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What is the value of product abc?

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What is the value of product abc?  [#permalink]

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Updated on: 09 Jul 2013, 22:16
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What is the value of product abc?

(1) 2^a * 3^b * 5^c = 1728
(2) a, b, and c are nonnegative integers

Hello, community: try out this problem that I just wrote up for one of my students.

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Brian

Curriculum Developer, Instructor, and Host of Veritas Prep On Demand

Save $100 on live Veritas Prep GMAT Courses and Admissions Consulting Enroll now. Pay later. Take advantage of Veritas Prep's flexible payment plan options. Veritas Prep Reviews Originally posted by VeritasPrepBrian on 16 Nov 2010, 17:12. Last edited by Bunuel on 09 Jul 2013, 22:16, edited 3 times in total. RENAMED THE TOPIC. Most Helpful Community Reply Orion Representative Joined: 26 Jul 2010 Posts: 353 Re: Data Sufficiency Challenge Problem [#permalink] Show Tags 17 Nov 2010, 09:36 4 2 Thanks for the responses, everyone! I love this question because of the strategy it brings up, which we call: Why Are You Here? Regarding statement 2, it's nowhere close to being sufficient on its own. So there are two likely reasons that it's there: 1) To trick you into thinking that you need it, and therefore picking C instead of A 2) To add information that IS, in fact, necessary to go with statement 1, so that the correct answer is C and not A The GMAT doesn't use "red herring" statements - those that are simply so far out of scope that they're not even relevant - very often at all; if they provide a statement in a Data Sufficiency problem there has to be a reason...it's either a trap or it's necessary information. The good news for you is that you can use either case the same way: look at that statement to determine whether you really need it. Here, although statement 1 may seem sufficient on its own (c must be 0 in order to make the 5 term equal to 1, since 1728 has no multiples of 5), that only fits if we know that they're all integers. Statement 2, by providing us with that information explicitly (they're nonnegative integers), should make us pause to think about statement 1: Do they have to be integers? We don't need to use logarithms on the GMAT (thankfully!), but we should know enough that there would conceivably exist a set of noninteger exponents that would solve this problem. Even if you just assume that a and b are 1 so that: 5^c = 288 There is some value for c that will get us 288, so we can prove that statement 1 is not on its own sufficient. We need statement 2's help to determine that they're integers, so the correct answer is C. So, strategically, when you see a statement that on its own is clearly not sufficient, ask yourself "why are you here?". Is it providing essential information, or is it there to make you think you need it? _________________ Brian Curriculum Developer, Instructor, and Host of Veritas Prep On Demand Save$100 on live Veritas Prep GMAT Courses and Admissions Consulting

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Re: Data Sufficiency Challenge Problem  [#permalink]

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16 Nov 2010, 23:55
[quote="VeritasPrepBrian"]Hello, community:

Try out this problem that I just wrote up for one of my students:

What is the value of product abc?

1) 2^a * 3^b * 5^c = 1728

2) a, b, and c are nonnegative integers[/quote]

1728 = 2^6 * 3^3 * 5^0

(1) If a,b,c are not integers, they can take infinite values
Eg (6,3,0) is te integral solution
Take c=0, a=1 then b = [m]log_3(864)[/m]
Take c=0, a=2 then b = [m]log_3(432)[/m]

(2) Not sufficient to know the product

(1+2) Since prime factorisation is unique, a=6,b=3,c=0 ()--> abc=0
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Re: Data Sufficiency Challenge Problem  [#permalink]

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Updated on: 17 Nov 2010, 03:50
1728=(2^6)X(3^3)X(5^0)
=> c=0 by equating the powers of like terms on both sides.

So what ever the value of a & b, the product with c will be zero.

The statement that neither of the nos a,b,c are non negative doesnt give any solution.

So i feel the answer is A

Please correct me if I am wrong.

Originally posted by mattapraveen on 17 Nov 2010, 02:04.
Last edited by mattapraveen on 17 Nov 2010, 03:50, edited 1 time in total.
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Re: Data Sufficiency Challenge Problem  [#permalink]

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17 Nov 2010, 02:30
I chose A, as 1728 is 2^6*3^3 .

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Re: Data Sufficiency Challenge Problem  [#permalink]

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17 Nov 2010, 13:51
1
It should be C.
(1) does not give me enough information. There are different variations of a,b,c (integers, non-integers, lagorithmus, positive and negative values) that will satisfy the equations. insufficient

(2) alone insufficient.

