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Re: 10^25 – 560 is divisible by all of the following EXCEPT: [#permalink]
Bunuel wrote:
enigma123 wrote:
10^25 – 560 is divisible by all of the following EXCEPT:
a)11
b)8
c)5
d)4
e) 3

Guys any idea what concept has been Tested over here and what will be the answer?

I have started doing it this way but got stuck. So can someone please help?

I have started from

10^5 - 560 = 99,440 i.e. it has two 9s followed by 440.
.
.
10^10 - 560 = 99,99,440 ------------------------------> Am I doing it right this way?


Yes, you were on a right track.

10^(25) is a 26 digit number: 1 with 25 zeros. 10^(25)-560 will be 25 digit number: 22 9's and 440 in the end: 9,999,999,999,999,999,999,999,440 (you don't really need to write down the number to get the final answer). From this point you can spot that all 9's add up to some multiple of 3 (naturally) and 440 add up to 8 which is not a multiple of 3. So, the sum of all the digits is not divisible by 3 which means that the number itself is not divisible by 3.

Answer: E.

You can also quickly spot that the given number is definitely divisible:
By 2 as the last digit is even;
By 4 as the last two digits are divisible by 4;
By 8 as the last three digits are divisible by 8;
By 11 as 11 99's as well as 440 have no reminder upon division by 11 (or by applying divisibility by 11 rule).

Check Divisibility Rules chapter of Number Theory: math-number-theory-88376.html


Thank you Bunuel. I used this tactic after seeing you reference it in other posts. I learned this before but had not committed it to memory until now. Great explanation as always
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Re: 10^25 – 560 is divisible by all of the following EXCEPT: [#permalink]
I am wondering whether the following test for divisibility by 11 is valid:

\((11-1)^{25}-560\) \(\implies\) \(Remainders: -1-10=-11\) \(\implies\) \(Remainder_{total} = 0\)

I am unsure whether from \((11-1)^{25}\) it follows that the remainder is \(-1\) as for instance the remainder of \((11-1)^2\) is \(-10\). So how do I know that the remainder is only -1 when the exponent of \((11-1)^{25}\) is odd?
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Re: 10^25 – 560 is divisible by all of the following EXCEPT: [#permalink]
value of 10^25 has 25 zeroes & 1 one ; last three digits would be 440
440 factors 11*4*5*2 ;
not possible value ; 3
IMO E


enigma123 wrote:
10^25 – 560 is divisible by all of the following EXCEPT:

A. 11
B. 8
C. 5
D. 4
E. 3


Guys any idea what concept has been Tested over here and what will be the answer?

I have started doing it this way but got stuck. So can someone please help?

I have started from

10^5 - 560 = 99,440 i.e. it has two 9s followed by 440.
.
.
10^10 - 560 = 99,99,440 ------------------------------> Am I doing it right this way?
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Re: 10^25 – 560 is divisible by all of the following EXCEPT: [#permalink]
This was my approach.

10^25 will be a huge number with 100..000 we know if we subtract the 560 the number will become 9999....460. We have to focus on the 460 and its divisors.

I took 460 and performed a prime factorization, this results in the factors of 11, 5, 2, 2 , 2 (the building blocks to make 460).

I then took to prime factors of the answer choices.

A) 11 - prime factor is 11 and 11 is a prime factor for 460, therefore out.
B) 8 - 2, 2, 2 - 460 has three prime factors of 2, therefore out
C) 5 - this is also a prime factor of 460, therefore out
D) 4 - 2, 2 - 460 contains at least two prime factors of 2 therefore out
E) 3 - is not a prime factor of 460, therefore, cannot be a divisor

Please let me know if there are any errors using this approach.
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Re: 10^25 – 560 is divisible by all of the following EXCEPT: [#permalink]
Fast Approach:
10^25 – 560 is divisible by all of the following EXCEPT:

A. 11
B. 8
C. 5
D. 4
E. 3


We know that 10^25 finish with zero.

Suppose 1000 - 560 = 440.

440 is an even number, so we can eliminate all the even answer choices: B and D.
440 is also a multiple of 5, so we can eliminate C.

We remain with A (11) and E (3).
440 can be expressed as: 11*40, thus 440 is divisible by 11.

We remain with only 3.

Answer E.
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Re: 10^25 – 560 is divisible by all of the following EXCEPT: [#permalink]
10^25 = 3a +1
Where a is the natural numbers
560 =3b +2
Where b is the natural number
10^25- 560
3a +1- 3b - 2
3(a-b) -1
Not divisible by 3
Option E is the answer

Posted from my mobile device
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Re: 10^25 – 560 is divisible by all of the following EXCEPT: [#permalink]
10^25 – 560
will give us 22*9 & 440 in end
given is even so options b,c,d can be eliminated
among a & e ; 22 times 9 and 440 would be divisble by 11
left with 3 which does not divide the value
option E


enigma123 wrote:
10^25 – 560 is divisible by all of the following EXCEPT:

A. 11
B. 8
C. 5
D. 4
E. 3


Guys any idea what concept has been Tested over here and what will be the answer?

I have started doing it this way but got stuck. So can someone please help?

I have started from

10^5 - 560 = 99,440 i.e. it has two 9s followed by 440.
.
.
10^10 - 560 = 99,99,440 ------------------------------> Am I doing it right this way?
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Re: 10^25 – 560 is divisible by all of the following EXCEPT: [#permalink]
enigma123 wrote:
10^25 – 560 is divisible by all of the following EXCEPT:

A. 11
B. 8
C. 5
D. 4
E. 3



My Approach is Kinda Different.

Rather then multiplying 10^25 we can just take 1000 - 560 which will yield = 440

Which means it is divisible by all numbers except 3

Answer = E
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Re: 10^25 560 is divisible by all of the following EXCEPT: [#permalink]
Bunuel wrote:
enigma123 wrote:
10^25 – 560 is divisible by all of the following EXCEPT:
a)11
b)8
c)5
d)4
e) 3

Guys any idea what concept has been Tested over here and what will be the answer?

I have started doing it this way but got stuck. So can someone please help?

I have started from

10^5 - 560 = 99,440 i.e. it has two 9s followed by 440.
.
.
10^10 - 560 = 99,99,440 ------------------------------> Am I doing it right this way?


Yes, you were on a right track.

10^(25) is a 26 digit number: 1 with 25 zeros. 10^(25)-560 will be 25 digit number: 22 9's and 440 in the end: 9,999,999,999,999,999,999,999,440 (you don't really need to write down the number to get the final answer). From this point you can spot that all 9's add up to some multiple of 3 (naturally) and 440 add up to 8 which is not a multiple of 3. So, the sum of all the digits is not divisible by 3 which means that the number itself is not divisible by 3.

Answer: E.

You can also quickly spot that the given number is definitely divisible:
By 2 as the last digit is even;
By 4 as the last two digits are divisible by 4;
By 8 as the last three digits are divisible by 8;
By 11 as 11 99's as well as 440 have no reminder upon division by 11 (or by applying divisibility by 11 rule).

Check Divisibility Rules chapter of Number Theory: https://gmatclub.com/forum/math-number- ... 88376.html


Hi

Why does the bit above in bold show that the number has no remainder upon division by 11?
Thanks
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Re: 10^25 560 is divisible by all of the following EXCEPT: [#permalink]
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