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When x is divided by 4, the quotient is y and the remainder is 1.
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29 Aug 2014, 12:01

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When x is divided by 4, the quotient is y and the remainder is 1. When x is divided by 7, the quotient is z and the remainder is 6. Which of the following is the value of y in terms of z?

A) 4z/7 + 5 B) (7z + 5) / 6 C) (6z + 7) / 4 D) (7z + 5) / 4 E) (4z + 6) / 7

When x is divided by 4, the quotient is y and the remainder is 1.
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29 Aug 2014, 13:39

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goodyear2013 wrote:

When x is divided by 4, the quotient is y and the remainder is 1. When x is divided by 7, the quotient is z and the remainder is 6. Which of the following is the value of y in terms of z?

A) 4z/7 + 5 B) (7z + 5) / 6 C) (6z + 7) / 4 D) (7z + 5) / 4 E) (4z + 6) / 7

This is easy one.

When x is divided by 4, the quotient is y and the remainder is 1: x = 4y + 1. When x is divided by 7, the quotient is z and the remainder is 6: x = 7z + 6.

Equate those two: 4y + 1 = 7z + 6; y = (7z + 5)/4.

Re: When x is divided by 4, the quotient is y and the remainder is 1.
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10 Dec 2015, 06:32

goodyear2013 wrote:

When x is divided by 4, the quotient is y and the remainder is 1. When x is divided by 7, the quotient is z and the remainder is 6. Which of the following is the value of y in terms of z?

A) 4z/7 + 5 B) (7z + 5) / 6 C) (6z + 7) / 4 D) (7z + 5) / 4 E) (4z + 6) / 7

This is easy one.

Number = Quotient*Divisor + Remainder

x = 4y + 1 (i) x = 7z + 6 (ii)

Equating (i) and (ii) 4y + 1 = 7z + 6 y = (7z + 5)/4

Re: When x is divided by 4, the quotient is y and the remainder is 1.
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27 Jun 2017, 14:27

goodyear2013 wrote:

When x is divided by 4, the quotient is y and the remainder is 1. When x is divided by 7, the quotient is z and the remainder is 6. Which of the following is the value of y in terms of z?

A) 4z/7 + 5 B) (7z + 5) / 6 C) (6z + 7) / 4 D) (7z + 5) / 4 E) (4z + 6) / 7

This is easy one.

X is 13- one way to come with the number is just through trial and error- if x is 13 then z is 1 and y is 3- only D solves for Y

Re: When x is divided by 4, the quotient is y and the remainder is 1.
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26 Jan 2018, 13:47

Hi All,

This question can be solved in a couple of different ways, but you would likely find the algebra to be fairly straight-forward. From the first two sentences, we can create the following 2 equations:

X/4 = Y remainder 1 X = 4Y + 1

X/7 = Z remainder 6 X = 7Z + 6

Now we can set the two equations equal to one another: