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Re: Quant Question of the Day Chat [#permalink]
nikhil553 wrote:
let d=60km speed of the car=V km/hr t= d/v when car travelled in V+20 velcoity it reach 60Km destination in 30 min less than V travelled so (60/V)-(60/V+20) = 30 min or 0.5 hour (60/40)-(60/60) = 05 hour or 30 min hence the answer B i hope this will help you

Great Explanation ! Kudos to you !
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Re: Quant Question of the Day Chat [#permalink]
Hi Everyone, new to this group

thank you everyone in advance
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Re: Quant Question of the Day Chat [#permalink]
gmatophobia wrote:
PS Question 1 - Dec 21 If a car had traveled 20 kmh faster than it actually did, the trip would have lasted 30 minutes less. If the car went exactly 60 km, at what speed did it travel? A. 35 kmh B. 40 kmh C. 50 kmh D. 60 kmh E. 65 kmh Source: GMAT Club Tests | Difficulty: Medium



gmatophobia wrote:
DS Question 1 - Dec 21 If p and q are integers, then what is the units digit of 155^(9q) + 138^p + 146^q (1) The remainder is 2, when the positive integer p is divided by 8 (2) q is a prime number less than 10 Source: GMAT Whiz | Difficulty : Hard



PS Question 1 - Dec 22

a and b are integers such that a/b=3.45. If R is the remainder of a/b, which of the following could NOT be equal to R?

A. 3
B. 9
C. 36
D. 81
E. 144

Source: Manhattan GMAT | Difficulty: Medium

DS Question 1 - Dec 22

If x>0, is √x a positive integer?

(1) x^2 is a positive integer

(2) x=m∗b where m=b

Source: EmpowerGMAT | Difficulty: Hard

Originally posted by gmatophobia on 22 Dec 2022, 01:52.
Last edited by gmatophobia on 22 Dec 2022, 01:56, edited 2 times in total.
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Re: Quant Question of the Day Chat [#permalink]
gmatophobia wrote:
DS Question 1 - Dec 22 If x>0, is √x a positive integer? (1) x^2 is a positive integer (2) x=m∗b where m=b Source: EmpowerGMAT | Difficulty: Hard

1) Careful of the trap! If x=3, then root(x) is not int. If x=4, then it is int. Insuff.

2) x=b^2 x is positive integer, so b^2 must be positive int. Therefore root(x)=root(b^2)=b

B.

mysterymanrog wrote:
1) Careful of the trap! If x=3, then root(x) is not int. If x=4, then it is int. Insuff. 2) x=b^2 x is positive integer, so b^2 must be positive int. Therefore root(x)=root(b^2)=b B.

Should be a tad more precise: m and b can both be negative, but they are always integers. So its abs(b) rather than just B.

ex: m=b=-4 x=16 root(x)=4=abs(b)

And I fell for the trap, lol its C

Originally posted by mysterymanrog on 22 Dec 2022, 02:51.
Last edited by mysterymanrog on 22 Dec 2022, 02:56, edited 2 times in total.
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Re: Quant Question of the Day Chat [#permalink]
mysterymanrog wrote:
Should be a tad more precise: m and b can both be negative, but they are always integers. So its abs(b) rather than just B. ex: m=b=-4 x=16 root(x)=4=abs(b)

2) x=b^2, where we just know that x>0, so we have no information of b, m are integers.. Then it is Insufficient...

If we combine both 1 & 2 then we can say b, m are positive integers, therefore b^2 positive int. hence root(x) is a positive integer

So, C...
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Re: Quant Question of the Day Chat [#permalink]
aps326 wrote:
2) x=b^2, where we just know that x>0, so we have no information of b, m are integers.. Then it is Insufficient... If we combine both 1 & 2 then we can say b, m are positive integers, therefore b^2 positive int. hence root(x) is a positive integer So, C...

Yep!!! I accidentally saw x>0 and thought x=int
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Re: Quant Question of the Day Chat [#permalink]
mysterymanrog wrote:
Yep!!! I accidentally saw x>0 and thought x=int

Nice question though...
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Re: Quant Question of the Day Chat [#permalink]
aps326 wrote:
Nice question though...

Yep! Teaches you to be very careful
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Re: Quant Question of the Day Chat [#permalink]
nikhil553 wrote:
let d=60km speed of the car=V km/hr t= d/v when car travelled in V+20 velcoity it reach 60Km destination in 30 min less than V travelled so (60/V)-(60/V+20) = 30 min or 0.5 hour (60/40)-(60/60) = 05 hour or 30 min hence the answer B i hope this will help you

This really helped i was initially trying to do this by gap method
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Re: Quant Question of the Day Chat [#permalink]
DS Question 2 - Dec 22

If x is a positive integer greater than 1, is x a prime number?

(1) x does not have a factor p such that 2
(2) The product of any two factors of x is greater than 2 but less than 10.

