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Re: The data in the table show cell phone ownership status by grade level [#permalink]
Bunuel wrote:
The data in the table show cell phone ownership status by grade level of 300 middle school students. If one of the 300 students is randomly selected, what is the probability that the student owns a cell phone, given that the student is a seventh grader?




A. 11/60

B. 11/100

C. 163/300

D. 55/163

E. 11/20



The question says "GIVEN that the student is in the 7th grade". That means we can ignore the rest of the chart and only look at the 7th grade row. 55/100 is 11/20, answer E.
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Re: The data in the table show cell phone ownership status by grade level [#permalink]
Chakolate wrote:
Bunuel wrote:
The data in the table show cell phone ownership status by grade level of 300 middle school students. If one of the 300 students is randomly selected, what is the probability that the student owns a cell phone, given that the student is a seventh grader?




A. 11/60

B. 11/100

C. 163/300

D. 55/163

E. 11/20



The question says "GIVEN that the student is in the 7th grade". That means we can ignore the rest of the chart and only look at the 7th grade row. 55/100 is 11/20, answer E.


We're asked to choose 1 student from the total of 300, so your answer is wrong!
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Re: The data in the table show cell phone ownership status by grade level [#permalink]
hoang221 wrote:

We're asked to choose 1 student from the total of 300, so your answer is wrong!


You say I'm wrong, I say you're wrong. I guess we'll have to wait until Bunuel weighs in.
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The data in the table show cell phone ownership status by grade level [#permalink]
Use Bayes' theorem. P(A|B) = P(B|A)P(A)/P(B). We have:

P(A|B) is the prob that given a student in 7th grade, he/she has a smartphone (what we want to find).

P(B|A) is the prob. that given a student in 7th grade with a smartphone, he/she is in the 7th grade. Therefore, P(B|A) = 1.

P(A) is the prob. that a 7th grade student has a smartphone. Hence, P(A) = 55/300.

P(B) is the prob. that a student is in 7th grade. Thus, P(B) = 1/3.

Finally, P(A|B) = 1(55/300)/3 = 165/300 = 11/20.

Hope this helps.
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The data in the table show cell phone ownership status by grade level [#permalink]
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