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x(x – y) – z(x – y) =

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x(x – y) – z(x – y) =  [#permalink]

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New post 01 Jun 2017, 11:10
00:00
A
B
C
D
E

Difficulty:

  5% (low)

Question Stats:

88% (00:53) correct 12% (01:15) wrong based on 66 sessions

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x(x – y) – z(x – y) =  [#permalink]

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New post 01 Jun 2017, 12:13
Bunuel wrote:
\(x(x – y) – z(x – y) =\)

(A) x – y
(B) x – z
(C) (x – y)(x – z)
(D) (x – y)(x + z)
(E) (x – y)(z – x)


\(x(x – y) – z(x – y) =\)

Factor out \((x - y)\) to get

\((x - y) (x - z)\)

Answer C


To double check work

Prompt: \(x(x – y) – z(x – y) =\)

\((x^2 - xy) - (xz - yz)\)=

\(x^2 - xy - xz + yz\)

Answer: \((x - y) (x - z)\) =

\(x^2 - xz - xy + yz\) - rearrange the two inner terms and it's a match
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Re: x(x – y) – z(x – y) =  [#permalink]

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New post 01 Jun 2017, 14:43
Bunuel wrote:
\(x(x – y) – z(x – y) =\)

(A) x – y
(B) x – z
(C) (x – y)(x – z)
(D) (x – y)(x + z)
(E) (x – y)(z – x)


Given \(x(x – y) – z(x – y) =\)
(x - y) is common factor, taking out the common factor we get;
(x - y)(x - z)
Answer C...
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Re: x(x – y) – z(x – y) =  [#permalink]

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New post 05 Jun 2017, 15:20
Bunuel wrote:
\(x(x – y) – z(x – y) =\)

(A) x – y
(B) x – z
(C) (x – y)(x – z)
(D) (x – y)(x + z)
(E) (x – y)(z – x)


Let’s simplify the given expression:

x(x - y) - z(x - y)

Factoring out (x- y), we have:

(x - y)(x - z)

Answer: C
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Re: x(x – y) – z(x – y) =  [#permalink]

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New post 05 Jun 2017, 15:29
Top Contributor
Bunuel wrote:
\(x(x – y) – z(x – y) =\)

(A) x – y
(B) x – z
(C) (x – y)(x – z)
(D) (x – y)(x + z)
(E) (x – y)(z – x)


The posters above me demonstrated the best/faster approach, BUT if you didn't think of that technique, you can still solve the question.
We're looking for an expression that is EQUIVALENT to x(x – y) – z(x – y)
So, for any set of values for x, y and z, the correct answer must evaluate to have the same value as x(x – y) – z(x – y)

So, let's plug in some values for x, y and z
Let's try x = 3, y = 1 and z = 10

First plug those values into the GIVEN expression.
We get: x(x – y) – z(x – y) = 3(3 – 1) – 10(3 – 1)
= 3(2) – 10(2)
= 6 - 20
= -14

So, the correct answer choice will be the one that evaluates to -14 when we plug in x = 3, y = 1 and z = 10
(A) x – y = 3 - 1 = 2. We want -14. ELIMINATE A
(B) x – z = 3 - 10 = -7. We want -14. ELIMINATE B
(C) (x – y)(x – z) = (3 - 1)(3 - 10) = (2)(-7) = -14. GREAT! KEEP C
(D) (x – y)(x + z) = (3 - 1)(3 + 10) = (2)(13)= 26. We want -14. ELIMINATE D
(E) (x – y)(z – x) = (3 - 1)(10 - 3) = (2)(7)= 14. We want -14. ELIMINATE E

By the process of elimination, the correct answer is

Cheers,
Brent

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Re: x(x – y) – z(x – y) =  [#permalink]

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New post 06 Jun 2017, 05:38
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Bunuel wrote:
\(x(x – y) – z(x – y) =\)

(A) x – y
(B) x – z
(C) (x – y)(x – z)
(D) (x – y)(x + z)
(E) (x – y)(z – x)


We need to rearrange the terms in order to get the desired option.
On opening the brackets and rearranging, we get

x^2 - xy - zx + zy = x^2 - zx -xy + zy = x(x - z) - y(x - z) = (x - z)(x - y)

Correct Option C
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Re: x(x – y) – z(x – y) =  [#permalink]

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New post 09 Feb 2019, 12:09
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: x(x – y) – z(x – y) =   [#permalink] 09 Feb 2019, 12:09
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