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Rhoda tosses a coin 5 times. Find the probability of getting exactly 4

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ruchi857
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Rhoda tosses a coin 5 times. Find the probability of getting exactly 4 [#permalink] New post   Updated on: 24 Aug 2017, 23:58
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Rhoda tosses a coin 5 times. Find the probability of getting exactly 4 heads.

A. 1/32
B. 1/16
C. 3/32
D. 1/8
E. 5/32


Show Spoiler
Answer: 5/32


I fail to understand why have we multiplied by (5).
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E

Originally posted by ruchi857 on 17 May 2016, 04:21.
Last edited by Bunuel on 24 Aug 2017, 23:58, edited 2 times in total.
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Re: Rhoda tosses a coin 5 times. Find the probability of getting exactly 4 [#permalink] New post   17 May 2016, 04:30
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ruchi857 wrote:
Rhoda tosses a coin 5 times. Find the probability of getting exactly 4 heads.

Show Spoiler
Answer: 5/32


I fail to understand why have we multiplied by (5).


You can have the following 5 cases:
THHHH
HTHHH
HHTHH
HHHTH
HHHHT

Each of the 5 cases has the probability of (1/2)^5, thus the overall probability is 5*(1/2)^5.
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Re: Rhoda tosses a coin 5 times. Find the probability of getting exactly 4 [#permalink] New post   21 May 2016, 10:54
Would be glad if I get a more elaborate explanation to this problem.
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Re: Rhoda tosses a coin 5 times. Find the probability of getting exactly 4 [#permalink] New post   10 Jul 2016, 05:59
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Please note that the coin problems are very similar to alphabet problems and can be solved in the same way.

Exactly 4 heads out of 5 would be: HHHHT, HHTHH, or many other combinations.

therefore, no. of possible combinations are 5!/4!*1! = 5

Probability = 5/2^5 = 5/32
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Re: Rhoda tosses a coin 5 times. Find the probability of getting exactly 4 [#permalink] New post   08 Dec 2016, 00:39
To get 4 heads from 5 tosses there must be 4H and 1T. The probability of getting 4H and then 1T is 1/(2^5).
However, there are 5 ways to arrange 4H and 1T in 5 tosses. This is found using combinations nCr: 5!/(4!)(1!).
Multiplying the probability by the number of arrangements = 5/32.
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Re: Rhoda tosses a coin 5 times. Find the probability of getting exactly 4 [#permalink] New post   14 Jul 2018, 19:27
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ruchi857 wrote:
Rhoda tosses a coin 5 times. Find the probability of getting exactly 4 heads.

A. 1/32
B. 1/16
C. 3/32
D. 1/8
E. 5/32


The probability of H-H-H-H-T in this order is (½)^4 (½) = 1/32. However, the 4 heads and 1 tail can be arranged in 5!/4! = 5 ways. Therefore, the probability of getting 4 heads and 1 tail is 5 x 1/32 = 5/32.

Answer: E
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Re: Rhoda tosses a coin 5 times. Find the probability of getting exactly 4 [#permalink] New post   04 Oct 2022, 22:25
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Given that Rhoda tosses a coin 5 times and we need to find Find the probability of getting exactly 4 heads.

Coin is tossed 5 times => Total number of cases = \(2^5\) = 32

Cases in which we get 4H is same as getting 1T. Cases for 1T can be found by putting 1 tail in any of the 5 slots _ _ _ _ _ => THHHH, HTHHH, HHTHH, HHHTH, HHHHT => 5 ways

=> P(4H) = \(\frac{5}{32}\)

So, Answer will be E
Hope it helps!

Watch the following video to learn How to Solve Probability with Coin Toss Problems

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Re: Rhoda tosses a coin 5 times. Find the probability of getting exactly 4 [#permalink]
04 Oct 2022, 22:25
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