Last visit was: 23 Apr 2024, 20:45 It is currently 23 Apr 2024, 20:45

GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

# Quant Question of the Day Chat

SORT BY:
Tags:
Show Tags
Hide Tags
CR Forum Moderator
Joined: 25 Jan 2022
Posts: 832
Own Kudos [?]: 643 [0]
Given Kudos: 558
Location: Italy
GPA: 3.8
Quant Chat Moderator
Joined: 22 Dec 2016
Posts: 3083
Own Kudos [?]: 4080 [0]
Given Kudos: 1851
Location: India
CR Forum Moderator
Joined: 25 Jan 2022
Posts: 832
Own Kudos [?]: 643 [0]
Given Kudos: 558
Location: Italy
GPA: 3.8
Quant Chat Moderator
Joined: 22 Dec 2016
Posts: 3083
Own Kudos [?]: 4080 [0]
Given Kudos: 1851
Location: India
Re: Quant Question of the Day Chat [#permalink]
nikhil553 wrote:
let d=60km speed of the car=V km/hr t= d/v when car travelled in V+20 velcoity it reach 60Km destination in 30 min less than V travelled so (60/V)-(60/V+20) = 30 min or 0.5 hour (60/40)-(60/60) = 05 hour or 30 min hence the answer B i hope this will help you

Great Explanation ! Kudos to you !
Intern
Joined: 20 Dec 2022
Posts: 7
Own Kudos [?]: 0 [0]
Given Kudos: 6
Re: Quant Question of the Day Chat [#permalink]
Hi Everyone, new to this group

Quant Chat Moderator
Joined: 22 Dec 2016
Posts: 3083
Own Kudos [?]: 4080 [0]
Given Kudos: 1851
Location: India
Re: Quant Question of the Day Chat [#permalink]
gmatophobia wrote:
PS Question 1 - Dec 21 If a car had traveled 20 kmh faster than it actually did, the trip would have lasted 30 minutes less. If the car went exactly 60 km, at what speed did it travel? A. 35 kmh B. 40 kmh C. 50 kmh D. 60 kmh E. 65 kmh Source: GMAT Club Tests | Difficulty: Medium

B

gmatophobia wrote:
DS Question 1 - Dec 21 If p and q are integers, then what is the units digit of 155^(9q) + 138^p + 146^q (1) The remainder is 2, when the positive integer p is divided by 8 (2) q is a prime number less than 10 Source: GMAT Whiz | Difficulty : Hard

C

PS Question 1 - Dec 22

a and b are integers such that a/b=3.45. If R is the remainder of a/b, which of the following could NOT be equal to R?

A. 3
B. 9
C. 36
D. 81
E. 144

Source: Manhattan GMAT | Difficulty: Medium

DS Question 1 - Dec 22

If x>0, is √x a positive integer?

(1) x^2 is a positive integer

(2) x=m∗b where m=b

Source: EmpowerGMAT | Difficulty: Hard

Originally posted by gmatophobia on 22 Dec 2022, 01:52.
Last edited by gmatophobia on 22 Dec 2022, 01:56, edited 2 times in total.
CR Forum Moderator
Joined: 25 Jan 2022
Posts: 832
Own Kudos [?]: 643 [0]
Given Kudos: 558
Location: Italy
GPA: 3.8
Re: Quant Question of the Day Chat [#permalink]
gmatophobia wrote:
DS Question 1 - Dec 22 If x>0, is √x a positive integer? (1) x^2 is a positive integer (2) x=m∗b where m=b Source: EmpowerGMAT | Difficulty: Hard

1) Careful of the trap! If x=3, then root(x) is not int. If x=4, then it is int. Insuff.

2) x=b^2 x is positive integer, so b^2 must be positive int. Therefore root(x)=root(b^2)=b

B.

mysterymanrog wrote:
1) Careful of the trap! If x=3, then root(x) is not int. If x=4, then it is int. Insuff. 2) x=b^2 x is positive integer, so b^2 must be positive int. Therefore root(x)=root(b^2)=b B.

Should be a tad more precise: m and b can both be negative, but they are always integers. So its abs(b) rather than just B.

ex: m=b=-4 x=16 root(x)=4=abs(b)

And I fell for the trap, lol its C

Originally posted by mysterymanrog on 22 Dec 2022, 02:51.
Last edited by mysterymanrog on 22 Dec 2022, 02:56, edited 2 times in total.
Intern
Joined: 26 Nov 2022
Posts: 22
Own Kudos [?]: 16 [0]
Given Kudos: 6
Re: Quant Question of the Day Chat [#permalink]
mysterymanrog wrote:
Should be a tad more precise: m and b can both be negative, but they are always integers. So its abs(b) rather than just B. ex: m=b=-4 x=16 root(x)=4=abs(b)

2) x=b^2, where we just know that x>0, so we have no information of b, m are integers.. Then it is Insufficient...

