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A shipment of 1500 heads of cabbage, each of which was approximately
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10 Feb 2011, 23:16
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75% (03:10) correct 25% (03:28) wrong based on 307 sessions
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A shipment of 1500 heads of cabbage, each of which was approximately the same size was purchased for $600.The day the shipment arrived 2/3 of the heads were sold, each at 25% above the cost per head.The following day the rest were sold at a price per head equal to 10% less than the price each head sold for the day before.what was the gross profit on this shipment? (A) $100 (B) $115 (C) $125 (D) $130 (E) $135 Total number of heads=1500 cost=600
Cost per head=1500/600=2.5 2/3(1500)=1000 cost of 1000 heads=2.5*1.25*1000=3130 cost of rest 500 heads=3(500)=1500
Gross profit =4630600=4030
But this answer is wrong.I think the method I am using is correct.
Where is the problem? Pls help
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Re: A shipment of 1500 heads of cabbage, each of which was approximately
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11 Feb 2011, 02:36
Quote: Total number of heads=1500 cost=600
Cost per head=1500/600=2.5; not correct
\(1500\quad head = \$600\) \(1 head = \frac{600}{1500}\)
2/3(1500)=1000 cost of 1000 heads=2.5*1.25*1000=3130 cost of rest 500 heads=3(500)=1500
Gross profit =4630600=4030
But this answer is wrong.I think the method I am using is correct.
Where is the problem? Pls help I recommend one should use fractions to solve this one rather than converting it into decimals Sol: 1500 heads > $600 1 head > $600/1500 1 head > $(2/5) 25% more of (2/5) > 125/100 * 2/5 = $(1/2) He sold 2/3*1500 = 1000 heads for $(1/2) per head Total revenue by selling 1000 heads = 1000 * 1/2 = $500 Heads left: 500 Cost per head: 90% of the previous price: 90/100 * 1/2 = $(9/20) Total revenue by selling 500 heads = 9/20 * 500 = 225 Total revenue after selling 1500 cabbage heads  225+500 = $725 Money spent on the purchase: $600 Profit = 725600 = $125 Ans: "C"
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Re: A shipment of 1500 heads of cabbage, each of which was approximately
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12 Feb 2011, 13:23
fluke wrote: Quote: Total number of heads=1500 cost=600
Cost per head=1500/600=2.5; not correct
\(1500\quad head = \$600\) \(1 head = \frac{600}{1500}\)
2/3(1500)=1000 cost of 1000 heads=2.5*1.25*1000=3130 cost of rest 500 heads=3(500)=1500
Gross profit =4630600=4030
But this answer is wrong.I think the method I am using is correct.
Where is the problem? Pls help I recommend one should use fractions to solve this one rather than converting it into decimals Sol: 1500 heads > $600 1 head > $600/1500 1 head > $(2/5) 25% more of (2/5) > 125/100 * 2/5 = $(1/2) He sold 2/3*1500 = 1000 heads for $(1/2) per head Total revenue by selling 1000 heads = 1000 * 1/2 = $500 Heads left: 500 Cost per head: 90% of the previous price: 90/100 * 1/2 = $(9/20) Total revenue by selling 500 heads = 9/20 * 500 = 225 Total revenue after selling 1500 cabbage heads  225+500 = $725 Money spent on the purchase: $600 Profit = 725600 = $125 Ans: "C" Thanks I was wrong while calculating cost per head
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Re: A shipment of 1500 heads of cabbage, each of which was approximately
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13 Feb 2011, 04:29
1.25 * 2/3 * 1500 * 600/1500  Day 1 Total SP 0.9 * 1.25 * 1/3 * 1500 * 600/1500  Day 2 total SP => Total SP = 600/1500 * 1500 * 1.25 (2/3 + 0.9 * 1/3) = 600 * 5/4 * (2 + 0.9)/3 = 3000 * 2.9/12 = 725 => Profit = 725  600 = $ 125
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Re: A shipment of 1500 heads of cabbage, each of which was approximately
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29 Apr 2015, 12:11
This sol might help, its faster if we solve this way , might save you some time Prob:Total number of heads=1500 Cost Price =$600 Sale Price = 2/3 sold at 25% profit & 1/3 sold at price (10% less than the price each head sold for the day before) Sol: will calculate these in bulks only (will try not to go down to single level)2/3 of 1500 ~ 1000 > sold on day 1 1/3 of 1500 ~ 500 > sold on day 2
Day 1: Sale price of 2/3 sold at 25% profit = 1000 * 600/1500 * 125/100 = $500 ~~now 1000 heads sold at $500, with the same price could have sold remaining 500 heads for = $500/2 = $250* Day 2:Sale price of 1/3 (=500 heads) sold at 10% less than previous day price, that's 10% less of $250 = $225 (90% of $250)Total sale price (Day1 + Day2) = $500 + $225 = $725 Profit = SP  CP = $725  $600 = $125Ans C
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Re: A shipment of 1500 heads of cabbage, each of which was approximately
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25 May 2017, 15:57
Quote: A shipment of 1500 heads of cabbage, each of which was approximately the same size was purchased for $600.The day the shipment arrived 2/3 of the heads were sold, each at 25% above the cost per head.The following day the rest were sold at a price per head equal to 10% less than the price each head sold for the day before.what was the gross profit on this shipment?
