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Re: a, b, c, and d lie on the number line such that a < b. [#permalink]
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Vinodhini1803 wrote:
I feel answer is C..Since
if we take a = 0, and d = x then C = 2x and b = 4x
then a-b = -4x
and c + d = 3x
answer is -4/3.
where am I going wrong

chetan2u, Kindly help



You can’t assume any values. So taking a=0 is not correct.
a could be 10, then the answer will change.
a could be 5, 100, anything.
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Re: a, b, c, and d lie on the number line such that a < b. [#permalink]
We could use the concept of ratios out here. If a/c is one ratio and if we add/sub two different constants, in this case b and d to the numerator and the denominator, we will get a different ratio. And this ratio will keep changing based on the constants we add or subtract.

Twin Question: https://gmatclub.com/forum/if-a-b-c-and ... 48920.html
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Re: a, b, c, and d lie on the number line such that a < b. [#permalink]
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I hope GMAT doesn't throw stuff like this on the exam...huge time wasters that just gets people spinning about a possible solution. It's clear there isn't any, but then self doubt creeps in and voila, I wasted 2-3 minutes.
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a, b, c, and d lie on the number line such that a < b. [#permalink]
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a, b, c, and d lie on the number line such that a<b. What is the value of (a-b)/(c+d)?

As per question
Let assume a, b= a+x (as b>a)

1. c lies exactly between a and b.
C= a+x/2,
Can not solve so not sufficient

2. d lies exactly between a and c.

d = (a+ (a+x/2))/2
d= a+x/4
So alone is not sufficient.

Combine 1 & 2..
C= a+x/2, d= a+x/4
C+d= 2a+3x/4
a-b= -x

(a-b)/(c+d)= -x/(2a+3x/4)... Can not solve further..so I sufficient

IMO E

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Re: a, b, c, and d lie on the number line such that a < b. [#permalink]
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Re: a, b, c, and d lie on the number line such that a < b. [#permalink]
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