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Math Expert V
Joined: 02 Sep 2009
Posts: 59674
Re: 12 Easy Pieces (or not?)  [#permalink]

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Shef08 wrote:
Bunuel wrote:
4. If -3<x<5 and -7<y<9, which of the following represent the range of all possible values of y-x?
A. -4<y-x<4
B. -2<y-x<4
C. -12<y-x<4
D. -12<y-x<12
E. 4<y-x<12

To get max value of y-x take max value of y and min value of x: 9-(-3)=12;
To get min value of y-x take min value of y and max value of x: -7-(5)=-12;

Hence, the range of all possible values of y-x is -12<y-x<12.

Why is it not A? Can’t we simply subtract x from y? Then the answer will be A?

Posted from my mobile device

You can only apply subtraction when the signs of inequalities are in the opposite directions:

If $$a>b$$ and $$c<d$$ (signs in opposite direction: $$>$$ and $$<$$) --> $$a-c>b-d$$ (take the sign of the inequality you subtract from).
Example: $$3<4$$ and $$5>1$$ --> $$3-5<4-1$$.

You can only add inequalities when their signs are in the same direction:

If $$a>b$$ and $$c>d$$ (signs in same direction: $$>$$ and $$>$$) --> $$a+c>b+d$$.
Example: $$3<4$$ and $$2<5$$ --> $$3+2<4+5$$.

For more check Manipulating Inequalities.
_________________
Manager  B
Joined: 01 Jan 2019
Posts: 80
Concentration: Finance, Entrepreneurship
GPA: 3.24
Re: 12 Easy Pieces (or not?)  [#permalink]

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Bunuel wrote:
Shef08 wrote:
Bunuel wrote:
4. If -3<x<5 and -7<y<9, which of the following represent the range of all possible values of y-x?
A. -4<y-x<4
B. -2<y-x<4
C. -12<y-x<4
D. -12<y-x<12
E. 4<y-x<12

To get max value of y-x take max value of y and min value of x: 9-(-3)=12;
To get min value of y-x take min value of y and max value of x: -7-(5)=-12;

Hence, the range of all possible values of y-x is -12<y-x<12.

Why is it not A? Can’t we simply subtract x from y? Then the answer will be A?

Posted from my mobile device

You can only apply subtraction when the signs of inequalities are in the opposite directions:

If $$a>b$$ and $$c<d$$ (signs in opposite direction: $$>$$ and $$<$$) --> $$a-c>b-d$$ (take the sign of the inequality you subtract from).
Example: $$3<4$$ and $$5>1$$ --> $$3-5<4-1$$.

You can only add inequalities when their signs are in the same direction:

If $$a>b$$ and $$c>d$$ (signs in same direction: $$>$$ and $$>$$) --> $$a+c>b+d$$.
Example: $$3<4$$ and $$2<5$$ --> $$3+2<4+5$$.

For more check Manipulating Inequalities.

Thank you, Bunuel!
Manager  G
Joined: 13 Apr 2019
Posts: 181
Location: India
Concentration: Marketing, Operations
GMAT 1: 690 Q49 V35 GPA: 3.5
WE: General Management (Retail)
Re: 12 Easy Pieces (or not?)  [#permalink]

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1
Shef08 wrote:
Bunuel wrote:
4. If -3<x<5 and -7<y<9, which of the following represent the range of all possible values of y-x?
A. -4<y-x<4
B. -2<y-x<4
C. -12<y-x<4
D. -12<y-x<12
E. 4<y-x<12

To get max value of y-x take max value of y and min value of x: 9-(-3)=12;
To get min value of y-x take min value of y and max value of x: -7-(5)=-12;

Hence, the range of all possible values of y-x is -12<y-x<12.

Why is it not A? Can’t we simply subtract x from y? Then the answer will be A?

