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When counting from 3 to 201, 53 is the 51 st number counted. When coun

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Noshad
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When counting from 3 to 201, 53 is the 51 st number counted. When coun [#permalink] New post   20 Mar 2019, 04:25
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When counting from 3 to 201, 53 is the 51 st number counted. When counting backwards from 201 to 3, 53 is the n th number counted. What is n?

(A) 146 (B) 147 (C) 148 (D) 149 (E) 150
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D
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BrentGMATPrepNow
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Re: When counting from 3 to 201, 53 is the 51 st number counted. When coun [#permalink] New post   20 Mar 2019, 08:42
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Noshad wrote:
When counting from 3 to 201, 53 is the 51 st number counted. When counting backwards from 201 to 3, 53 is the n th number counted. What is n?

(A) 146
(B) 147
(C) 148
(D) 149
(E) 150


Counting backwards from 201 to 3
term1 = 201
term2 = 201 - 1 [we're subtracting ONE 1]
term3 = 201 - 1 - 1 = 201 - 2 [we're subtracting TWO 1's]
term4 = 201 - 1 - 1 - 1 = 201 - 3 [we're subtracting THREE 1's]
term5 = 201 - 1 - 1 - 1 - 1 = 201 - 4 [we're subtracting FOUR 1's]
.
.
.
See the pattern?
The number we subtract from 201 is one less than the term number.
For example, term40 = 201 - 39

In general, term n = 201 - (n-1)
We're told that term n = 53
So, we can write: 53 = 201 - (n-1)
Simplify: 53 = 202 - n
Solve: n = 202 - 53 = 149

Answer: D

Cheers,
Brent
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Re: When counting from 3 to 201, 53 is the 51 st number counted. When coun [#permalink] New post   20 Mar 2019, 09:45
Noshad wrote:
When counting from 3 to 201, 53 is the 51 st number counted. When counting backwards from 201 to 3, 53 is the n th number counted. What is n?

(A) 146 (B) 147 (C) 148 (D) 149 (E) 150


total terms = 201-3 + 1 = 199 terms
so from 201 to 53 we will have ; 201-53 = 148 +1 ; 149 terms
IMO D
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Re: When counting from 3 to 201, 53 is the 51 st number counted. When coun [#permalink] New post   25 Mar 2019, 14:37
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Archit3110 wrote:
Noshad wrote:
When counting from 3 to 201, 53 is the 51 st number counted. When counting backwards from 201 to 3, 53 is the n th number counted. What is n?

(A) 146 (B) 147 (C) 148 (D) 149 (E) 150


total terms = 201-3 + 1 = 199 terms
so from 201 to 53 we will have ; 201-53 = 148 +1 ; 149 terms
IMO D


Hello Archit3110!

Is it also ok to do it this way?

\(201 = 53 + (n-1)\)

\(n = 149\)

Kind regards!
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Re: When counting from 3 to 201, 53 is the 51 st number counted. When coun [#permalink] New post   26 Mar 2019, 00:54
jfranciscocuencag wrote:
Archit3110 wrote:
Noshad wrote:
When counting from 3 to 201, 53 is the 51 st number counted. When counting backwards from 201 to 3, 53 is the n th number counted. What is n?

(A) 146 (B) 147 (C) 148 (D) 149 (E) 150


total terms = 201-3 + 1 = 199 terms
so from 201 to 53 we will have ; 201-53 = 148 +1 ; 149 terms
IMO D


Hello Archit3110!

Is it also ok to do it this way?

\(201 = 53 + (n-1)\)

\(n = 149\)

Kind regards!


jfranciscocuencag
well its same formula what I have mentioned in the solution :) ..
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Re: When counting from 3 to 201, 53 is the 51 st number counted. When coun [#permalink] New post   15 Apr 2021, 11:22
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Noshad wrote:
When counting from 3 to 201, 53 is the 51 st number counted. When counting backwards from 201 to 3, 53 is the n th number counted. What is n?

(A) 146 (B) 147 (C) 148 (D) 149 (E) 150


Solution:

When counting backwards from 201 to 3, 53 is the 201 - 53 + 1 = 149th number. Thus, n = 149.

Answer: D
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Re: When counting from 3 to 201, 53 is the 51 st number counted. When coun [#permalink] New post   16 Apr 2021, 00:50
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Total numbers from 3 to 201 are 199.

199 = Left + Right - 1

=> 199 = 51 + Right - 1

=> 199 - 50 = Right

=> 149

Answer D
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Re: When counting from 3 to 201, 53 is the 51 st number counted. When coun [#permalink] New post   17 Oct 2022, 17:29
Hello from the GMAT Club BumpBot!

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Re: When counting from 3 to 201, 53 is the 51 st number counted. When coun [#permalink]
17 Oct 2022, 17:29
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