If we combine both 1 & 2 then we can say b, m are positive integers, therefore b^2 positive int. hence root(x) is a positive integer

So, C...
CR Forum Moderator
Joined: 25 Jan 2022
Posts: 832
Own Kudos [?]: 643 [0]
Given Kudos: 558
Location: Italy
GPA: 3.8
Re: Quant Question of the Day Chat [#permalink]
aps326 wrote:
2) x=b^2, where we just know that x>0, so we have no information of b, m are integers.. Then it is Insufficient... If we combine both 1 & 2 then we can say b, m are positive integers, therefore b^2 positive int. hence root(x) is a positive integer So, C...

Yep!!! I accidentally saw x>0 and thought x=int
Intern
Joined: 26 Nov 2022
Posts: 22
Own Kudos [?]: 16 [0]
Given Kudos: 6
Re: Quant Question of the Day Chat [#permalink]
mysterymanrog wrote:
Yep!!! I accidentally saw x>0 and thought x=int

Nice question though...
CR Forum Moderator
Joined: 25 Jan 2022
Posts: 832
Own Kudos [?]: 643 [0]
Given Kudos: 558
Location: Italy
GPA: 3.8
Re: Quant Question of the Day Chat [#permalink]
aps326 wrote:
Nice question though...

Yep! Teaches you to be very careful
Intern
Joined: 23 Nov 2022
Posts: 10
Own Kudos [?]: 1 [0]
Given Kudos: 26
Re: Quant Question of the Day Chat [#permalink]
nikhil553 wrote:
let d=60km speed of the car=V km/hr t= d/v when car travelled in V+20 velcoity it reach 60Km destination in 30 min less than V travelled so (60/V)-(60/V+20) = 30 min or 0.5 hour (60/40)-(60/60) = 05 hour or 30 min hence the answer B i hope this will help you

This really helped i was initially trying to do this by gap method
Quant Chat Moderator
Joined: 22 Dec 2016
Posts: 3083
Own Kudos [?]: 4080 [0]
Given Kudos: 1851
Location: India
Re: Quant Question of the Day Chat [#permalink]
DS Question 2 - Dec 22

If x is a positive integer greater than 1, is x a prime number?

(1) x does not have a factor p such that 2
(2) The product of any two factors of x is greater than 2 but less than 10.

Source: GMAT Club Tests | Difficulty: Hard Easy if one is careful
CR Forum Moderator
Joined: 25 Jan 2022
Posts: 832
Own Kudos [?]: 643 [0]
Given Kudos: 558
Location: Italy
GPA: 3.8
Re: Quant Question of the Day Chat [#permalink]
gmatophobia wrote:
DS Question 2 - Dec 22 If x is a positive integer greater than 1, is x a prime number? (1) x does not have a factor p such that 2GMAT Club Tests | Difficulty: Hard Easy if one is careful

Hopefully I didn’t bait myself:

1) x does not have a factor p such that 2Almost sufficient. However
X=4 has factors 4,2,1. There is no factor such that 2X=3 has factors 3,1. Same as before. NS.
2) The product of ANY two factors is 2If x=4, 4*4 is 16. Therefore, X cannot be 4. The same for any values larger than 3 - 5*5=25, etc.
If x=3, 3*3=9, 3*1=3 and 1*1 is 3. X can be 3.
If x=2, 2*1=2, x cannot be 2.
X must be 3, therefore X is prime.
Intern
Joined: 26 Nov 2022
Posts: 22
Own Kudos [?]: 16 [0]
Given Kudos: 6
Re: Quant Question of the Day Chat [#permalink]
[quote="mysterymanrog"]Hopefully I didn’t bait myself: 1) x does not have a factor p such that 210 and similarly for all odd integers more then 9.

So B is Sufficient.

Please lemme know if I have gone somewhere wrong.
Quant Chat Moderator
Joined: 22 Dec 2016
Posts: 3083
Own Kudos [?]: 4080 [0]
Given Kudos: 1851
Location: India
Re: Quant Question of the Day Chat [#permalink]
PS Question 2 - Dec 22

At a family summer party, each of the x members of the family chose whether or not to have a hamburger and whether or not to have a hotdog. If 1/3 chose to have a hamburger, and of those 1/7 chose to also have a hotdog, then how many family members chose NOT to have both.

