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Re: The employees of a certain department of Company X currently [#permalink]
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gmatophobia wrote:
joaoalencar023 wrote:
The employees of a certain department of company X constitute 22 percent of the employees of the company. If the company were to expand the department by adding 2 employees new to the company for every current employee of the department, the percent of the employees of Company X who would be the in this department would be closest to?

A)40%
B)44%
C)46%
D)52%
E)60%


The employees of a certain department of company X constitute 22 percent of the employees of the company.

Assume

  • The number of employees that the company has = \(100\)
  • The number of employees that the department has = \(22 {\text{% of }}100 = 22\)

If the company were to expand the department by adding 2 employees new to the company for every current employee of the department

  • Number of new employees = \(2*22 = 44\)
  • The number of employees that the department has after the addition of 44 new employees= \(22 + 44 = 66\)
  • The number of employees that the company has after the addition of 44 new employees = \(144\)

the percent of the employees of Company X who would be in this department would be closest to

Required precentage \(= \frac{66}{144} * 100 = \frac{33}{72}*100 = \frac{33}{36}*50\)

\(\frac{33}{36} \approx 1\), hence, the percentage will be slightly greater than 50.

Option D



Confused on this one...

If we use 100 employees to start
X = Dept
C = Company

X=22
C = 100

If we add 2 new employees for every employee in Dept X, we would add 44 new employees

(22+44) / (100+44) * 100 = Percent of Employees in Company in Dept X

66/144 = .4583333 * 100 = 46%?

Normally i would agree with the estimation of 33/36 roughly equal to 1, but here the answers are too close to make that assumption no?
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The employees of a certain department of Company X currently [#permalink]
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­I just had this question in my mock exam today and the correct answer is indeed answer C: 46% 

Once I reached 66/144 I looked for the GCF (66,144), which is 6.

66/144 = 11/24 and that equals to 44/96. 
From this fraction, I know that the answer is less than 50% and also that it is more than 44% as 44/96>44/100. 

The only possible answer for 44%<x<50% is C: 46%. 

:) 

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The employees of a certain department of Company X currently [#permalink]
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Expert Reply
 
joaoalencar023 wrote:
The employees of a certain department of Company X currently constitute 22 percent of the employees of the company. If the company were to expand the department by adding 2 employees new to the company for every current employee of the department, the percent of the employees of Company X who would then be in this department would be closest to

A. 40%
B. 44%
C. 46%
D. 52%
E. 66%


Attachment:
2024-01-28_21-06-39.png


Of 100 employees in company X, 22 belong to the department. If for every 1 employee of the department, 2 are added, for 22 employees 44 are added.

Hence, in the department we now have 66 employees while total number of employees becomes 144. 

Required Percentage = \(\frac{66}{144} = \frac{11}{24}\)

This is less than 50% because 12/24 would be 50%. It is also more than 44% because 11/25 would be 44/100. The only possible option is 46%.

Answer (C)

Click here to check out my video on Estimations

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Re: The employees of a certain department of Company X currently [#permalink]
33/72 = 11/24.

11/24 is 1/24 less than 12/24 or 50%.

1/24 or 4/96 is real close to 4/100, so it must be:

50%-4% = 46%

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Re: The employees of a certain department of Company X currently [#permalink]
@joaoalencar023Given: The employees of a certain department of Company X currently constitute 22 percent of the employees of the company.
Asked: If the company were to expand the department by adding 2 employees new to the company for every current employee of the department, the percent of the employees of Company X who would then be in this department would be closest to
Let the total employees of the company be x.
Employees in the department = 22%x = .22x

Employees to be added to the department = 2*.22x = .44x
Employees in the department = .22x + .44x = .66x
Total employees = x + .44x = 1.44x

The percent of the employees of Company X who would then be in the department = .66x/1.44x = 46%

IMO C
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Re: The employees of a certain department of Company X currently [#permalink]
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