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AshikaP
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Steve gets on the elevator at the 11th floor of a building a Updated on: 23 Mar 2014, 06:02
Originally posted by AshikaP on 01 Apr 2006, 22:43.
Last edited by Bunuel on 23 Mar 2014, 06:02, edited 1 time in total.
Renamed the topic, edited the question, added the OA and moved to PS forum.
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70% (02:18) correct 30% (02:34) wrong based on 1225 sessions

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Steve gets on the elevator at the 11th floor of a building and rides up at a rate of 57 floors per minute. At the same time Joyce gets on an elevator on the 51st floor of the same building and rides down at a rate of 63 floors per minute. If they continue traveling at these rates, at which floor will their paths cross?

A. 19
B. 28
C. 30
D. 32
E. 44
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C
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Steve gets on the elevator at the 11th floor of a building a Updated on: 13 Aug 2023, 23:54
Originally posted by KarishmaB on 09 Sep 2016, 00:05.
Last edited by KarishmaB on 13 Aug 2023, 23:54, edited 1 time in total.
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AshikaP
Steve gets on the elevator at the 11th floor of a building and rides up at a rate of 57 floors per minute. At the same time Joyce gets on an elevator on the 51st floor of the same building and rides down at a rate of 63 floors per minute. If they continue traveling at these rates, at which floor will their paths cross?

A. 19
B. 28
C. 30
D. 32
E. 44
Show more

Even though this question uses elevators (which usually means a tougher question), it involves very simple relative speed calculation.

Steve is on 11th floor and Joyce on 51st floor so they have a distance of 40 floors between them.
Steve's speed is 57 floors/min and Joyce's speed is 63 floors/min in opposite direction (towards Steve).
Their relative speed will be the sum of their individual speeds = 57 + 63 = 120 floors/min

Time taken to meet = 40/120 = 1/3 min = 20 secs

Distance covered by Steve in 20 secs = Speed*Time = 57 * (1/3) = 19 floors.
So he is at 11+19 = 30th floor when they meet.

Answer (C)

Check this video for when to use relative speed: https://youtu.be/wrYxeZ2WsEM
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Steve gets on the elevator at the 11th floor of a building a 02 Apr 2006, 01:12
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Yeah C

Usuing Speed Formula: Speed = Distance / Time

Distance to be covered = 51-11 = 40

Speed of approach = 57 + 63 floors/min

Time = 40/120 = 1/3

So Steve will cover 57x 1/3 floors in that time = 19

So he will be in 19 + 11 floor = 30th Floor
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Steve gets on the elevator at the 11th floor of a building a 02 Apr 2006, 00:54
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Answer C...

Steve travels at a rate of 57 floors/60s~1floor/1s

Joyce travels at a rate of 63 floors/60s~1floor/1s

Between them there are approximatelly 40 floors, so they will both have to travel ~ 20 floors to cross each other.... 20 floors is ~ 20 s

We need to use this formula.... Rate*Time=Distance

Steve: 57/60*20=19

Joyce: 63/60*20=21....

Adding things up we get 30......
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Steve gets on the elevator at the 11th floor of a building a 02 Apr 2006, 19:32
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yeap its 30 i kinda figured it out ina different way little later because it was bothering me...

but its pretty much the same :)
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Steve gets on the elevator at the 11th floor of a building a 23 Mar 2014, 20:58
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Distance between Steve & Joyce = 40 floors

Lets say they meet on x floor

Time required for Joyce to reach x floor = Time required for Steve

So the equation would be

\(\frac{x}{57} = \frac{40-x}{63}\)

x = 19

Start is at 11th floor, so 11 + 19 = 30 = Answer = C
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Steve gets on the elevator at the 11th floor of a building a 08 Sep 2016, 23:18
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Steve gets on the elevator at the 11th floor of a building and rides up at a rate of 57 floors per minute. At the same time Joyce gets on an elevator on the 51st floor of the same building and rides down at a rate of 63 floors per minute. If they continue traveling at these rates, at which floor will their paths cross?

40 floors/120 floors per minute=1/3 minutes
11+57/3=30
51-63/3=30
C. 30
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Steve gets on the elevator at the 11th floor of a building a 02 Feb 2023, 16:05
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Here is an equation to solve the problem.


Let time it will take for that to happen be x.

Riding up will be.


11 + 57x


Riding down.

51 - 63x


Therefore

11 + 57x = 51 - 63x

57x + 63x = 51 - 11

120x = 40

x = 1/3.

Sub for x in any of the Expressions gives 30.

Posted from my mobile device
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Steve gets on the elevator at the 11th floor of a building a 04 Aug 2023, 13:35
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KarishmaB
AshikaP
Steve gets on the elevator at the 11th floor of a building and rides up at a rate of 57 floors per minute. At the same time Joyce gets on an elevator on the 51st floor of the same building and rides down at a rate of 63 floors per minute. If they continue traveling at these rates, at which floor will their paths cross?

