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Re: Raymond purchased a package of ground beef at a cost of $1.9 [#permalink]
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1.98x=0.6xy

y=1.98x/0.6x=3.3

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Raymond purchased a package of ground beef at a cost of $1.9 [#permalink]
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ajit257 wrote:
Raymond purchased a package of ground beef at a cost of $1.98 per pound. If, for the same amount of money, Raymond could have purchased a piece of steak that weighed 40 percent less than the package of ground beef, what was the cost per pound of the steak?

A. $4.95
B. $4.20
C. $3.60
D. $3.30
E. $3.10[/quote

Fedemaravilla wrote:
I think this answer I bad written. It talks about a package of beef not specifing that how many pounds does it weight. Then it says again 40% less than the package, how can we assume that the package weights 1 pound??

Fedemaravilla , it might seem confusing, but you should not assume the first package weighs one pound. See Bunuel , above

You are dealing with a rate (\(\frac{cost}{pound}\)), not a quantity.

The prompt gives us "cost per [one] pound" for convenience.
But "cost per [one] pound" does not mean there is only one pound.

Suppose the first package weighed two pounds.
The prompt would have told us it cost $3.96.
The rest of the question would be the same.

What was the cost per pound of the steak?

\(\frac{TotalCost}{NumberOfLbs}\) = Cost per pound

The number of pounds changed to a fraction of the original number of pounds
40 percent less than 2 pounds = (.60)(2) = 1.2 pounds
The equation for the original rate also must change:
From \(\frac{$3.96}{2 lb}\) to \(\frac{$3.96}{1.2lbs} = $3.30\) per pound for steak

Similarly, here: \(\frac{$1.98}{1lb} = $1.98\) per pound for ground beef.
The number of pounds changed from 1 to 0.6 pounds
That changes the original rate
The equation also must change to \(\frac{$1.98}{.60} = $3.30\) per pound of steak

In short, when you see "cost per pound," you are dealing with a rate, not a quantity.
Focus on the rate, and in this case, how the rate gets changed.

Hope that helps.
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Re: Raymond purchased a package of ground beef at a cost of $1.9 [#permalink]
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1.98/x = 0.6/1
0.6x = 1.98
x = 3.3
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Re: Raymond purchased a package [#permalink]
Always for this kind of a problem(s), the best method is to go by the cross multiplications ,

If A = B , And C is what ???

A= B , then take C= X, then X = B*C/A

SO, 1 Pound of beef = $ 1.98

Then 60% of 1 Pound of Steak (A) = $1.98 (B)

Then 100 % of 1 Pound of steak (C) = X

So , X = $1.98 *1 Pond of steak / .6Pound of steak


We get $3.30 Ans D.

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Re: Raymond purchased a package of ground beef at a cost of $1.9 [#permalink]
a EP2 question CAT6 lol
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Re: Raymond purchased a package of ground beef at a cost of $1.9 [#permalink]
I think this answer I bad written. It talks about a package of beef not specifing that how many pounds does it weight. Then it says again 40% less than the package, how can we assume that the package weights 1 pound??
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Re: Raymond purchased a package of ground beef at a cost of $1.9 [#permalink]
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Re: Raymond purchased a package of ground beef at a cost of $1.9 [#permalink]
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