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A full bottle contains 40% oil, 20% vinegar, and 40% water. The bottle

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A full bottle contains 40% oil, 20% vinegar, and 40% water. The bottle  [#permalink]

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New post 22 Jul 2018, 23:05
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Question Stats:

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A full bottle contains 40% oil, 20% vinegar, and 40% water. The bottle is poured into a larger bottle, four times as big as original. The remaining space in the larger bottle is then filled with water. If there was 8 ml of oil in the original bottle, how much of water is in the final mixture?

A. 8 ml
B. 20 ml
C. 60 ml
D. 68 ml
E. 80 ml

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Re: A full bottle contains 40% oil, 20% vinegar, and 40% water. The bottle  [#permalink]

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New post 22 Jul 2018, 23:13
1
Bunuel wrote:
A full bottle contains 40% oil, 20% vinegar, and 40% water. The bottle is poured into a larger bottle, four times as big as original. The remaining space in the larger bottle is then filled with water. If there was 8 ml of oil in the original bottle, how much of water is in the final mixture?

A. 8 ml
B. 20 ml
C. 60 ml
D. 68 ml
E. 80 ml



Step 1 : oil in original bottle 40% = 8ml
Therefore original bottle capacity = 20ml
Step 2 : Volume of other 2 (vinegar and water ) in mix
Water = oil =8
Vinegar = 12 (this is not required)
Step 3 : volume of big bottle = 4* original bottle = 4*20 = 80

Step 4: Remaining volume = 80- original bottle mix poured = 80 -20 =60 (water poured)
Step 5 : Water poured + water in original mix = 60+8 = 68 ml
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A full bottle contains 40% oil, 20% vinegar, and 40% water. The bottle  [#permalink]

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New post 22 Jul 2018, 23:17
1
Bunuel wrote:
A full bottle contains 40% oil, 20% vinegar, and 40% water. The bottle is poured into a larger bottle, four times as big as original. The remaining space in the larger bottle is then filled with water. If there was 8 ml of oil in the original bottle, how much of water is in the final mixture?

A. 8 ml
B. 20 ml
C. 60 ml
D. 68 ml
E. 80 ml


Given:
Let the smaller bottle size be, x ml
Then Larger bottle size = 4x ml
Oil in smaller bottle = 8 ml = 40%
This tells us that 1ml of any solution is equal to 5%, 1ml = 5%

Therefore: Smaller bottle capacity = water+oil+vinegar = 40%+40%+20% = 8ml+8ml+4ml = 20 ml
Larger bottle capacity = 4*20ml = 80ml

Given: The remaining space in the larger bottle is then filled with water = 80ml - 20ml = 60ml of water
Water already present in the bottle = 8ml + 60ml = 68ml in mixture
Hence D is the answer


Please give kudos if you like the explanation :)
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Re: A full bottle contains 40% oil, 20% vinegar, and 40% water. The bottle  [#permalink]

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New post 23 Jul 2018, 04:39
1
Bunuel wrote:
A full bottle contains 40% oil, 20% vinegar, and 40% water. The bottle is poured into a larger bottle, four times as big as original. The remaining space in the larger bottle is then filled with water. If there was 8 ml of oil in the original bottle, how much of water is in the final mixture?

A. 8 ml
B. 20 ml
C. 60 ml
D. 68 ml
E. 80 ml


Let x be the size of original bottle
1. Ratio of oil, vinegar and water are in 2:1:2.
2. Given: 8 ml of oil in original bottle.
So,
2/5 * x = 8, which gives x=20
3. Given: Larger bottle = 4 * original bottle
i.e Larger bottle = 4 * x = 4 * 20 = 80

So, 20 ml poured in 80 ml of bottle. That leaves 80-20 = 60 ml remaining
Given, remaining space in the larger bottle is then filled with water

i.e. 60 ml filled in large bottle with water.

Question asked is: water in final mixture, which is 8 ml(as poured from original bottle previously) + 60 ml (highlighted above)
Equals 68 - option (D)

Please let me know, if this is correct ! Kindly publish the answer asap
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Re: A full bottle contains 40% oil, 20% vinegar, and 40% water. The bottle  [#permalink]

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New post 23 Jul 2018, 20:03
I am getting a D.

Following is my approach :
Let the volume of the bottle be X ml;
Oil (40%) = 8ml, we get 40x/100 =8; x = 20ml
Water (40%) would be 8 ml -------(i)

four times size of the bottle would be 4x = 4 * 20 =80 ml.
Space remaining after pouring 20 ml = 80 - 20 =60ml-----(ii)

Adding (i) and (ii);
60 + 8 = 68ml.


Please kudo if that helped.

looking forward to a faster approach though.
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Re: A full bottle contains 40% oil, 20% vinegar, and 40% water. The bottle  [#permalink]

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New post 18 Aug 2018, 08:51
Please see attached file below
The correct answer is (D) 68 ml.
Attachments

Bottle x and 4x.png
Bottle x and 4x.png [ 31.65 KiB | Viewed 848 times ]

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Re: A full bottle contains 40% oil, 20% vinegar, and 40% water. The bottle  [#permalink]

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New post 22 Oct 2018, 08:47
Bunuel wrote:
A full bottle contains 40% oil, 20% vinegar, and 40% water. The bottle is poured into a larger bottle, four times as big as original. The remaining space in the larger bottle is then filled with water. If there was 8 ml of oil in the original bottle, how much of water is in the final mixture?

A. 8 ml
B. 20 ml
C. 60 ml
D. 68 ml
E. 80 ml


Oil:Vinegar:water:total

4:2:4:10

4x = 8 , x = 2

then the ratios will be 8:4:8:20

Since the larger bottle is 4 times it will 20*4 = 80

80 - 20 = 60 water that needs to be added.

Previously there was 8 ml water and now we added 60 to fill the remaining so 60 + 8 = 68

Answer choice D
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Re: A full bottle contains 40% oil, 20% vinegar, and 40% water. The bottle &nbs [#permalink] 22 Oct 2018, 08:47
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