a) $100 b) $115 c) $125 d) $130 e) $135 We are given that a shipment of 1500 heads of cabbage costs 600 dollars, or 600/1500 = $0.40 per cabbage. We are given that 2/3 x 1500 = 1,000 heads of cabbage sold for 1.25 x $0.40 = $0.50. So, a total of 1,000 x $0.50 = $500 was made on the sale of those heads of cabbage. The next day, 500 heads of cabbage were sold at a price of 0.9 x $0.50 = $0.45, so a total of 500 x $0.45 = $225 dollars was made on the sale of those heads. Thus, a total of 500 + 225 = $725 was made. Thus, profit = 725  600 = $125. Answer: C
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Re: A shipment of 1500 heads of cabbage, each of which was approximately
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Updated on: 10 Jun 2017, 00:15
GMATD11 wrote: A shipment of 1500 heads of cabbage, each of which was approximately the same size was purchased for $600.The day the shipment arrived 2/3 of the heads were sold, each at 25% above the cost per head.The following day the rest were sold at a price per head equal to 10% less than the price each head sold for the day before.what was the gross profit on this shipment? a) $100 b) $115 c) $125 d) $130 e) $135 Total number of heads=1500 cost=600
Cost per head=1500/600=2.5 2/3(1500)=1000 cost of 1000 heads=2.5*1.25*1000=3130 cost of rest 500 heads=3(500)=1500
Gross profit =4630600=4030
But this answer is wrong.I think the method I am using is correct.
Where is the problem? Pls help Profit per unit works well with these numbers. (Profit per item) * (# items) = gross profit Cost per cabbage is $600 for 1500 heads = 40¢ per head Sell Price A is 25% above cost: 40¢ * 1.25 = 50¢. Profit per head for price A = 10¢ = .10Sell Price B is 10% less than Sell Price A: 50¢ *.90 = 45¢. Profit per head for price B = 5¢ = .05Number of items at price A = 2/3 of 1,500 = 1,000 Number of items at price B = 1/3 of 1,500 = 500 1,000 * .10 = $100 500 * .05 = $25 Gross profit = 100 + 25 = $125 Answer C
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Originally posted by generis on 09 Jun 2017, 21:15.
Last edited by generis on 10 Jun 2017, 00:15, edited 1 time in total.



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Re: A shipment of 1500 heads of cabbage, each of which was approximately
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09 Jun 2017, 23:33
genxer123 wrote: GMATD11 wrote: A shipment of 1500 heads of cabbage, each of which was approximately the same size was purchased for $600.The day the shipment arrived 2/3 of the heads were sold, each at 25% above the cost per head.The following day the rest were sold at a price per head equal to 10% less than the price each head sold for the day before.what was the gross profit on this shipment? a) $100 b) $115 c) $125 d) $130 e) $135 Total number of heads=1500 cost=600
Cost per head=1500/600=2.5 2/3(1500)=1000 cost of 1000 heads=2.5*1.25*1000=3130 cost of rest 500 heads=3(500)=1500
Gross profit =4630600=4030
But this answer is wrong.I think the method I am using is correct.
Where is the problem? Pls help Profit per unit works well with these numbers. (Profit per item) * (# items) = gross profit Cost per cabbage is $600 for 1500 heads = 40¢ per head Sell Price A is 10% above cost: 40¢ * 1.1 = 50¢. Profit per head for price A = 10¢ = .10Sell Price B is 10% less than Sell Price A: 50¢ *.90 = 45¢. Profit per head for price B = 5¢ = .05Number of items at price A = 2/3 of 1,500 = 1,000 Number of items at price B = 1/3 of 1,500 = 500 1,000 * .10 = $100 500 * .05 = $25 Gross profit = 100 + 25 = $125 Answer C The rest of your calculations are correct. But its 40 * 1.25 = 50(because its 25% more than the cost) Please make the necessary change!
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Re: A shipment of 1500 heads of cabbage, each of which was approximately
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10 Jun 2017, 00:19
pushpitkc wrote: The rest of your calculations are correct. But its 40 * 1.25 = 50(because its 25% more than the cost)
Please make the necessary change!
Thanks for catching my typo! Edited.
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Re: A shipment of 1500 heads of cabbage, each of which was approximately
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08 Apr 2018, 05:24
GMATD11 wrote: A shipment of 1500 heads of cabbage, each of which was approximately the same size was purchased for $600.The day the shipment arrived 2/3 of the heads were sold, each at 25% above the cost per head.The following day the rest were sold at a price per head equal to 10% less than the price each head sold for the day before.what was the gross profit on this shipment?
