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# A student draws 35 lines in the XY plane, none of which are vertical

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Manager
Joined: 20 Feb 2017
Posts: 164
Location: India
Concentration: Operations, Strategy
WE: Engineering (Other)
A student draws 35 lines in the XY plane, none of which are vertical  [#permalink]

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09 Jul 2018, 02:29
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45% (medium)

Question Stats:

64% (02:32) correct 36% (01:59) wrong based on 115 sessions

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A student draws 35 lines in the XY plane, none of which are vertical and 15 of which have a positive slope. Of those with positive slope, 1/3 also have a positive Y-intercept. If 23 lines have a Y-intercept less than or equal to zero, how many lines contain no point in Quadrant I?
A: 0
B: 7
C: 13
D: 20
E: 35

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A student draws 35 lines in the XY plane, none of which are vertical  [#permalink]

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09 Jul 2018, 02:56
2
3
Raksat wrote:
A student draws 35 lines in the XY plane, none of which are vertical and 15 of which have a positive slope. Of those with positive slope, 1/3 also have a positive Y-intercept. If 23 lines have a Y-intercept less than or equal to zero, how many lines contain no point in Quadrant I?
A: 0
B: 7
C: 13
D: 20
E: 35

Hi...
35 lines..
15 positive slope that if x increases y increases and vice versa..
So 1/3 have a positive y intercept, so remaining 2/3 or 10 have negative y intercept or y is 0
But total 23 have negative or zero y intercept, so 23-10=13 of these have negative slope..
So these 13 will never cross the quad I

Ans 13
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A student draws 35 lines in the XY plane, none of which are vertical  [#permalink]

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09 Jul 2018, 03:02
chetan2u wrote:

So 1/3 have a positive y intercept, so remaining 2/3 or 10 have negative y intercept..

Ans 13

chetan2u

Shouldn't the remaining 10 lines have zero or negative y-intercept ? The final answer doesn't change anyway.
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Re: A student draws 35 lines in the XY plane, none of which are vertical  [#permalink]

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09 Jul 2018, 03:07
workout wrote:
chetan2u wrote:

So 1/3 have a positive y intercept, so remaining 2/3 or 10 have negative y intercept..

Ans 13

chetan2u

Shouldn't the remaining 10 lines have zero or negative y-intercept ? The final answer doesn't change anyway.

Yes , it will be 0 or negative...
You are correct. Doesn't effect the answer so didn't mention it.
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2)Combination of similar and dissimilar things : http://gmatclub.com/forum/topic215915.html
3) effects of arithmetic operations : https://gmatclub.com/forum/effects-of-arithmetic-operations-on-fractions-269413.html

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Re: A student draws 35 lines in the XY plane, none of which are vertical  [#permalink]

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09 Jul 2018, 10:45
2
Raksat wrote:
A student draws 35 lines in the XY plane, none of which are vertical and 15 of which have a positive slope. Of those with positive slope, 1/3 also have a positive Y-intercept. If 23 lines have a Y-intercept less than or equal to zero, how many lines contain no point in Quadrant I?
A: 0
B: 7
C: 13
D: 20
E: 35

There are 8 categories of lines

(i) positive slope, positive y-intercept - x

(ii) positive slope, passing through origin - y

(iii) positive slope, negative y-intercept - z

(iv) negative slope & positive y-intercept - a

(v) negative slope & passing through origin - b

(vi) negative slope & negative y-intercept - c

(vii) parallel to x - axis & with positive y-intercept - p

(viii) parallel to x - axis & with negative y-intercept - q

Lines x, y, z, a, p pass through Quadrant I, we are asked to find (b + c + q)

Given x + y + z + a + b + c + p + q = 35

x + y + z = 15

x = 15/3 = 5, hence y + z = 10

y + z + b + c + q = 23

hence b + c + q = 23 - 10 = 13

Thanks,
GyM
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Re: A student draws 35 lines in the XY plane, none of which are vertical  [#permalink]

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17 Aug 2018, 06:36
chetan2u wrote:
Raksat wrote:
A student draws 35 lines in the XY plane, none of which are vertical and 15 of which have a positive slope. Of those with positive slope, 1/3 also have a positive Y-intercept. If 23 lines have a Y-intercept less than or equal to zero, how many lines contain no point in Quadrant I?
A: 0
B: 7
C: 13
D: 20
E: 35

