A veterinarian calculates the median weight of ten dogs. Later, she ad

Bunuel can you please provide the explanation for this question?

The issue is whether the two added dogs are both greater than the original median (median increases), or if one is greater and the other is less (median stays the same). You should also think about what happens if the all the 10 or 12 dogs have the same weight.

Stat (1)
Although this seems like it would be sufficient because both would be greater than the original mean, there are subtle differences between median and average (mean).

For instance, if the weights are {10, 10, 10, 10, 10, 10, 11, 11, 11, 10000}, then the average will be over 1000. In this contrived example, the two added weights could be 999 and 1100, which would move the median from 10 to 10.5 because the new set is {10, 10, 10, 10, 10, 10, 11, 11, 11, 999, 1100, 10000}.
Insufficient

Stat (2)
Clearly, the median could change. But it could also stay the same: for instance, if the original 10 dogs weigh 10 lbs each, then the median won't change no matter what the 2 added dogs weigh.
Insufficient

Stat (1+2)
The examples described above are both still possible.
Insufficient

(e) Statements (1) and (2) TOGETHER are NOT sufficient to answer the question asked, and additional data specific to the problem are needed.