(A) $100 (B) $115 (C) $125 (D) $130 (E) $135
hello highly intellectally smart people please help a passionate problem solver here is my solution which is wrong, but i dont understand why its wrong:) why why why total number of gabbage 1500 original cost per gabbage \(600/1500\) = 0.30 cents 2/3 of gabbage sold at 0.25 % more than it was bought > 0.30*1.25 = 37.5 (profit of 2/3 of gabbage sold 7,5 * 1000 = 7500 >7500/100 = 75 rest of gabbage is sold at 10 % less than day before > 37.5 * 0.1 = 3.75 > 37,53,75 = 33.75 so profit 3.75*500 =1875 > 1875/100 = 18.75 total profit 75+18,75 = 93.75 why



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A shipment of 1500 heads of cabbage, each of which was approximately
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08 Apr 2018, 10:51
dave13 wrote: GMATD11 wrote: A shipment of 1500 heads of cabbage, each of which was approximately the same size was purchased for $600.The day the shipment arrived 2/3 of the heads were sold, each at 25% above the cost per head.The following day the rest were sold at a price per head equal to 10% less than the price each head sold for the day before.what was the gross profit on this shipment?
(A) $100 (B) $115 (C) $125 (D) $130 (E) $135
hello highly intellectally smart people please help a passionate problem solver here is my solution which is wrong, but i dont understand why its wrong:) why why why total number of gabbage 1500 original cost per gabbage \(600/1500\) = 0.30 cents 2/3 of gabbage sold at 0.25 % more than it was bought > 0.30*1.25 = 37.5 (profit of 2/3 of gabbage sold 7,5 * 1000 = 7500 >7500/100 = 75 rest of gabbage is sold at 10 % less than day before > 37.5 * 0.1 = 3.75 > 37,53,75 = 33.75 so profit 3.75*500 =1875 > 1875/100 = 18.75 total profit 75+18,75 = 93.75 why Hi dave13 , you are indeed a passionate problem solver, which is admirable. It looks to me as if you mostly understand how to solve the problem. You have a couple of arithmetic mistakes. Quote: original cost per gabbage \(600/1500\) = 0.30 cents Try that arithmetic again. Quote: rest of gabbage is sold at 10 % less than day before > 37.5 * 0.1 = 3.75 Whoops. 10 % LESS than means 90 percent OF (1  .10) = .90 Not onetenth X percent less = (1  Xpercent) See below for links on GMAT and percents If you get stuck trying to decide what "10% less than" means, take a simple example. A cake cost $100 Next day it is on sale for10% LESS than before Did the cake cost $10? No. (1.00  .10) = .90 The cake sold for .90 * $100 = $90 Finally, I don't understand this part Quote: 37.5 (profit of 2/3 of gabbage sold 7,5 * 1000 = 7500 >7500/100 = 75 37.5 CENTS (wrong number, but that's not the point) = .375 DOLLARS Total revenue on 1,000 = (.375 * 1,000) = $375 ??? I think? Am I missing something? Try again? You'll get it. See mikemcgarry Percents on the GMAT And more on GMAT percents HERE: "For example, the multiplier for a 40% increase would be: 1 + 0.40 = 1.4, and the multiplier for a 40% decrease would be 1 – 0.40 = 0.6 . . ."
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Re: A shipment of 1500 heads of cabbage, each of which was approximately
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08 Apr 2018, 11:02
GMATD11 wrote: A shipment of 1500 heads of cabbage, each of which was approximately the same size was purchased for $600.The day the shipment arrived 2/3 of the heads were sold, each at 25% above the cost per head.The following day the rest were sold at a price per head equal to 10% less than the price each head sold for the day before.what was the gross profit on this shipment? (A) $100 (B) $115 (C) $125 (D) $130 (E) $135 Total number of heads=1500 cost=600
Cost per head=1500/600=2.5 2/3(1500)=1000 cost of 1000 heads=2.5*1.25*1000=3130 cost of rest 500 heads=3(500)=1500
Gross profit =4630600=4030
But this answer is wrong.I think the method I am using is correct.
Where is the problem? Pls help Cost per cabbage = $600/1500 = $0.40 1000 cabbages sold for 25% above cost on day 1: profit on day 1 = 1000*0.25*0.40 = 100 500 cabbages sold for 10% less than day before on day 2: profit on day 2 = 500*(0.50*0.90  0.40) = 500*(0.05) = 25 Profit = 100 + 25 = 125
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Re: A shipment of 1500 heads of cabbage, each of which was approximately
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21 Aug 2019, 03:02
Solutions as presented above are too timeconsuming.
profit = revenuecost 100 = 5/4*400400 25 = 5/4*9/10*200200
100+25 = 125




Re: A shipment of 1500 heads of cabbage, each of which was approximately
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