A. 19
B. 28
C. 30
D. 32
E. 44

Even though this question uses elevators (which usually means a tougher question), it involves very simple relative speed calculation.

Steve is on 11th floor and Joyce on 51st floor so they have a distance of 40 floors between them.
Steve's speed is 57 floors/min and Joyce's speed is 63 floors/min in opposite direction (towards Steve).
Their relative speed will be the sum of their individual speeds = 57 + 63 = 120 floors/min

Time taken to meet = 40/120 = 1/3 min = 20 secs

Distance covered by Steve in 20 secs = Speed*Time = 57 * (1/3) = 19 floors.
So he is at 11+19 = 30th floor when they meet.

Answer (C)

Check this post on relative speed:
https://www.gmatclub.com/forum/veritas- ... elatively/
https://www.gmatclub.com/forum/veritas- ... -concepts/
Show more

Dear KarishmaB

Why the distance between them is 40 floors? Shouldn't the 11th and the 51st floor be included in that count and in that case the number of floors would be (51-11)+1= 41 floors, or maybe they should be excluded and in that case the number of floors between them would be (51-11)-1= 39?

Thank you in advance for your feedback :)
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Steve gets on the elevator at the 11th floor of a building a 05 Aug 2023, 06:43
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GianKR
KarishmaB
AshikaP
Steve gets on the elevator at the 11th floor of a building and rides up at a rate of 57 floors per minute. At the same time Joyce gets on an elevator on the 51st floor of the same building and rides down at a rate of 63 floors per minute. If they continue traveling at these rates, at which floor will their paths cross?

A. 19
B. 28
C. 30
D. 32
E. 44

Even though this question uses elevators (which usually means a tougher question), it involves very simple relative speed calculation.

Steve is on 11th floor and Joyce on 51st floor so they have a distance of 40 floors between them.
Steve's speed is 57 floors/min and Joyce's speed is 63 floors/min in opposite direction (towards Steve).
Their relative speed will be the sum of their individual speeds = 57 + 63 = 120 floors/min

Time taken to meet = 40/120 = 1/3 min = 20 secs

Distance covered by Steve in 20 secs = Speed*Time = 57 * (1/3) = 19 floors.
So he is at 11+19 = 30th floor when they meet.

Answer (C)

Check this post on relative speed:
https://www.gmatclub.com/forum/veritas- ... elatively/
https://www.gmatclub.com/forum/veritas- ... -concepts/

Dear KarishmaB

Why the distance between them is 40 floors? Shouldn't the 11th and the 51st floor be included in that count and in that case the number of floors would be (51-11)+1= 41 floors, or maybe they should be excluded and in that case the number of floors between them would be (51-11)-1= 39?

Thank you in advance for your feedback :)
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Take a simpler example. Say you are on the 3rd floor of a building and have to go to the 5th floor. How many floors do you have to climb?
From 3rd to 4th and then from 4th to 5th i.e. 2 floors.
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Steve gets on the elevator at the 11th floor of a building a 07 Aug 2023, 00:11
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Steve gets on the elevator at the 11th floor of a building and rides up at a rate of 57 floors per minute. At the same time Joyce gets on an elevator on the 51st floor of the same building and rides down at a rate of 63 floors per minute. If they continue traveling at these rates, at which floor will their paths cross?

This can be solved by the relative velocity concept
The difference in the floors = 51-11=40
Relative velocity=57+63=120 floors per minute

Time taken to cross each other = Difference of floors/relative velocity = 40/120 = 1/3 minute

Therefore the floor they will cross their path can be given by
=> 11+57*(1/3) = 11+19=30

Hence C
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Steve gets on the elevator at the 11th floor of a building a 09 Aug 2024, 11:51
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can this be solved by ratio method?
63:57
21:19?
40 floor difference gets divided in ratio 21:19?
i am not getting the answer after this step
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Steve gets on the elevator at the 11th floor of a building a 19 Oct 2024, 19:38
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drambo24
can this be solved by ratio method?
63:57
21:19?
40 floor difference gets divided in ratio 21:19?
i am not getting the answer after this step
Show more

Since 40 floor is divide in the ratio 19: 21.
We can say that the distance travelled by steve will be 19/40*40 = 19 floors
Steve starts from 11th floor and travel another 19 floors, 11+19= 30. Hence, 30th floor.
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Steve gets on the elevator at the 11th floor of a building a 18 Jun 2025, 06:32
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KarishmaB
AshikaP
Steve gets on the elevator at the 11th floor of a building and rides up at a rate of 57 floors per minute. At the same time Joyce gets on an elevator on the 51st floor of the same building and rides down at a rate of 63 floors per minute. If they continue traveling at these rates, at which floor will their paths cross?