A. x/21
B. x/10
C. 9x/10
D. 10x/21
E. 20x/21

Source: EmpowerGMAT | Difficulty: Medium
Intern
Joined: 26 Nov 2022
Posts: 22
Own Kudos [?]: 16 [0]
Given Kudos: 6
Re: Quant Question of the Day Chat [#permalink]
Out of x members of the family 1/3 chose to have hamburger that is x * 1/3 = x/3, now out of them 1/7 chose to also have hotdog so x/3 * 1/7 = x/21,
Now those who will have both are x/21 then those members who chose NOt to have both = x - x/21 = 20x/21.

Hence "E".
CR Forum Moderator
Joined: 25 Jan 2022
Posts: 832
Own Kudos [?]: 643 [0]
Given Kudos: 558
Location: Italy
GPA: 3.8
Re: Quant Question of the Day Chat [#permalink]
aps326 wrote:
Answer is B, But I have different approach for that... 2) The product of any two factors of x is greater than 2 but less than 10. By the statement we know X is a positive integers greater than 1. So here we can check x cannot be 2 as it’s factors are 1 & 2 so the product of the factors = 2 and x cannot be 4 as well as it’s factors are 1, 2 & 4 so the product of the factors 1 n 2 is 2. Similarly for all even integers, hence here we know x cannot be even... Now similarly if we do for odd positive integers it implies that x can be 3, 5, or 7. "Notice that x cannot be 9 because 3 and 9 both are factors of 9 and 3*9=27>10 and similarly for all odd integers more then 9. So B is Sufficient. Please lemme know if I have gone somewhere wrong.

I am not sure if X can be 5 or 7. Statement B states any two factors, not any two unique factors, so technically you need to check (x^2). Otherwise, I think your solution is good.

It depends how you interpert the question I guess

Originally posted by mysterymanrog on 22 Dec 2022, 11:22.
Last edited by mysterymanrog on 22 Dec 2022, 11:25, edited 1 time in total.
Quant Chat Moderator
Joined: 22 Dec 2016
Posts: 3083
Own Kudos [?]: 4080 [0]
Given Kudos: 1851
Location: India
Re: Quant Question of the Day Chat [#permalink]
gmatophobia wrote:
PS Question 1 - Dec 22 a and b are integers such that a/b=3.45. If R is the remainder of a/b, which of the following could NOT be equal to R? A. 3 B. 9 C. 36 D. 81 E. 144 Source: Manhattan GMAT | Difficulty: Medium

A

gmatophobia wrote:
DS Question 1 - Dec 22 If x>0, is √x a positive integer? (1) x^2 is a positive integer (2) x=m∗b where m=b Source: EmpowerGMAT | Difficulty: Hard

E

aps326 wrote:
2) x=b^2, where we just know that x>0, so we have no information of b, m are integers.. Then it is Insufficient... If we combine both 1 & 2 then we can say b, m are positive integers, therefore b^2 positive int. hence root(x) is a positive integer So, C...

What if m = some number ^ (1/4) ; its not given that m and b are integers.

Originally posted by gmatophobia on 23 Dec 2022, 00:37.
Last edited by gmatophobia on 23 Dec 2022, 00:43, edited 2 times in total.
Senior Manager
Joined: 17 Jun 2022
Posts: 251
Own Kudos [?]: 123 [0]
Given Kudos: 67
Re: Quant Question of the Day Chat [#permalink]
An airline passenger is planning a trip that involves three connecting flights that leave from Airports A, B, and C, respectively. The first flight leaves Airport A every hour, beginning at 8:00 a.m., and arrives at Airport B 3/2 hours later. The second flight leaves Airport B every 20 minutes, beginning at 8:00 a.m., and arrives at Airport C 7/6 hours later. The third flight leaves Airport C every hour, beginning at 8:45 a.m. What is the least total amount of time the passenger must spend between flights if all flights keep to their schedules?

(A) 25 min
(B) 1 hr 5 min
(C) 1 hr 15 min
(D) 2 hr 20 min
(E) 3 hr 40 mi
Re: Quant Question of the Day Chat [#permalink]
1  ...  30   31   32   33   34  ...  224
Moderator:
Math Expert
92883 posts