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A baker is storing cake boxes in cartons that measure 25 inches by 42

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A baker is storing cake boxes in cartons that measure 25 inches by 42 [#permalink]

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New post 20 Nov 2014, 02:20
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A baker is storing cake boxes in cartons that measure 25 inches by 42 inches by 60 inches. If the measurement of each cake box is 8 inches by 7 inches by 5 inches, then what is the maximum number of cake boxes that can be placed in each carton?

A. 330
B. 300
C. 252
D. 225
E. 210
[Reveal] Spoiler: OA

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Re: A baker is storing cake boxes in cartons that measure 25 inches by 42 [#permalink]

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New post 20 Nov 2014, 07:31
PareshGmat wrote:
A baker is storing cake boxes in cartons that measure 25 inches by 42 inches by 60 inches. If the measurement of each cake box is 8 inches by 7 inches by 5 inches, then what is the maximum number of cake boxes that can be placed in each carton?

A. 330
B. 300
C. 252
D. 225
E. 210


Similar question to practice: a-grocer-is-storing-soap-boxes-in-cartons-that-measure-150337.html
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Re: A baker is storing cake boxes in cartons that measure 25 inches by 42 [#permalink]

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New post 20 Nov 2014, 08:26
IMO, the answer should be D, 225.

Volume of carton = 25*42*60 = 63,000
Volume of one box = 5*7*8 = 280

Maximum number of boxes that can be placed in the carton = 63000/280 = 225.

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Re: A baker is storing cake boxes in cartons that measure 25 inches by 42 [#permalink]

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New post 20 Nov 2014, 18:57
gmatter24 wrote:
IMO, the answer should be D, 225.

Volume of carton = 25*42*60 = 63,000
Volume of one box = 5*7*8 = 280

Maximum number of boxes that can be placed in the carton = 63000/280 = 225.


Correct answer is E (210)

You may give a try again..... I'll post the detailed answer later

Anyone else???
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Re: A baker is storing cake boxes in cartons that measure 25 inches by 42 [#permalink]

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New post 21 Nov 2014, 03:33
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The dimensions of the carton are 25" x 42" x 60" and those of each cake box are 8" x 7" x 5".

To maximize number of boxes try and fit maximum into the base of the box. If you take the base as 25" x 42" and fit 5 x 6 boxes of 5" x 7", then the total number of boxes is 5 x 6 x integer(60/8) = 5 x 6 x 7 = 210.

Alternatively you could try taking the base as 60" x 42" and fit 12 x 6 boxes of 5" x 7", then the total number of boxes is 12 x 6 x integer(25/8) = 12 x 6 x 3 = 216. But since that is not an answer option, I go with (E) 210.
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A baker is storing cake boxes in cartons that measure 25 inches by 42 [#permalink]

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New post 23 Nov 2014, 18:55
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Answer = E = 210

\(\frac{25*42*60}{8*7*5}\)

Pair up the numerator/denominator in such a way that it gets divided completely "without adjustment"

Dimensions cannot be adjusted

\(\frac{25}{5} = 5\)

\(\frac{42}{7} = 6\)

\(\frac{60}{8}\) >> This will go maximum to 7 (Leave the decimal value; That space is wasted)

Answer = 7*6*5 = 210
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Re: A baker is storing cake boxes in cartons that measure 25 inches by 42 [#permalink]

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New post 25 Nov 2014, 23:55
Divide 25/5 to get 5. Well that is one dimension dealt with.
Divide 42/ 7 to get 6. another dimension dealt with.
Divide the greatest number under 60 by 8(i mean to get an integer). that would be 56. 56/8=7.
So 7*5*6= 210. E

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Re: A baker is storing cake boxes in cartons that measure 25 inches by 42 [#permalink]

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New post 24 Jan 2015, 14:19
Could you pls explain the reason in adopting a different trick in dealing with this question then the simple one posted in a-grocer-is-storing-soap-boxes-in-cartons-that-measure-150337.html. what is the thing to look for in dealing with these question because on first look both the questions look of the same type...

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Re: A baker is storing cake boxes in cartons that measure 25 inches by 42 [#permalink]

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New post 24 Jan 2015, 19:15
Hi jhasac,

If you've ever received a package or sent a package that was not completely filled (so extra packaging was included to keep the items in the box from shifting around), then you've experienced what these types of questions are ultimately about: "empty" space.

Since this question asks us to MAXIMIZE the number of boxes that we can put in a carton, we have to think about how to maximize the space given the dimensions of the carton and the dimensions of the boxes that we're going to put into it. Thus, we have to think about MORE than just the volumes. Often, one or more of the wrong answers is based on a conceptual math mistake that might be made, so it's important to take the necessary notes (drawing pictures sometimes helps too) and PROVE that your answer is the correct one.

Here, the issue is about "orienting" the boxes so that we can fill as much of the carton as possible (and minimize the "empty" space.

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Re: A baker is storing cake boxes in cartons that measure 25 inches by 42 [#permalink]

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Re: A baker is storing cake boxes in cartons that measure 25 inches by 42 [#permalink]

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New post 08 Sep 2017, 05:19
ANSWER IS E = 210

L=25 B= 42 H=60 OF CARDBOARD

CAKE BOX = L=5 B=7 H=8

CONSIDER CARDBOARD LxB , 25/5 = 5 BOXES CAN COME LENGTH WISE AND 42/7 = 6 CAN COME BREADTH WISE => I TIER =30 BOXES

TOTAL HEIGHT OF CARDBOARD = 60 AND OF BOX =8 SO 60/8 = 7.5 TIER CAN COME

WE CANT CUT BOX SO WE TAKE ONLY 7 TIERS

1 TIER = 30 BOXES
7 TIER = 210 BOXES => OPTION E
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A baker is storing cake boxes in cartons that measure 25 inches by 42 [#permalink]

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New post 17 Oct 2017, 07:58
PareshGmat wrote:
Answer = E = 210

\(\frac{25*42*60}{8*7*5}\)

Pair up the numerator/denominator in such a way that it gets divided completely "without adjustment"

Dimensions cannot be adjusted

\(\frac{25}{5} = 5\)

\(\frac{42}{7} = 6\)

\(\frac{60}{8}\) >> This will go maximum to 7 (Leave the decimal value; That space is wasted)

Answer = 7*6*5 = 210


hi

how to pair ...?

I am stumped when paired as under...

60/5 = 12

42/7 = 6

25/8 = 3

thus, 12 * 6* 3 = 216 :?

please help me resolve this ...

anyway, is this as such that, information, given in the question, is ALWAYS in the format: "Lenght Base Height"....?

thanks in advance ...

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