ramyasree0299
Hi, Thanks for the explanation, But the first statement specifies that there are 4800 cans FILLED. Not that 4800 cans have been installed with lids. Although it is tempting, I’m little hesitant to assume that in parallel 2 machines of C has installed. Case. 1, I assumed 4800 cans were filled by 400x A machines and 600y B machines. We can’t determine values of x and y. So insufficient Case 2, Since we have no information of the number of C machines ratio is highly insufficient for determining any number. Combined, I have derived 4800 = 400x + 600y, Now Let’s just assume your approach then according to case 2 4800 = 2*600*y, y=4 but what about x? It was never mentioned that A machine was not working at all. So how can we assume x=0 for the above? I think the option could be E. Let me know if i missed any point
Note that the question says "a lid is installed on every can that is filled". Therefore, if 4800 cans are filled each minute, then 4800 lids must also be installed
If that statement was missing from the stem, then you would be correct.
Furthermore, the question also states that no lids are installed on empty cans - otherwise this would also make the answer E.
mysterymanrog
1) There must be 2 C machines. However, we cannot determine the exact amount - there could be 4 B machines, or 6A machines, or some combination. Therefore INS. 2) Gives us a ratio, but no further info. INS. 3) From 1 we know that there are 2 C machines. That means we need 4 B machines. 4 B machines gives us exactly 4800 cans/min, therefore there must be 2 C machines and 4 B machines.
small mistake, there should be 6 A machines but I forgot to calculate them. So total is 6A,4B and 2C