A. 19
B. 28
C. 30
D. 32
E. 44

Even though this question uses elevators (which usually means a tougher question), it involves very simple relative speed calculation.

Steve is on 11th floor and Joyce on 51st floor so they have a distance of 40 floors between them.
Steve's speed is 57 floors/min and Joyce's speed is 63 floors/min in opposite direction (towards Steve).
Their relative speed will be the sum of their individual speeds = 57 + 63 = 120 floors/min

Time taken to meet = 40/120 = 1/3 min = 20 secs

Distance covered by Steve in 20 secs = Speed*Time = 57 * (1/3) = 19 floors.
So he is at 11+19 = 30th floor when they meet.

Answer (C)

Check this video for when to use relative speed: https://youtu.be/wrYxeZ2WsEM
Show more

Hi [b]KarishmaB [/b] , Thank you for the explanation,
i am struggling to understand one thing, why is everyone assuming the meeting distance wrto steve, if we consider wrto steve then 11+19 = 30 is correct, but in the question there are two people Joyce coming down from 51st floor, so if we consider 19 with respect to joyce then the answer is 32 ? How to deduce this ?
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Steve gets on the elevator at the 11th floor of a building a 18 Jun 2025, 07:00
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IMpratik
KarishmaB
AshikaP
Steve gets on the elevator at the 11th floor of a building and rides up at a rate of 57 floors per minute. At the same time Joyce gets on an elevator on the 51st floor of the same building and rides down at a rate of 63 floors per minute. If they continue traveling at these rates, at which floor will their paths cross?

A. 19
B. 28
C. 30
D. 32
E. 44

Even though this question uses elevators (which usually means a tougher question), it involves very simple relative speed calculation.

Steve is on 11th floor and Joyce on 51st floor so they have a distance of 40 floors between them.
Steve's speed is 57 floors/min and Joyce's speed is 63 floors/min in opposite direction (towards Steve).
Their relative speed will be the sum of their individual speeds = 57 + 63 = 120 floors/min

Time taken to meet = 40/120 = 1/3 min = 20 secs

Distance covered by Steve in 20 secs = Speed*Time = 57 * (1/3) = 19 floors.
So he is at 11+19 = 30th floor when they meet.

Answer (C)
Hi [b]KarishmaB [/b], Thank you for the explanation,
i am struggling to understand one thing, why is everyone assuming the meeting distance wrto steve, if we consider wrto steve then 11+19 = 30 is correct, but in the question there are two people Joyce coming down from 51st floor, so if we consider 19 with respect to joyce then the answer is 32 ? How to deduce this ?
Show more
W.R.T Joyce, the distance covered when they meet wouldn't be 19 but (63 * 1/3) = 21 since Joyce's speed is 63 floors/min. So, Joyce will have to go down to (51 -21) floor = 30th floor. Hope this helps.
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Steve gets on the elevator at the 11th floor of a building a 18 Jun 2025, 23:07
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You can calculate it wrto either.

Time taken to meet = 1/3 mins

Steve covered 57 * 1/3 = 19 floors. So he reached 11 + 19 = 30th floor
Joyce covered 63 ( 1/3) = 21 floors. So she reached 51 - 21 = 30th floor



IMpratik
KarishmaB
AshikaP
Steve gets on the elevator at the 11th floor of a building and rides up at a rate of 57 floors per minute. At the same time Joyce gets on an elevator on the 51st floor of the same building and rides down at a rate of 63 floors per minute. If they continue traveling at these rates, at which floor will their paths cross?

A. 19
B. 28
C. 30
D. 32
E. 44

Even though this question uses elevators (which usually means a tougher question), it involves very simple relative speed calculation.

Steve is on 11th floor and Joyce on 51st floor so they have a distance of 40 floors between them.
Steve's speed is 57 floors/min and Joyce's speed is 63 floors/min in opposite direction (towards Steve).
Their relative speed will be the sum of their individual speeds = 57 + 63 = 120 floors/min

Time taken to meet = 40/120 = 1/3 min = 20 secs

Distance covered by Steve in 20 secs = Speed*Time = 57 * (1/3) = 19 floors.
So he is at 11+19 = 30th floor when they meet.

Answer (C)

Check this video for when to use relative speed: https://youtu.be/wrYxeZ2WsEM

Hi [b]KarishmaB [/b], Thank you for the explanation,
i am struggling to understand one thing, why is everyone assuming the meeting distance wrto steve, if we consider wrto steve then 11+19 = 30 is correct, but in the question there are two people Joyce coming down from 51st floor, so if we consider 19 with respect to joyce then the answer is 32 ? How to deduce this ?
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