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Math Expert
Joined: 02 Sep 2009
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A full bottle contains 40% oil, 20% vinegar, and 40% water. The bottle
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23 Jul 2018, 00:05
Question Stats:
74% (01:52) correct 26% (01:37) wrong based on 223 sessions
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A full bottle contains 40% oil, 20% vinegar, and 40% water. The bottle is poured into a larger bottle, four times as big as original. The remaining space in the larger bottle is then filled with water. If there was 8 ml of oil in the original bottle, how much of water is in the final mixture? A. 8 ml B. 20 ml C. 60 ml D. 68 ml E. 80 ml
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Joined: 28 Jun 2018
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Re: A full bottle contains 40% oil, 20% vinegar, and 40% water. The bottle
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23 Jul 2018, 00:13
Bunuel wrote: A full bottle contains 40% oil, 20% vinegar, and 40% water. The bottle is poured into a larger bottle, four times as big as original. The remaining space in the larger bottle is then filled with water. If there was 8 ml of oil in the original bottle, how much of water is in the final mixture?
A. 8 ml B. 20 ml C. 60 ml D. 68 ml E. 80 ml Step 1 : oil in original bottle 40% = 8ml Therefore original bottle capacity = 20ml Step 2 : Volume of other 2 (vinegar and water ) in mix Water = oil =8 Vinegar = 12 (this is not required) Step 3 : volume of big bottle = 4* original bottle = 4*20 = 80 Step 4: Remaining volume = 80 original bottle mix poured = 80 20 =60 (water poured) Step 5 : Water poured + water in original mix = 60+8 = 68 ml
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A full bottle contains 40% oil, 20% vinegar, and 40% water. The bottle
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23 Jul 2018, 00:17
Bunuel wrote: A full bottle contains 40% oil, 20% vinegar, and 40% water. The bottle is poured into a larger bottle, four times as big as original. The remaining space in the larger bottle is then filled with water. If there was 8 ml of oil in the original bottle, how much of water is in the final mixture?
A. 8 ml B. 20 ml C. 60 ml D. 68 ml E. 80 ml Given: Let the smaller bottle size be, x ml Then Larger bottle size = 4x ml Oil in smaller bottle = 8 ml = 40% This tells us that 1ml of any solution is equal to 5%, 1ml = 5% Therefore: Smaller bottle capacity = water+oil+vinegar = 40%+40%+20% = 8ml+8ml+4ml = 20 ml Larger bottle capacity = 4*20ml = 80ml Given: The remaining space in the larger bottle is then filled with water = 80ml  20ml = 60ml of water Water already present in the bottle = 8ml + 60ml = 68ml in mixture Hence D is the answer Please give kudos if you like the explanation
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Joined: 18 Jun 2018
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Re: A full bottle contains 40% oil, 20% vinegar, and 40% water. The bottle
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23 Jul 2018, 05:39
Bunuel wrote: A full bottle contains 40% oil, 20% vinegar, and 40% water. The bottle is poured into a larger bottle, four times as big as original. The remaining space in the larger bottle is then filled with water. If there was 8 ml of oil in the original bottle, how much of water is in the final mixture?
A. 8 ml B. 20 ml C. 60 ml D. 68 ml E. 80 ml Let x be the size of original bottle
1. Ratio of oil, vinegar and water are in 2:1:2. 2. Given: 8 ml of oil in original bottle.So, 2/5 * x = 8, which gives x=20 3. Given: Larger bottle = 4 * original bottle i.e Larger bottle = 4 * x = 4 * 20 = 80 So, 20 ml poured in 80 ml of bottle. That leaves 8020 = 60 ml remainingGiven, remaining space in the larger bottle is then filled with water
i.e. 60 ml filled in large bottle with water. Question asked is: water in final mixture, which is 8 ml(as poured from original bottle previously) + 60 ml (highlighted above) Equals 68  option (D) Please let me know, if this is correct ! Kindly publish the answer asap



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Re: A full bottle contains 40% oil, 20% vinegar, and 40% water. The bottle
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23 Jul 2018, 21:03
I am getting a D.
Following is my approach : Let the volume of the bottle be X ml; Oil (40%) = 8ml, we get 40x/100 =8; x = 20ml Water (40%) would be 8 ml (i)
four times size of the bottle would be 4x = 4 * 20 =80 ml. Space remaining after pouring 20 ml = 80  20 =60ml(ii)
Adding (i) and (ii); 60 + 8 = 68ml.
Please kudo if that helped.
looking forward to a faster approach though.



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Re: A full bottle contains 40% oil, 20% vinegar, and 40% water. The bottle
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18 Aug 2018, 09:51
Please see attached file below The correct answer is (D) 68 ml.
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Bottle x and 4x.png [ 31.65 KiB  Viewed 1200 times ]



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Re: A full bottle contains 40% oil, 20% vinegar, and 40% water. The bottle
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22 Oct 2018, 09:47
Bunuel wrote: A full bottle contains 40% oil, 20% vinegar, and 40% water. The bottle is poured into a larger bottle, four times as big as original. The remaining space in the larger bottle is then filled with water. If there was 8 ml of oil in the original bottle, how much of water is in the final mixture?
A. 8 ml B. 20 ml C. 60 ml D. 68 ml E. 80 ml Oil:Vinegar:water:total 4:2:4:10 4x = 8 , x = 2 then the ratios will be 8:4:8:20 Since the larger bottle is 4 times it will 20*4 = 80 80  20 = 60 water that needs to be added. Previously there was 8 ml water and now we added 60 to fill the remaining so 60 + 8 = 68 Answer choice D




Re: A full bottle contains 40% oil, 20% vinegar, and 40% water. The bottle
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22 Oct 2018, 09:47






