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# A veterinarian calculates the median weight of ten dogs. Later, she ad

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Math Expert
Joined: 02 Sep 2009
Posts: 61385
A veterinarian calculates the median weight of ten dogs. Later, she ad  [#permalink]

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16 Dec 2019, 00:32
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Difficulty:

95% (hard)

Question Stats:

28% (01:55) correct 72% (01:28) wrong based on 43 sessions

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A veterinarian calculates the median weight of ten dogs. Later, she adds the weights of two additional dogs to her calculations. Is the median of the new list of twelve dogs' weights greater than the median of the original ten?

(1) The weight of one of the added dogs is greater than the average of the original ten, and the weight of the other added dog is less than the average of the original ten.

(2) The weights of the two added dogs are each greater than the median weight of the original ten.

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HEC & IMD School Moderator
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Schools: HEC'22 (J), IMD '22
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Re: A veterinarian calculates the median weight of ten dogs. Later, she ad  [#permalink]

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16 Dec 2019, 01:24
Median of 12 > Median of 10 ??

Statement 1: Insufficient. We do not know the average/median of weights. The average can be greater than median and vice versa. Both situations possible

A D / B C E

Statement 1: Sufficient. The weight of 2 dogs is more than the median of other 10. Surely, there will be a increasing shift of Median.

'B' is the winner.

Bunuel wrote:
A veterinarian calculates the median weight of ten dogs. Later, she adds the weights of two additional dogs to her calculations. Is the median of the new list of twelve dogs' weights greater than the median of the original ten?

(1) The weight of one of the added dogs is greater than the average of the original ten, and the weight of the other added dog is less than the average of the original ten.

(2) The weights of the two added dogs are each greater than the median weight of the original ten.

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Intern
Joined: 20 Dec 2019
Posts: 35
Re: A veterinarian calculates the median weight of ten dogs. Later, she ad  [#permalink]

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27 Dec 2019, 11:03
Old median could be mode, thus even the shift cause median to remain same. This may or may not be the case. Hence insufficient.
Re: A veterinarian calculates the median weight of ten dogs. Later, she ad   [#permalink] 27 Dec 2019, 11:03
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