Combining (1) and (2) we have now the information that supplement statement (1). If we know that a,b,c are non-negative integers, we could then say that the only possible values are 6,3 and 0 (1728=2^6*3^3*5^0) and the value of a*b*c=0
Hence C
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Re: Data Sufficiency Challenge Problem  [#permalink]

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17 Nov 2010, 16:36
1
1) 2^a * 3^b * 5^c = 1728 => 2^6 * 3^3 * 5^0 . Therefore, abc = 6*3*0 =0 .
So, 1) should be sufficient.

2) a, b, c are non negative . i.e they can be positive or 0. However, this could lead to multiple values for abc. So, 2) is not sufficient.

Answer is A, 1) ALONE is sufficient
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Re: Data Sufficiency Challenge Problem  [#permalink]

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17 Nov 2010, 23:47
A for me.
2^a * 3^b * 5^c = 1728 would mean that the factor of 5 does not contribute to the multiplication (mutiples of 5 end with 5 or 0). Hence the value of c = 0. By knowing this, I can say that the value of abc = 0.
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Re: Data Sufficiency Challenge Problem  [#permalink]

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18 Nov 2010, 08:48
From statement 1 we can factor out 1728=2^6 *3^3 *5^1
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Yesterday's DS Challenge Question - solution here!  [#permalink]

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18 Nov 2010, 14:37
2
Hey everyone - sorry...yesterday's question was formatted as "competition mode" and I can't figure out how to undo it, so I don't think anyone has seen my response yet. Here it is:

_______________________________________________________________________________________________________________

Thanks for the responses, everyone! I love this question because of the strategy it brings up, which we call:

Why Are You Here?

Regarding statement 2, it's nowhere close to being sufficient on its own. So there are two likely reasons that it's there:

1) To trick you into thinking that you need it, and therefore picking C instead of A
2) To add information that IS, in fact, necessary to go with statement 1, so that the correct answer is C and not A

The GMAT doesn't use "red herring" statements - those that are simply so far out of scope that they're not even relevant - very often at all; if they provide a statement in a Data Sufficiency problem there has to be a reason...it's either a trap or it's necessary information. The good news for you is that you can use either case the same way: look at that statement to determine whether you really need it.

Here, although statement 1 may seem sufficient on its own (c must be 0 in order to make the 5 term equal to 1, since 1728 has no multiples of 5), that only fits if we know that they're all integers. Statement 2, by providing us with that information explicitly (they're nonnegative integers), should make us pause to think about statement 1: Do they have to be integers?

We don't need to use logarithms on the GMAT (thankfully!), but we should know enough that there would conceivably exist a set of noninteger exponents that would solve this problem. Even if you just assume that a and b are 1 so that:

5^c = 288

There is some value for c that will get us 288, so we can prove that statement 1 is not on its own sufficient. We need statement 2's help to determine that they're integers, so the correct answer is C.

So, strategically, when you see a statement that on its own is clearly not sufficient, ask yourself "why are you here?". Is it providing essential information, or is it there to make you think you need it?
_________________

Brian

Curriculum Developer, Instructor, and Host of Veritas Prep On Demand

Save \$100 on live Veritas Prep GMAT Courses and Admissions Consulting

Enroll now. Pay later. Take advantage of Veritas Prep's flexible payment plan options.

Veritas Prep Reviews

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Re: Yesterday's DS Challenge Question - solution here!  [#permalink]

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19 Nov 2010, 07:28
I picked the answer as A and now I figure out what was my mistake.

But still, its very difficult to think that in the expression 2^a * 3^b * 5^c = 1728, even with a,b and c taking non integer value we can get the product,1728.
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Re: What is the value of product abc?  [#permalink]

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04 May 2014, 08:26
hi brian

so basically we should never assume that the numbers r integers if it is not given... also i need some explanation for statement one.... how is a,b,c being integers matter?... if they were fractions... how would they give us that number 1728?
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Re: What is the value of product abc?  [#permalink]

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20 May 2014, 06:25
NGGMAT wrote:
hi brian

so basically we should never assume that the numbers r integers if it is not given... also i need some explanation for statement one.... how is a,b,c being integers matter?... if they were fractions... how would they give us that number 1728?

