The numbers a, b, and c are all positive. If b^2 - c^2 = 17, then wha

(a+b)(a-b)=17

both statements don't get us close to the value of C
in order to get value of c we have to know value of A or B for that we can use both statements and get value of A and B to get value of C

b^2-c^2=17>>(a-3)^2-c^2=17
and a+b=21
a=12,b=9
with this we get c=+-8 we know they are positive so 8

hence answer is C

Hi ,
(b+c)(b-c)=17, what is the value of (a+c)(a-c)?
Statement 1 is insufficient:
This does not say anything c. Also a-b=3 will have many values for a and b.
Statement 2 is also insufficient:
This again does not say anything about c. Also (a + b)/(a - b)= 7 has many values.
Together sufficient:
(a+b)=21 and a-b=3
Solving we get a=12 and b=9
If we subs in b^2 - c^2 = 17 we get c^2=8.
So we know values of a and c.
So together sufficient.
Answer is C.

I think the answer should be D. b^2-c^2 = 17, leaves us with two b = 9 and C = 8. These are the only two possible positive numbers whose squares differ by 17.
a. Substituting for b, we get a, and hence sufficient.
b. Again substituting for b, we get the value for A. Sufficient.

Hi nphatak,

The prompt does NOT state that A, B and C are integers. Knowing that they might be non-integers, are there any OTHER values that you can come up with for B and C.....?

GMAT assassins aren't born, they're made,
Rich

MAGOOSH OFFICIAL SOLUTION:

Let X = a^2 - c^2, the value we are seeking. Notice if we subtract the first equation in the prompt from this equation, we get a^2 - b^2 = X – 17. In other words, if we could find the value of a^2 - b^2, then we could find the value of X.

Statement #1: a – b = 3

From this statement alone, we cannot calculate a^2 - b^2, so we can’t find the value of X. Statement #1, alone and by itself, is insufficient.

Statement #2: (a + b)/(a - b) = 7

From this statement alone, we cannot calculate a^2 - b^2, so we can’t find the value of X. Statement #2, alone and by itself, is insufficient.

Statements #1 & #2 combined: Now, if we know both statements are true, then we could multiple these two equations, which cancel the denominator, and result in the simple equation a + b = 21. Now, we have the numerical value of both (a – b) and (a + b), so from the difference of two squares formula, we can figure out a^2 - b^2, and if we know the numerical value of that, we can calculate X and answer the prompt. Combined, the statements are sufficient.

Answer = C

Dear , can you I tried to find examples for A,B as non-integer numbers in form (A+B)(A-B)=17 but i did not found?

can you give me examples

Dear , can you I tried to find examples for A,B as non-integer numbers in form (A+B)(A-B)=17 but i did not found?

can you give me examples

hi 23a2012
you can have lot of examples ...
let a+b=17/2.. a-b=2... so (a+b)(a-b)=2*17/2=17..
there are two numbers a and b and two eq, so u can find the answer..
a+b=17/2..
a-b=2 or a=b+2.
put the value in above equation..
b+2+b=17/2..
2*b=17/2 - 2 = 13/2.... so b = 13/4 and a= b+2=13/4+2=21/4....
similarly a+b=17/3.. a-b=3... and so on

Hi Bunuel,
I don't know why I don't get the highlighted part above. I get the arithmetic behind it but fail to understand why we can do this. I am familiar with systems of equations where you add and subtract equations to eliminate terms. I have a feeling this is very simple but I am just not seeing it. Please help!
Thanks

Hi renept,

I think that you might find it easier to think of that math as 'substitution' instead of multiplication.

Fact 1 tells us that (a - b) = 3
Fact 2 gives us another equation: (a + b)/(a - b) = 7

Combining the two Facts, notice how (a - b) appears in both equations? We can 'substitute' the value of (a - b) into the second equation, which would give us...

(a + b)/3 = 7
(a + b) = 21

GMAT assassins aren't born, they're made,
Rich

(1) a – b = 3
3 variable 2 eqn not possible to solve
Clearly insufficient

(2) (a + b)/(a - b)= 7
3 variable 2 equation not possible

However when 1 and 2 is combined 3 variables 3 equation possible to solve

Therefore IMO D

The equation (B^2 - C^2 = 17) can be factored as ((B + C)(B - C) = 17). The possible factor pairs for 17 are ((1, 17)) and ((-1, -17)), since 17 is a prime number. This leads to the following possibility:

(B + C = 17) and (B - C = 1)
Solving these two equations simultaneously, we get (B = 9) and (C = 8)

HENCE Now we can solve for A and the answer is {b}Option D[/b]
Bunuel EMPOWERgmatRichC help!!!!!!!!!!

We are not give that a, b, and c are integers, hence your reasoning in red above is not correct.

Hi Arihant16,

This exact issue is discussed in older posts further up the thread, but to reiterate:

While the prompt does tell us that A, B and C are POSITIVE, it does NOT state that the three variables are integers. Thus, while B=9, C=8 is a possible solution to the given equation, it is NOT the only one.

GMAT assassins aren't born, they're made,
Rich

Contact Rich at: Rich.C@empowergmat.com
www.empowergmat.com

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Since A,B,C are all positive and not the integer, We can also give B=5 and C=2\(\sqrt{2}\) then also your answer might come, Since it is just a number not integer, you cant give this as answer