Zarrolou wrote:
deepri0812 wrote:
A grocer is storing soap boxes in cartons that measure 25 inches by 42 inches by 60 inches. If the measurement of each soap box is 7 inches by 6 inches by 5 inches, then what is the maximum number of soap boxes that can be placed in each carton?
A -210
B - 252
C - 280
D -300
E-420
Area of the box = \(25*42*60=63000\)
Area of one soap = \(7*6*5=210\)
Tot number = \(\frac{63000}{210}=300\)
You have to calculate the area of the box, then divide it by the area of one soap, and you ll find the number of soaps that will fit into the box
D
Thanks Zarrolou for quick reply.
I am getting confused between volume approach as done by you and my thought process:
Think about lining up the dimensions of the small boxes along the dimensions of the carton so that you can fill the carton with no wasted space. Since one edge of the small box is 7 inches, that edge of the small boxes should be placed along the side of the carton that is 42 inches long, since 42 is the only dimension that can be divided by 7 evenly. Thus you can put six small boxes along that side, but if you do that 6*6 soap boxes will have width 36 which would be greater than 25 & will exceed the carton width. so how can we just divide the volume of the carton & the soap's volume.
Or am I thinking too much
??