Bunuel wrote:
A full bottle contains 40% oil, 20% vinegar, and 40% water. The bottle is poured into a larger bottle, four times as big as original. The remaining space in the larger bottle is then filled with water. If there was 8 ml of oil in the original bottle, how much of water is in the final mixture?
A. 8 ml
B. 20 ml
C. 60 ml
D. 68 ml
E. 80 ml
Given:
Let the smaller bottle size be, x ml
Then Larger bottle size = 4x ml
Oil in smaller bottle = 8 ml = 40%
This tells us that 1ml of any solution is equal to 5%, 1ml = 5%
Therefore: Smaller bottle capacity = water+oil+vinegar = 40%+40%+20% = 8ml+8ml+4ml = 20 ml
Larger bottle capacity = 4*20ml = 80ml
Given: The remaining space in the larger bottle is then filled with water = 80ml - 20ml = 60ml of water
Water already present in the bottle = 8ml + 60ml = 68ml in mixture
Hence D is the answer
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