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Updated on: 16 Aug 2018, 00:56
Originally posted by EgmatQuantExpert on 20 Jul 2018, 05:03.
Last edited by EgmatQuantExpert on 16 Aug 2018, 00:56, edited 6 times in total.
Last edited by EgmatQuantExpert on 16 Aug 2018, 00:56, edited 6 times in total.
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
66% (02:40) correct
34%
(02:40)
wrong
based on 229
sessions
History
Date
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Not Attempted Yet
e-GMAT Question of the Week #8
In the quadrilateral shown above, the length of AB and CD is 6 units and 8 units respectively. If the length of AC is 10 units, then which of the following can be the perimeter of quadrilateral ABCD?
To access all the questions: Question of the Week: Consolidated List
In the quadrilateral shown above, the length of AB and CD is 6 units and 8 units respectively. If the length of AC is 10 units, then which of the following can be the perimeter of quadrilateral ABCD?
- a) 20 units
b) 35 units
c) 48 units
d) 52 units
e) 60 units
To access all the questions: Question of the Week: Consolidated List
Updated on: 13 Aug 2018, 00:42
Originally posted by EgmatQuantExpert on 20 Jul 2018, 05:08.
Last edited by EgmatQuantExpert on 13 Aug 2018, 00:42, edited 2 times in total.
Last edited by EgmatQuantExpert on 13 Aug 2018, 00:42, edited 2 times in total.
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Solution
Given:
- • AB= 6 units
• CD= 8 units
• AC= 10 units
To find:
- • The option which can be the correct diameter of quadrilateral ABCD.
Approach and Working:
Perimeter of ABCD= AB+BC+CD+DA= 8+6+AD+BC= 14+AD+BC
- • Hence, we will get the minimum value of perimeter when AD and BC are minimum
• And, we will get the maximum value of perimeter when AD and BC are maximum.
In ∆ ADC,
- • 10-8 < AD < 10+8
• 2 < AD < 18
In ∆ ABC,
- • 10-6 < BC < 10+6
• 4 < BC < 16
Hence, 6 < AD+BC < 34
Thus, 20<Perimeter of ABCD< 48
The only option which lies between 20 and 48 is 35.
Hence, the correct answer is option B.
Answer: B
General Discussion
20 Jul 2018, 05:33
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EgmatQuantExpert
In triangle ADC ,3<AD<17
In triangle ABC ,5<BC<15
Therefore Max perimeter 8+6+17+15=46
Min perimeter 6+8+3+5=22
22<P<46
So B
