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Re: What is the value of xy ? (1) y – 1 = x (2) x^2 + x – 6 = 0
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16 Apr 2018, 08:56

Statement 1 : y-1=x, y=x+1, xy=x(x+1)-- no solution Statement 2: Solve the quadratic equation and we get x= 2, -3 If x=2, y=3 (With help from Statement 1), then xy =3x2= 6 If x=-3, y=-2 (With help from Statement 1), then xy =-3 x -2= 6. Answer is C- BOTH statements (1) and (2) TOGETHER are sufficient to answer the question asked, but NEITHER statement ALONE is sufficient to answer the question asked.

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Re: What is the value of xy ? (1) y – 1 = x (2) x^2 + x – 6 = 0 &nbs
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16 Apr 2018, 08:56