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# x(x – y) – z(x – y) =

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Re: x(x – y) – z(x – y) = [#permalink]
Bunuel wrote:
$$x(x – y) – z(x – y) =$$

(A) x – y
(B) x – z
(C) (x – y)(x – z)
(D) (x – y)(x + z)
(E) (x – y)(z – x)

Given $$x(x – y) – z(x – y) =$$
(x - y) is common factor, taking out the common factor we get;
(x - y)(x - z)
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Re: x(x – y) – z(x – y) = [#permalink]
Bunuel wrote:
$$x(x – y) – z(x – y) =$$

(A) x – y
(B) x – z
(C) (x – y)(x – z)
(D) (x – y)(x + z)
(E) (x – y)(z – x)

Let’s simplify the given expression:

x(x - y) - z(x - y)

Factoring out (x- y), we have:

(x - y)(x - z)

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Re: x(x – y) – z(x – y) = [#permalink]
2
Kudos
Bunuel wrote:
$$x(x – y) – z(x – y) =$$

(A) x – y
(B) x – z
(C) (x – y)(x – z)
(D) (x – y)(x + z)
(E) (x – y)(z – x)

We need to rearrange the terms in order to get the desired option.
On opening the brackets and rearranging, we get

x^2 - xy - zx + zy = x^2 - zx -xy + zy = x(x - z) - y(x - z) = (x - z)(x - y)

Correct Option C
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Re: x(x – y) – z(x – y) = [#permalink]
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Re: x(x – y) – z(x – y) = [#permalink]
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