ajit257 wrote:

Raymond purchased a package of ground beef at a cost of $1.98 per pound. If, for the same amount of money, Raymond could have purchased a piece of steak that weighed 40 percent less than the package of ground beef, what was the cost per pound of the steak?

A. $4.95

B. $4.20

C. $3.60

D. $3.30

E. $3.10[/quote

Fedemaravilla wrote:

I think this answer I bad written. It talks about a package of beef not specifing that how many pounds does it weight. Then it says again 40% less than the package, how can we assume that the package weights 1 pound??

Fedemaravilla , it might seem confusing, but you should not assume the first package weighs one pound. See

Bunuel ,

aboveYou are dealing with a rate (

\(\frac{cost}{pound}\)), not a quantity.

The prompt gives us "cost per [one] pound" for convenience.

But "cost per [one] pound" does not mean there is

only one pound.

Suppose the first package weighed two pounds.

The prompt would have told us it cost $3.96.

The rest of the question would be the same.

What was the cost per pound of the steak?

\(\frac{TotalCost}{NumberOfLbs}\) =

Cost per poundThe number of pounds changed to a fraction of the original number of pounds

40 percent less than 2 pounds = (.60)(2) = 1.2 pounds

The equation for the original

rate also must change:

From

\(\frac{$3.96}{2 lb}\) to

\(\frac{$3.96}{1.2lbs} = $3.30\) per pound for steak

Similarly, here:

\(\frac{$1.98}{1lb} = $1.98\) per pound for ground beef.

The number of pounds changed from 1 to 0.6 pounds

That changes the original rate

The equation also must change to

\(\frac{$1.98}{.60} = $3.30\) per pound of steak

In short, when you see "cost per pound," you are dealing with a rate, not a quantity.

Focus on the rate, and in this case, how the rate gets changed.

Hope that helps.

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