Quant Question of the Day Chat

Can you please expulsin ?

St.1 is quite straight forward and its not sufficient.

St.2
y and (z -1 ) are positive number as both lie to the right of |x+1| (modulus is always non negative).

Also, as y < z - 1, we can conclude that z lies right on the number line compared to y.

So, the relative position of y and z on the number line is

----- y ----- z ------

|x + 1| is less than y.

Therefore we can infer that the distance between x and -1 is less than the value of y.

Regardless of which side of -1 ’x’ lies, the value of ’x’ will always be less than the value of y.

We can visualize this by plotting x , y and -1 on the number line.

----- -1 ----- x ----- y ------

----- x ----- -1 ----- y ------

Hence we can conclude that x < y < z

Option B

DS Question 1 - Dec 25

If x and y are positive integers, what is the greatest common divisor of x and y?

(1) 2x + y = 73
(2) 5x – 3y = 1

Source: Manhattan GMAT | Difficulty: Hard

PS Question 1 - Dec 25

At a local beach, the ratio of little dogs to average dogs to enormous dogs is 2:5:8. Late in the afternoon, the ratio of little dogs to average dogs doubles and the ratio of little dogs to enormous dogs increases. If the new percentage of little dogs and the new percentage of average dogs are both integers and there are fewer than 30 total dogs at the beach, which of the following represents a possible new percentage of enormous dogs?

A. 25%
B. 40%
C. 50%
D. 55%
E. 70%

Source: Veritas Prep | Difficulty: Hard

Can someone explain me how to solve this problem 😥

There js probably a discussion but you would do the following

(x+y)^2-(x-y)^2

expand it to
x^2+2xy+y^2-(x^2-2xy+y^2)
Simplify into 4xY
So really its 2^4xy
xy=1, so 2^4 which is just 16

PS Question 1 - Dec 26

Find the number of trailing zeros in (23!+24!+26!).

A. 2
B. 4
C. 5
D. 8
E. 10

Source: Others | Difficulty: Hard

DS Question 1 - Dec 26

If a, b, and c are integers and a < b < c, are a, b, and c consecutive integers?

(1) The median of {a!, b!, c!} is an odd number.

(2) c! is a prime number.

Source: GMAT Club Tests | Difficulty: Hard

Only factorial who has odd value is 0! or 1! b=0 or 1, but this is clearly not sufficient.

2) c! is prime - only 2! is prime.

3) There are no negative factorials, so b cannot =0. Therefore, a=0 b=1 c=3

Suff

Answer would be B or C?

b cannot be sufficient

we only know the value of c - 2

but we know nothing else

Ohh! My bad, I read a b c are Positive Integers...

For the case a, b, c are Integers answer will be C..

Thanks..!!

are gmat test centres noiseless? if not can i use ear plugs?

Yes, they are generally noiseless but also depends on area to area. But, in case they are not, then you are not even allowed to take your water bottle or any kind of paper or pen to your allotted system let alone earplugs.

Not sure if it’s the case at every the center or not but I have heard that the Noida center is quite good and they also have headphones for blocking the noise at the test station and also provide you the option for earplugs

I’m sure you can contact the center you schedule at and ask them about similar provisions

I believe it depends on the type of center too

Pearson centers have earplugs built in

like they give you dome

PS Question 2 - Dec 26

A set of numbers has the property that for any number t in the set, t + 2 is in the set. If -1 is in the set, which of the following must also be in the set?

I. -3
II. 1
III. 5

(A) I only
(B) II only
(C) I and II only
(D) II and III only
(E) I, II , and III

Source: Official Guide | Difficulty: Medium

thanks for the information