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A car drives 40 miles on local roads at 20 mph, and 180 miles on the h

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A car drives 40 miles on local roads at 20 mph, and 180 miles on the h  [#permalink]

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New post 24 Feb 2015, 06:44
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A car drives 40 miles on local roads at 20 mph, and 180 miles on the highway at 60 mph, what is the average speed of the entire trip?

A. 36 mph
B. 40 mph
C. 44 mph
D. 52 mph
E. 58 mph

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Re: A car drives 40 miles on local roads at 20 mph, and 180 miles on the h  [#permalink]

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New post 24 Feb 2015, 07:32
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40 miles at 20 mph takes 2 hours
180 miles at 60 mph takes 3 hours

Average speed = Total distance / Total time
= (40 + 180) / (2 + 3)
= 220 / 5
= 44

The correct answer is C.
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Re: A car drives 40 miles on local roads at 20 mph, and 180 miles on the h  [#permalink]

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New post 24 Feb 2015, 13:07
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So The Answer is Plainly C....

we have a general relation for speed , time and distance : v (velocity) * t ( time)= d (distance)

for first part we have d=40 miles , and v= 20 mph so we can obtain time : 20*t = 40 Or t= 40/20 = 2 hours the needed time to cover 40 miles

in the same way we should divide 180 to 60 to find the needed time to cover 180 miles ,so t= 3 hours

so the total time for covering total distance would be 3+2 = 5 hours and total distance is 40+180= 220 miles

Final stage : average speed is total distance divide to total time : 220/5 = 44 miles per hour....
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A car drives 40 miles on local roads at 20 mph, and 180 miles on the h  [#permalink]

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New post 24 Feb 2015, 18:51
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Answer = C. 44 mph

Average speed \(= \frac{Total distance}{Total time} = \frac{40+180}{\frac{40}{20} + \frac{180}{60}} = \frac{220}{5} = 44\)
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Re: A car drives 40 miles on local roads at 20 mph, and 180 miles on the h  [#permalink]

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New post 02 Mar 2015, 04:19
Bunuel wrote:
A car drives 40 miles on local roads at 20 mph, and 180 miles on the highway at 60 mph, what is the average speed of the entire trip?

A. 36 mph
B. 40 mph
C. 44 mph
D. 52 mph
E. 58 mph

Kudos for a correct solution.


MAGOOSH OFFICIAL SOLUTION:

In phase #1 of the trip, the car traveled 40 mi at 20 mph. That time of this phase was:
time = distance/rate = (40 mi)/(20 mph) = 2 hr

In phase #2 of the trip, the car traveled 180 mi at 60 mph. That time of this phase was:
time = distance/rate = (180 mi)/(60 mph) = 3 hr

The total distance of the trip = 40 mi + 180 mi = 220 mi
The total time of the trip = 2 hr + 3 hr = 5 hr
The average speed of trip is given by
speed = distance/time = (220 mi)/(5 hr) = 44 mph

Answer: C.
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Collection of Questions:
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Re: A car drives 40 miles on local roads at 20 mph, and 180 miles on the h  [#permalink]

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New post 19 Apr 2016, 13:25
Average Speed = (Total Distance traveled) / (Total Time taken)

Total Distance = 40 +180 = 220 miles
Total Time = (40/20) +(180/60) = 2 + 3 = 5 hours

Average Speed = 220 /5 = 44 mph
Correct Option : C
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Re: A car drives 40 miles on local roads at 20 mph, and 180 miles on the h  [#permalink]

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New post 07 Sep 2018, 06:22
Average time = Total distance/Total time taken.

Average time = 220/5 = 44

C is the answer

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Re: A car drives 40 miles on local roads at 20 mph, and 180 miles on the h  [#permalink]

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New post 07 Sep 2018, 06:24
Bunuel wrote:
A car drives 40 miles on local roads at 20 mph, and 180 miles on the highway at 60 mph, what is the average speed of the entire trip?

A. 36 mph
B. 40 mph
C. 44 mph
D. 52 mph
E. 58 mph

Kudos for a correct solution.


Time taken for first \(40\) miles is \frac{40}{20} = \(2\) Hours
Time taken for next \(180\) miles is \frac{180}{50} = \(3\) Hours

So, For travelling 220 miles time taken is 5 Hours.

So, Avg Speed is \(\frac{220}{5} = 44 \ mph\), Answer must be (C)
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Re: A car drives 40 miles on local roads at 20 mph, and 180 miles on the h &nbs [#permalink] 07 Sep 2018, 06:24
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