Hi...
35 lines..
15 positive slope that if x increases y increases and vice versa..
So 1/3 have a positive y intercept, so remaining 2/3 or 10 have negative y intercept or y is 0
But total 23 have negative or zero y intercept, so 23-10=13 of these have negative slope..
So these 13 will never cross the quad I

Ans 13

Total 35 lines
23 of those lines have y intercept $$\leq$$ 0
5 of those lines have y intercept $$>$$ 0
what about the remaining seven lines ?
if they don't have a zero y intercept, or negative y intercept or positive y intercept , what kind of intercept do they have ?

Is it possible to have a line with NO y intercept? Isn't it the same as having a zero Y intercept?
if those 7 lines pass through the origin , then y intercept should be 0 and we should have 23 +7 lines having y intercept $$\leq$$0

Please account for those 7 lines .
Thanks.
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Re: A student draws 35 lines in the XY plane, none of which are vertical  [#permalink]

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19 Aug 2018, 09:12
Raksat wrote:
A student draws 35 lines in the XY plane, none of which are vertical and 15 of which have a positive slope. Of those with positive slope, 1/3 also have a positive Y-intercept. If 23 lines have a Y-intercept less than or equal to zero, how many lines contain no point in Quadrant I?
A: 0
B: 7
C: 13
D: 20
E: 35

Here is my approach.
Line contains no point in Quadrant I means Line has Y-intercept ≤ 0 AND negative slope
Of the 15 lines with positive slope, 1/3 also have a positive Y-intercept --> remaining 2/3 * 15 = 10 lines have Y-intercept ≤ 0
Of the 23 lines have Y-intercept ≤ 0, 10 lines have Y-intercept ≤ 0 AND positive slope --> remaining 23-10 = 13 lines Y-intercept ≤ 0 and negative slope
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Re: A student draws 35 lines in the XY plane, none of which are vertical  [#permalink]

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19 Aug 2018, 09:22
Izzyjust5 wrote:
Raksat wrote:
A student draws 35 lines in the XY plane, none of which are vertical and 15 of which have a positive slope. Of those with positive slope, 1/3 also have a positive Y-intercept. If 23 lines have a Y-intercept less than or equal to zero, how many lines contain no point in Quadrant I?
A: 0
B: 7
C: 13
D: 20
E: 35

Here is my approach.
Line contains no point in Quadrant I means Line has Y-intercept ≤ 0 AND negative slope
Of the 15 lines with positive slope, 1/3 also have a positive Y-intercept --> remaining 2/3 * 15 = 10 lines have Y-intercept ≤ 0
Of the 23 lines have Y-intercept ≤ 0, 10 lines have Y-intercept ≤ 0 AND positive slope --> remaining 23-10 = 13 lines Y-intercept ≤ 0 and negative slope

That can be easily understood , can you help me understand , about the y intercept of the remaining 7 lines , positive 5 y intercept ,zero and less = 23 Y intercept , that makes 28, what about the y intercept of the remaining 7 lines ?
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Re: A student draws 35 lines in the XY plane, none of which are vertical  [#permalink]

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19 Aug 2018, 09:28
1
stne wrote:
chetan2u wrote:
Raksat wrote:
A student draws 35 lines in the XY plane, none of which are vertical and 15 of which have a positive slope. Of those with positive slope, 1/3 also have a positive Y-intercept. If 23 lines have a Y-intercept less than or equal to zero, how many lines contain no point in Quadrant I?
A: 0
B: 7
C: 13
D: 20
E: 35

Hi...
35 lines..
15 positive slope that if x increases y increases and vice versa..
So 1/3 have a positive y intercept, so remaining 2/3 or 10 have negative y intercept or y is 0
But total 23 have negative or zero y intercept, so 23-10=13 of these have negative slope..
So these 13 will never cross the quad I

Ans 13

Total 35 lines
23 of those lines have y intercept $$\leq$$ 0
5 of those lines have y intercept $$>$$ 0
what about the remaining seven lines ?
if they don't have a zero y intercept, or negative y intercept or positive y intercept , what kind of intercept do they have ?