Posted from my mobile device

Here's how to solve using your approach:

A: -7<y<9
B: -3<x<5 this means B': -5<-x<3

A+B':: -12< y-x < 12

Never subtract or multiply or divide inequalities until you are sure of the sign. On the other hand, Addition can be done always irrespective of the sign.
Always use the addition approach on inequalities and never try to shortcut it by multiplying or dividing or subtracting
Manager  B
Joined: 01 Jan 2019
Posts: 80
Concentration: Finance, Entrepreneurship
GPA: 3.24
Re: 12 Easy Pieces (or not?)  [#permalink]

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azhrhasan wrote:
Shef08 wrote:
Bunuel wrote:
4. If -3<x<5 and -7<y<9, which of the following represent the range of all possible values of y-x?
A. -4<y-x<4
B. -2<y-x<4
C. -12<y-x<4
D. -12<y-x<12
E. 4<y-x<12

To get max value of y-x take max value of y and min value of x: 9-(-3)=12;
To get min value of y-x take min value of y and max value of x: -7-(5)=-12;

Hence, the range of all possible values of y-x is -12<y-x<12.

Why is it not A? Can’t we simply subtract x from y? Then the answer will be A?

Posted from my mobile device

Here's how to solve using your approach:

A: -7<y<9
B: -3<x<5 this means B': -5<-x<3

A+B':: -12< y-x < 12

Never subtract or multiply or divide inequalities until you are sure of the sign. On the other hand, Addition can be done always irrespective of the sign.
Always use the addition approach on inequalities and never try to shortcut it by multiplying or dividing or subtracting

That’s a great insight! I’ll have this fitted in my brains! Thanks a ton
Intern  B
Joined: 22 Dec 2018
Posts: 20
WE: Medicine and Health (Health Care)
Re: 12 Easy Pieces (or not?)  [#permalink]

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Bunuel wrote:
10. If $$n$$ is an integer and $$\frac{1}{10^{n+1}}<0.00737<\frac{1}{10^n}$$, then what is the value of n?
A. 1
B. 2
C. 3
D. 4
E. 5

Also no need for algebraic manipulation. 1/10^(n+1) is 10 times less than 1/10^n, and both when expressed as decimals are of a type 0.001 (some number of zeros before 1) --> so the given expression to hold true we should have: 0.001<0.00737<0.01, which means that n=2 (1/10^n=0.01 --> n=2).

Hi Bunuel,

I am unable to understand how did we get 0.001 for 1/10^(n+1).
From what i understand 1/10^(n+1) is of form 1/10^n x 10^1.

Thanks
Math Expert V
Joined: 02 Sep 2009
Posts: 59674
Re: 12 Easy Pieces (or not?)  [#permalink]

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1
swatjazz wrote:
Bunuel wrote:
10. If $$n$$ is an integer and $$\frac{1}{10^{n+1}}<0.00737<\frac{1}{10^n}$$, then what is the value of n?
A. 1
B. 2
C. 3
D. 4
E. 5

Also no need for algebraic manipulation. 1/10^(n+1) is 10 times less than 1/10^n, and both when expressed as decimals are of a type 0.001 (some number of zeros before 1) --> so the given expression to hold true we should have: 0.001<0.00737<0.01, which means that n=2 (1/10^n=0.01 --> n=2).

Hi Bunuel,

I am unable to understand how did we get 0.001 for 1/10^(n+1).
From what i understand 1/10^(n+1) is of form 1/10^n x 10^1.

Thanks

1/10^1 = 0.1
1/10^2 = 0.01
1/10^3 = 0.001
...

Thus, both 1/10^(n+1) and 1/10^n when expressed as decimals are of a type 0.001 (some number of zeros before 1). So, not that both are equal to 0.001 but both will be 0. followed by some number of zeros before 1.
_________________
Intern  B
Joined: 22 Dec 2018
Posts: 20
WE: Medicine and Health (Health Care)
Re: 12 Easy Pieces (or not?)  [#permalink]

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Bunuel wrote:
swatjazz wrote:
Bunuel wrote:
10. If $$n$$ is an integer and $$\frac{1}{10^{n+1}}<0.00737<\frac{1}{10^n}$$, then what is the value of n?
A. 1
B. 2
C. 3
D. 4
E. 5

Also no need for algebraic manipulation. 1/10^(n+1) is 10 times less than 1/10^n, and both when expressed as decimals are of a type 0.001 (some number of zeros before 1) --> so the given expression to hold true we should have: 0.001<0.00737<0.01, which means that n=2 (1/10^n=0.01 --> n=2).

Hi Bunuel,

I am unable to understand how did we get 0.001 for 1/10^(n+1).
From what i understand 1/10^(n+1) is of form 1/10^n x 10^1.

Thanks

1/10^1 = 0.1
1/10^2 = 0.01
1/10^3 = 0.001
...

