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3*3^(1/2)/2^(1/2)*4*3^(1/2)/3

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3*3^(1/2)/2^(1/2)*4*3^(1/2)/3  [#permalink]

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New post 13 Mar 2018, 06:52
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A
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  5% (low)

Question Stats:

88% (00:54) correct 12% (01:07) wrong based on 91 sessions

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Re: 3*3^(1/2)/2^(1/2)*4*3^(1/2)/3  [#permalink]

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New post 13 Mar 2018, 06:57
Bunuel wrote:
\(\frac{3\sqrt{3}}{\sqrt{2}}*\frac{4\sqrt{3}}{3}\)

A. 3

B. \(6\sqrt{2}\)

C. 12

D. \(12\sqrt{2}\)

E. 36


8. Exponents and Roots of Numbers



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Re: 3*3^(1/2)/2^(1/2)*4*3^(1/2)/3  [#permalink]

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New post 13 Mar 2018, 07:26
Bunuel wrote:
\(\frac{3\sqrt{3}}{\sqrt{2}}*\frac{4\sqrt{3}}{3}\)

A. 3

B. \(6\sqrt{2}\)

C. 12

D. \(12\sqrt{2}\)

E. 36


\(\frac{3√3*4√3}{3√2}\)

=\(\frac{3*3*4}{3√2}\)

=\(\frac{12}{√2}\)

=\(\frac{12√2}{√2*√2}\)

= \(6√2\),Answer must be (B)
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Re: 3*3^(1/2)/2^(1/2)*4*3^(1/2)/3  [#permalink]

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New post 14 Mar 2018, 16:02
Bunuel wrote:
\(\frac{3\sqrt{3}}{\sqrt{2}}*\frac{4\sqrt{3}}{3}\)

A. 3

B. \(6\sqrt{2}\)

C. 12

D. \(12\sqrt{2}\)

E. 36


Multiplying together the two expressions, we have:

(12 x 3)/(3√2) = 12/√2

Rationalizing the expression, we have:

(12√2)/2 = 6√2

Answer: B
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Re: 3*3^(1/2)/2^(1/2)*4*3^(1/2)/3  [#permalink]

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New post 27 Apr 2019, 05:55
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: 3*3^(1/2)/2^(1/2)*4*3^(1/2)/3   [#permalink] 27 Apr 2019, 05:55
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