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A right triangle has sides of length 2, 5, and x. A second right trian [#permalink]
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It is mentioned that both triangles are right-angle triangles.
Dimensions of the first triangle are 2,5,x
Then 3<x<7 is any real value in this range.
Here X could be the hypotenuse or 5 could be the hypotenuse. Those are the two values for X
If X is the hypotenuse, X = sqrt(29)
If 5 is the hypotenuse, X = sqrt(21)

Similarly for triangle two, Y = sqrt(33) or Y = sqrt(65)

In the final triangle, x,y,n, we can apply the same logic and quickly we can work out all possible values for n
n = sqrt(54), sqrt(86), sqrt(62), sqrt(94), sqrt(4), sqrt(44), sqrt(12), sqrt(36)

from this, 6 is the answer
B

Please share if there's a better way to get to the answer :).
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Re: A right triangle has sides of length 2, 5, and x. A second right trian [#permalink]
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Re: A right triangle has sides of length 2, 5, and x. A second right trian [#permalink]
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