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What is the ratio of 2^(-16) + 2^(-17) + 2^(-18) + 2^(-19)/5/4 to 2^(-

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Bunuel
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What is the ratio of 2^(-16) + 2^(-17) + 2^(-18) + 2^(-19)/5/4 to 2^(- [#permalink] New post   24 Apr 2018, 23:03
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What is the ratio of \(\frac{2^{(-16)} + 2^{(-17)} + 2^{(-18)} + 2^{(-19)}}{\frac{5}{4}}\) to \(2^{(-17)}\)?

(A) 3 to 2
(B) 5 to 2
(C) 3 to 1
(D) 4 to 1
(E) 5 to 1
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C
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Bunuel
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Re: What is the ratio of 2^(-16) + 2^(-17) + 2^(-18) + 2^(-19)/5/4 to 2^(- [#permalink] New post   24 Apr 2018, 23:06
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Bunuel wrote:
What is the ratio of \(\frac{2^{(-16)} + 2^{(-17)} + 2^{(-18)} + 2^{(-19)}}{\frac{5}{4}}\) to \(2^{(-17)}\)?

(A) 3 to 2
(B) 5 to 2
(C) 3 to 1
(D) 4 to 1
(E) 5 to 1


Similar question to practice: https://gmatclub.com/forum/the-value-of ... 30682.html
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obliraj
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Re: What is the ratio of 2^(-16) + 2^(-17) + 2^(-18) + 2^(-19)/5/4 to 2^(- [#permalink] New post   24 Apr 2018, 23:22
((2^(-19)(2^3+2^2+2+1))/5/4)/ 2^(-17)
=2^(-17)(15)/5/ 2^(-17)
=3/1
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Re: What is the ratio of 2^(-16) + 2^(-17) + 2^(-18) + 2^(-19)/5/4 to 2^(- [#permalink] New post   29 Sep 2018, 08:54
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Bunuel wrote:
What is the ratio of \(\frac{2^{(-16)} + 2^{(-17)} + 2^{(-18)} + 2^{(-19)}}{\frac{5}{4}}\) to \(2^{(-17)}\)?

(A) 3 to 2
(B) 5 to 2
(C) 3 to 1
(D) 4 to 1
(E) 5 to 1


Here, this is how I did it.

Ans is 3 to 1 (C)
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Re: What is the ratio of 2^(-16) + 2^(-17) + 2^(-18) + 2^(-19)/5/4 to 2^(- [#permalink]
29 Sep 2018, 08:54
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