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Thanks Bunuel! I caught my mistake. I was looking for other ways of solving question 133 OG 13th edi (121 in 12th edi), and that is how I landed here. Similar version of this question in the 13th and 12th edi OGs has the word 'once' instead of 'twice', as in the above question. My bad :( !!
Is my approach at solving the question correct?
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Thanks Bunuel! I caught my mistake. I was looking for other ways of solving question 133 OG 13th edi (121 in 12th edi), and that is how I landed here. Similar version of this question in the 13th and 12th edi OGs has the word 'once' instead of 'twice', as in the above question. My bad :( !!
Is my approach at solving the question correct?

Yes, for that question you solved correctly. Discussed here: there-are-8-teams-in-a-certain-league-and-each-team-plays-134582.html

Similar questions to practice:
how-many-diagonals-does-a-polygon-with-21-sides-have-if-one-101540.html
if-10-persons-meet-at-a-reunion-and-each-person-shakes-hands-110622.html
10-business-executives-and-7-chairmen-meet-at-a-conference-126163.html
how-many-different-handshakes-are-possible-if-six-girls-129992.html
15-chess-players-take-part-in-a-tournament-every-player-55939.html
there-are-5-chess-amateurs-playing-in-villa-s-chess-club-127235.html
if-each-participant-of-a-chess-tournament-plays-exactly-one-142222.html
there-are-8-teams-in-a-certain-league-and-each-team-plays-134582.html

All OG13 questions with solutions: the-official-guide-quantitative-question-directory-143450.html

Hope it helps.
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Hi All,

This prompt is remarkably similar to the following prompt:

there-are-8-teams-in-a-certain-league-and-each-team-plays-134582.html

However, since each team plays each other team TWICE (and not just once), the total number of games played is doubled.

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Smita04
There are 8 teams in a certain league and each team plays each of the other teams exactly twice. If each game is played by 2 teams, what is the total number of games played?

A. 15
B. 16
C. 28
D. 56
E. 64

When each team plays each of the other teams exactly once, the total number of games played would be 8C2 = (8 x 7)/2! = 28 games, so when each team plays the other teams twice, 28 x 2 = 56 games are played.

Answer: D
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It is a permutation solution,

8P2, (8x7x6!)/6!= 56
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Total number of games played = 8C2×2 = 56
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