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Working together without taking breaks, Michael and Donna painted the sidewalk in 6 hours. How long would it take Michael to paint the sidewalk by himself?

Let work done by Michael be M and Donna be D
GIVEN : 1/M + 1/D = 1/6
If we get the rate of Donna , we will be able to find one unique value M


(1) If Michael had left when the job was 1/3 done, it would have taken Donna 8 hours to finish the job by herself.

This statement implies that DONNA does 2/3rd of the work in 8 hrs
I.E. 1 work in 8*3/2 hrs = 12 hrs
We have got value of D , We can find the value of M . On solving we get the value of M = 12 hrs

Sufficient A/D

(2) If Donna had to paint 2 identical sidewalks all by herself, it would have taken her 24 hours to finish.

2 identical sidewalks 24 hrs , I.e. 1 sidewalk in 12 hrs
Equation is same as statement 1
Sufficient

Answer is D
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