When a, b, c are integers, and we have first statement as well, we need to put c=0 because 1728 has no 5 in it, and we have to make 5^c as 1. Even if they are fractions there can be two cases,

Case 1: They can be rational numbers/fractions, in which case the information coupled with statement 1 will be sufficient.

Case 2: They can be irrational numbers/fractions. In this case it won't suffice.

Hope it makes sense!!!
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Re: What is the value of product abc?  [#permalink]

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23 May 2014, 02:04
1
Hi,

Find value of abc

Statement 1: $$2^a * 3^b * 5^c = 1728$$
$$1728 = 2^6 * 3^3 * 5^0$$

Therefore, $$2^a * 3^b * 5^c = 2^6 * 3^3 * 5^0$$

a, b and c can have values: 6, 3 and 0 respectively.
or
if we take values for a and b to be 5, 3, we get: $$5^c = 2$$ =>$$c=\frac{log 2}{log5}$$
if we take values for a and b to be 6, 2, we get: $$5^c = 3$$ =>$$c= \frac{log 3}{log5}$$

Multiple solutions exist. So not sufficient

Statement 2: a, b, and c are nonnegative integers

Not sufficient

Combining both Statements,

we get, a = 6, b= 3 and c= 0

Hence,
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Re: What is the value of product abc?  [#permalink]

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12 Sep 2018, 10:14
VeritasPrepBrian wrote:
What is the value of product abc?

(1) 2^a * 3^b * 5^c = 1728
(2) a, b, and c are nonnegative integers

$$? = abc$$

$$\left( 1 \right)\,\,\,{2^a} \cdot {3^b} \cdot {5^c} = 1728\,\,\,\,\,\,\left\{ \begin{gathered} \,{\text{Take}}\,\,\left( {a,b,c} \right) = \left( {6,3,0} \right)\,\,\,\,\,\,\,\, \Rightarrow \,\,\,\,\,\,\,? = 0\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\left[ {1728 = {2^6} \cdot {3^3}} \right] \hfill \\ \,{\text{Take}}\,\,\left( {a,b,c} \right) = \left( {{x_{\text{p}}},1,1} \right)\,\,\,\,\,\,\,\mathop \Rightarrow \limits^{\left( * \right)} \,\,\,\,\,\,\,? = {x_{\text{p}}} > 0\,\,\,\,\,\,\,\,\,\, \hfill \\ \end{gathered} \right.$$

$$\left( * \right)\,\,\,{2^x} = \frac{{1728}}{{15}}\,\,\,\,\, \Rightarrow \,\,\,\,x = {x_p} > 0\,\,\,{\text{unique}}\,\,\,\,\,\,\left( {{\text{see}}\,\,{\text{image}}\,\,{\text{attached}}} \right)$$

$$\left( 2 \right)\,\,a,b,c\,\,\, \geqslant 0\,\,\,\,{\text{ints}}\,\,\,\,\left\{ \begin{gathered} \,{\text{Take}}\,\,\left( {a,b,c} \right) = \left( {0,0,0} \right)\,\,\,\,\, \Rightarrow \,\,\,\,\,? = 0 \hfill \\ \,\,Take\,\,\left( {a,b,c} \right) = \left( {1,1,1} \right)\,\,\,\,\, \Rightarrow \,\,\,\,\,? = 1 \hfill \\ \end{gathered} \right.$$

$$\left( {1 + 2} \right)\,\,\,\left\{ \begin{gathered} {2^a} \cdot {3^b} \cdot {5^c} = 1728 = {2^6} \cdot {3^3} \cdot {5^0} \hfill \\ \,a,b,c\,\,\, \geqslant 0\,\,\,\,{\text{ints}} \hfill \\ \end{gathered} \right.\,\,\,\,\,\,\,\,\, \Rightarrow \,\,\,\,\,\,\left( {a,b,c} \right) = \left( {6,3,0} \right)\,\,\,\,\,\,\, \Rightarrow \,\,\,\,? = 0\,\,\,\,\, \Rightarrow \,\,\,\,\,{\text{SUFF}}.\,\,\,\,\,\,\,$$

This solution follows the notations and rationale taught in the GMATH method.

Regards,
Fabio.
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Re: What is the value of product abc?   [#permalink] 12 Sep 2018, 10:14
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