Is it possible to have a line with NO y intercept? Isn't it the same as having a zero Y intercept?
if those 7 lines pass through the origin , then y intercept should be 0 and we should have 23 +7 lines having y intercept $$\leq$$0

Please account for those 7 lines .
Thanks.

5 of the 15 lines which have a positive slope have y intercept $$>$$ 0, not 5 of the total 35 lines have y intercept $$>$$ 0

In general, it is possible to have lines with NO y-intercept. Those lines never intersect the y-axis, or in other words, those lines are vertical (parallel to the y-axis). It is not the same as having a zero y-intercept. If a line is vertical and has a zero y-intercept, it is y-axis.
In this question, the stem clearly states that "A student draws 35 lines in the XY plane, none of which are vertical..." so it's not possible to have lines with NO y-intercept in this case.

Hope it's clear.
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A student draws 35 lines in the XY plane, none of which are vertical  [#permalink]

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19 Aug 2018, 09:45
Izzyjust5 wrote:
5 of the 15 lines which have a positive slope have y intercept >> 0, not 5 of the total 35 lines have y intercept >> 0

In general, it is possible to have lines with NO y-intercept. Those lines never intersect the y-axis, or in other words, those lines are vertical (parallel to the y-axis). It is not the same as having a zero y-intercept. If a line is vertical and has a zero y-intercept, it is y-axis.
In this question, the stem clearly states that "A student draws 35 lines in the XY plane, none of which are vertical..." so it's not possible to have lines with NO y-intercept in this case.

Hope it's clear.

I think you did not understand my question correctly.

May be I am missing something
total 35 lines , 15 have positive slope and 20 have 0 or negative slope ( 20 + 15 = 35)
out of 15 having positive slope, 5 have positive Y intercept
So 10 having positive slope have 0 or negative Y intercept
So total 15 lines have positive slope = 5 lines have positive y intercept and 10 lines have , zero or negative y intercept.
also we know total 23 lines have y intercept $$\leq$$ 0

so 23 + 5 = 28 , what kind of y intercept do the remaining 7 lines have ?
hope now my question is clear.

Edit:

Those 7 lines have positive y intercept but negative slope .

So here is the break up

Total 12 have positive y intercept out of which 5 have positive slope and 7 have zero or negative slope
total 23 have zero or negative Y intercept out of which 10 have positive slope and 13 have 0 or negative slope .

total 35 lines are now accounted for .
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Re: A student draws 35 lines in the XY plane, none of which are vertical  [#permalink]

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19 Aug 2018, 10:11
1
stne wrote:
Izzyjust5 wrote:
5 of the 15 lines which have a positive slope have y intercept >> 0, not 5 of the total 35 lines have y intercept >> 0

In general, it is possible to have lines with NO y-intercept. Those lines never intersect the y-axis, or in other words, those lines are vertical (parallel to the y-axis). It is not the same as having a zero y-intercept. If a line is vertical and has a zero y-intercept, it is y-axis.
In this question, the stem clearly states that "A student draws 35 lines in the XY plane, none of which are vertical..." so it's not possible to have lines with NO y-intercept in this case.

Hope it's clear.

I think you did not understand my question correctly.

May be I am missing something
total 35 lines , 15 have positive slope and 20 have 0 or negative slope ( 20 + 15 = 35)
out of 15 having positive slope, 5 have positive Y intercept
So 10 having positive slope have 0 or negative Y intercept
So total 15 lines have positive slope = 5 lines have positive y intercept and 10 lines have , zero or negative y intercept.
also we know total 23 lines have y intercept $$\leq$$ 0

so 23 + 5 = 28 , what kind of y intercept do the remaining 7 lines have ?
hope now my question is clear.

Edit:

Those 7 lines have positive y intercept but negative slope .

So here is the break up

Total 12 have positive y intercept out of which 5 have positive slope and 7 have negative slope
total 23 have zero or negative Y intercept out of which 10 have positive slope and 13 have 0 or negative slope .

total 35 lines are now accounted for .

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Re: A student draws 35 lines in the XY plane, none of which are vertical &nbs [#permalink] 19 Aug 2018, 10:11
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