Bunuel wrote:

A full bottle contains 40% oil, 20% vinegar, and 40% water. The bottle is poured into a larger bottle, four times as big as original. The remaining space in the larger bottle is then filled with water. If there was 8 ml of oil in the original bottle, how much of water is in the final mixture?

A. 8 ml

B. 20 ml

C. 60 ml

D. 68 ml

E. 80 ml

Given:

Let the smaller bottle size be, x ml

Then Larger bottle size = 4x ml

Oil in smaller bottle = 8 ml = 40%

This tells us that 1ml of any solution is equal to 5%, 1ml = 5%

Therefore: Smaller bottle capacity = water+oil+vinegar = 40%+40%+20% = 8ml+8ml+4ml = 20 ml

Larger bottle capacity = 4*20ml = 80ml

Given: The remaining space in the larger bottle is then filled with water = 80ml - 20ml = 60ml of water

Water already present in the bottle = 8ml + 60ml = 68ml in mixture

Hence D is the answer

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