 2/3rd of the work be, 1-(1/5*(1-2/3)? and not (1-1/5)*(1-2/3) ?
What do you mean by "remaining work of B"?
Re: Quant Question of the Day Chat
[#permalink]
30 Apr 2024, 00:40
30 Apr 2024, 00:40
8Harshitsharma wrote:
A did 2/3 of the work, so remaining work of A = (1-2/3). The remaining work of A is done by B but only 1/5 of (1-2/3) is completed so the remaining work of B = (1-1/5)(1-2/3) and the remaining work of B is to be done by C but she does 1/4*(1-2/3)(1-1/5) and the remaining work of C is then (1-1/4)(1-1/5)(1-2/3). Since we don’t have anyone after C, so the remaining work is (1-1/4)(1-1/5)(1-2/3)
This recent confusion of mine is related to this explanation.
