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Ofcourse SUBSTITUTION from choices is a good method

Dear chetan2u,

I somehow get stuck on the bold part. Could you briefly elaborate on this step?

Hi... \(7-x=3x^2+3x.........3x^2+4x-7=0.....3x^2+7x-3x-7=0.....x(3x+7)-1(3x+7)=0.....(x-1)(3x+7)=0\).. So either x-1=0, that is x=1 OR 3x+7=0...x=-7/3 OR both x=1 and X=-7/3 But x is NEGATIVE , so x=-7/3