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Two runners, P and Q, competed in a race of 400 m
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Updated on: 13 Aug 2018, 06:06
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3 common mistakes you must avoid in Distance questions – Practice question 1 Two runners, P and Q, competed in a race of 400 m. P ran at a constant speed of 5 strides in every 2 seconds, covering 10 m in that span. Q started at a constant speed. After running for 1 minute, Q increased its speed by 1 stride per second and finally finished the race at the same time with P. What is Q’s initial speed in kph if Q covered 4 m in every stride? A. 10 kph B. 11.5 kph C. 12.8 kph D. 13.6 kph E. 14.4 kph To solve question 2: Question 2To read the article: 3 common mistakes you must avoid in Distance questions
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Re: Two runners, P and Q, competed in a race of 400 m
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18 May 2018, 01:53
EgmatQuantExpert wrote: 3 common mistakes you must avoid in Distance questions – Practice question 1 Two runners, P and Q, competed in a race of 400 m. P ran at a constant speed of 5 strides in every 2 seconds, covering 10 m in that span. Q started at a constant speed. After running for 1 minute, Q increased its speed by 1 stride per second and finally finished the race at the same time with P. What is Q’s initial speed in kph if Q covered 4 m in every stride? A. 10 kph B. 11.5 kph C. 12.8 kph D. 13.6 kph E. 14.4 kph To solve question 2: Question 2To read the article: 3 common mistakes you must avoid in Distance questions Velocity of P = 10/2 = 5m/sec The total time taken by P = 400/5 = 80 sec. Now, out of 80 sec, Q has travelled at a constant speed of a fro 60 sec. Therefore, total distance travelled by Q in 60 Sec = 60a. In the remaining 20 sec... for every 1 Sec the velocity of Q increases by 4m/sec. 400 = 60a + 20a + 80 a = 4m/sec = 14.4kmph
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Re: Two runners, P and Q, competed in a race of 400 m
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Updated on: 20 May 2018, 06:25
Solution Given:• Two runners, P and Q, competed in a race of 400 m • P ran at a constant speed of 5 strides in every 2 seconds, covering 10 m in that span o Hence, in 2 seconds P covered 10 m Or, speed of P = \(\frac{10}{2}\) m/s = 5 m/s • Q started the race at a constant speed • Q covered 4 m in every stride • After running for 1 minute, Q increased its speed by 1 stride per second • Q finished the race, taking the same time as P To find:• The initial speed of Q, in kph Approach and Working: • As the race distance is 400 m and speed of P is 5 m/s, o Time taken by P to finish the race = \(\frac{400}{5}\) secs = 80 seconds • Given that the time taken by P and Q is same, Q also takes 80 seconds to finish the race • Let us assume that in the initial 60 seconds, Q took x strides per second o Therefore, in the last 20 seconds, Q took (x + 1) strides per second • As Q covers 4 m in every stride, the total distance covered by Q = 4 [60x +20(x + 1)] m Or, 4 [60x + 20 (x + 1)] = 400 Or, 60x + 20x + 20 = 100 Or, 80x = 80 Or, x = 1 stride/sec • Given that Q covered 4 m in every stride, the initial speed of Q = 4 m/s = 4 * \(\frac{18}{5}\) kph = \(\frac{72}{5}\) kph = 14.4 kph Hence, the correct answer is option E. Answer: E
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Re: Two runners, P and Q, competed in a race of 400 m
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16 May 2018, 18:34
EgmatQuantExpert wrote: 3 common mistakes you must avoid in Distance questions – Practice question 1 Two runners, P and Q, competed in a race of 400 m. P ran at a constant speed of 5 strides in every 2 seconds, covering 10 m in that span. Q started at a constant speed. After running for 1 minute, Q increased its speed by 1 stride per second and finally finished the race at the same time with P. What is Q’s initial speed in kph if Q covered 4 m in every stride? A. 10 kph B. 11.5 kph C. 12.8 kph D. 13.6 kph E. 14.4 kph Q's race, like P's, lasts (400/10)*2=80 seconds let x=Q's speed in mps in first minute 60*x+20*(x+4)=400 x=4 mps=14.4 kph E



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Re: Two runners, P and Q, competed in a race of 400 m
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11 Aug 2019, 06:23
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Re: Two runners, P and Q, competed in a race of 400 m
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