There are 8 teams in a certain league and each team plays each of the other team exactly once.if each game is played by 2 teams, what is the total number of games played?

a) 15
b) 16
c) 28
d) 56
e) 64
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Another approach to understand this question:

Make everyone stand in a line:
A B C D E F G H
A plays a game with each of the 7 others so 7 games. Now all A's games are done.
B plays a game with each of the 6 others ( C D E F G H) so 6 games. (The game of B with A has already been counted when we were counting A's games. So you just have to move forward, not back). All B's games are done.
Now C plays a game with each of the 5 others (D E F G H) so 5 games and so on till G plays 1 game with H.
Adding 7+6+5+...+1 = 7*8/2 = 28
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Every team plays with 7 teams...so total no of matches = 8 x 7 = 56.
Now, each match is played twice => 56 x 2
But 2 teams play a match => 56 x 2 /2 = 56.

Thanks Bunuel! I caught my mistake. I was looking for other ways of solving question 133 OG 13th edi (121 in 12th edi), and that is how I landed here. Similar version of this question in the 13th and 12th edi OGs has the word 'once' instead of 'twice', as in the above question. My bad !!
Is my approach at solving the question correct?

Hi All,

This prompt is remarkably similar to the following prompt:

there-are-8-teams-in-a-certain-league-and-each-team-plays-134582.html

However, since each team plays each other team TWICE (and not just once), the total number of games played is doubled.

Final Answer:

GMAT assassins aren't born, they're made,
Rich
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total games played games would be 8c2 ; 28
IMO C