Thus, both 1/10^(n+1) and 1/10^n when expressed as decimals are of a type 0.001 (some number of zeros before 1). So, not that both are equal to 0.001 but both will be 0. followed by some number of zeros before 1.

Thanks so much! It's crystal clear now. Much appreciated for quick response.
Manager  B
Joined: 27 Oct 2019
Posts: 54
12 Easy Pieces (or not?)  [#permalink]

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hmasand wrote:
Is this true tho?

The question specifically asks 1.5 hours BEFORE they meet. This would mean that (assuming they met in 4 hours. [25 x 4 = 100 + 65 x 4 = 260 TOTAL 360] The question asks about the 2.5th hour (4 hours - 1.5 hours), they would have been 100 miles apart at this juncture (25 x 2.5 = 62.50 + 65 x 2.5 = 162.5)

Bunuel wrote:
3. Fanny and Alexander are 360 miles apart and are traveling in a straight line toward each other at a constant rate of 25 mph and 65 mph respectively, how far apart will they be exactly 1.5 hours before they meet?
A. 25 miles
B. 65 miles
C. 70 miles
D. 90 miles
E. 135 miles

Make it simple! The question is: how far apart will they be exactly 1.5 hours before they meet? As Fanny and Alexander's combined rate is 25+65 mph then 1.5 hours before they meet they'll be (25+65)*1.5=135 miles apart.

This is the same doubt I have..
Bunuel can you please clarify this doubt..

Posted from my mobile device
Manager  B
Joined: 27 Oct 2019
Posts: 54
Re: 12 Easy Pieces (or not?)  [#permalink]

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Bunuel wrote:
12. If $${-\frac{1}{3}}\leq{x}\leq{-\frac{1}{5}}$$ and $${-\frac{1}{2}}\leq{y}\leq{-\frac{1}{4}}$$, what is the least value of $$x^2*y$$ possible?
A. -1/100
B. -1/50
C. -1/36
D. -1/18
E. -1/6

To get the least value of $$x^2*y$$, which obviously will be negative, try to maximize absolute value of $$x^2*y$$, as more is the absolute value of a negative number "more" negative it is (the smallest it is).

To maximize $$|x^2*y|$$ pick largest absolute values possible for $$x$$ and $$y$$: $$(-\frac{1}{3})^2*(-\frac{1}{2})=-\frac{1}{18}$$. Notice that: -1/18<-1/36<-1/50<-1/100, so -1/100 is the largest number and -1/18 is the smallest number (we cannot obtain -1/6 from x^2*y or else it would be the correct answer).

Is there any other way to do this questions??

Posted from my mobile device
Math Expert V
Joined: 02 Sep 2009
Posts: 59674
Re: 12 Easy Pieces (or not?)  [#permalink]

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ssshyam1995 wrote:
hmasand wrote:
Is this true tho?

The question specifically asks 1.5 hours BEFORE they meet. This would mean that (assuming they met in 4 hours. [25 x 4 = 100 + 65 x 4 = 260 TOTAL 360] The question asks about the 2.5th hour (4 hours - 1.5 hours), they would have been 100 miles apart at this juncture (25 x 2.5 = 62.50 + 65 x 2.5 = 162.5)

Bunuel wrote:
3. Fanny and Alexander are 360 miles apart and are traveling in a straight line toward each other at a constant rate of 25 mph and 65 mph respectively, how far apart will they be exactly 1.5 hours before they meet?
A. 25 miles
B. 65 miles
C. 70 miles
D. 90 miles
E. 135 miles

Make it simple! The question is: how far apart will they be exactly 1.5 hours before they meet? As Fanny and Alexander's combined rate is 25+65 mph then 1.5 hours before they meet they'll be (25+65)*1.5=135 miles apart.

This is the same doubt I have..
Bunuel can you please clarify this doubt..

Posted from my mobile device

I don't understand what is done there. If you want to solve this question long way, then:
1. The would meet in 360/(25 + 65) = 4 hours.
2. In 2.5 hours they together would cover 2.5*(25 + 65) = 225 miles, so 360 - 225 = 135 miles would be left to cover in the remaining 1.5 hours.
_________________ Re: 12 Easy Pieces (or not?)   [#permalink] 22 Nov 2019, 01:09

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