Source: GMAT Club Tests | Difficulty: Hard Easy if one is careful
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Re: Quant Question of the Day Chat [#permalink]
gmatophobia wrote:
DS Question 2 - Dec 22 If x is a positive integer greater than 1, is x a prime number? (1) x does not have a factor p such that 2GMAT Club Tests | Difficulty: Hard Easy if one is careful

Hopefully I didn’t bait myself:

1) x does not have a factor p such that 2Almost sufficient. However
X=4 has factors 4,2,1. There is no factor such that 2X=3 has factors 3,1. Same as before. NS.
2) The product of ANY two factors is 2If x=4, 4*4 is 16. Therefore, X cannot be 4. The same for any values larger than 3 - 5*5=25, etc.
If x=3, 3*3=9, 3*1=3 and 1*1 is 3. X can be 3.
If x=2, 2*1=2, x cannot be 2.
X must be 3, therefore X is prime.
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Re: Quant Question of the Day Chat [#permalink]
[quote="mysterymanrog"]Hopefully I didn’t bait myself: 1) x does not have a factor p such that 210 and similarly for all odd integers more then 9.

So B is Sufficient.

Please lemme know if I have gone somewhere wrong.
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Re: Quant Question of the Day Chat [#permalink]
PS Question 2 - Dec 22

At a family summer party, each of the x members of the family chose whether or not to have a hamburger and whether or not to have a hotdog. If 1/3 chose to have a hamburger, and of those 1/7 chose to also have a hotdog, then how many family members chose NOT to have both.

A. x/21
B. x/10
C. 9x/10
D. 10x/21
E. 20x/21

Source: EmpowerGMAT | Difficulty: Medium
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Re: Quant Question of the Day Chat [#permalink]
Out of x members of the family 1/3 chose to have hamburger that is x * 1/3 = x/3, now out of them 1/7 chose to also have hotdog so x/3 * 1/7 = x/21,
Now those who will have both are x/21 then those members who chose NOt to have both = x - x/21 = 20x/21.

Hence "E".
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Re: Quant Question of the Day Chat [#permalink]
aps326 wrote:
Answer is B, But I have different approach for that... 2) The product of any two factors of x is greater than 2 but less than 10. By the statement we know X is a positive integers greater than 1. So here we can check x cannot be 2 as it’s factors are 1 & 2 so the product of the factors = 2 and x cannot be 4 as well as it’s factors are 1, 2 & 4 so the product of the factors 1 n 2 is 2. Similarly for all even integers, hence here we know x cannot be even... Now similarly if we do for odd positive integers it implies that x can be 3, 5, or 7. "Notice that x cannot be 9 because 3 and 9 both are factors of 9 and 3*9=27>10 and similarly for all odd integers more then 9. So B is Sufficient. Please lemme know if I have gone somewhere wrong.

I am not sure if X can be 5 or 7. Statement B states any two factors, not any two unique factors, so technically you need to check (x^2). Otherwise, I think your solution is good.

It depends how you interpert the question I guess

Originally posted by mysterymanrog on 22 Dec 2022, 11:22.
Last edited by mysterymanrog on 22 Dec 2022, 11:25, edited 1 time in total.
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Re: Quant Question of the Day Chat [#permalink]
gmatophobia wrote:
PS Question 1 - Dec 22 a and b are integers such that a/b=3.45. If R is the remainder of a/b, which of the following could NOT be equal to R? A. 3 B. 9 C. 36 D. 81 E. 144 Source: Manhattan GMAT | Difficulty: Medium



gmatophobia wrote:
DS Question 1 - Dec 22 If x>0, is √x a positive integer? (1) x^2 is a positive integer (2) x=m∗b where m=b Source: EmpowerGMAT | Difficulty: Hard



aps326 wrote:
2) x=b^2, where we just know that x>0, so we have no information of b, m are integers.. Then it is Insufficient... If we combine both 1 & 2 then we can say b, m are positive integers, therefore b^2 positive int. hence root(x) is a positive integer So, C...

What if m = some number ^ (1/4) ; its not given that m and b are integers.

Originally posted by gmatophobia on 23 Dec 2022, 00:37.
Last edited by gmatophobia on 23 Dec 2022, 00:43, edited 2 times in total.
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Re: Quant Question of the Day Chat [#permalink]
An airline passenger is planning a trip that involves three connecting flights that leave from Airports A, B, and C, respectively. The first flight leaves Airport A every hour, beginning at 8:00 a.m., and arrives at Airport B 3/2 hours later. The second flight leaves Airport B every 20 minutes, beginning at 8:00 a.m., and arrives at Airport C 7/6 hours later. The third flight leaves Airport C every hour, beginning at 8:45 a.m. What is the least total amount of time the passenger must spend between flights if all flights keep to their schedules?

(A) 25 min
(B) 1 hr 5 min
(C) 1 hr 15 min
(D) 2 hr 20 min
(E) 3 hr 40 mi
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