Are positive integers p and q both greater than n ?

(1) p - q is greater than n
(2) q > p

(i) Clearly, not sufficient;
(ii) Clearly, not sufficient.

Taken together:
We can subtract two inequalities with different signs:
p-q > n -----p > n+q
q > p -------p < q
Subtract and get 0 > n

Since n is less than zero and p and q are positive integers, then obviously n < p or q

Are you sure the correct answer is C?

Let's do two cases for which the stated conditions hold.

Case 1: p= 2, q=3
From condition 1 it follows that n < -1, i.e. n is smaller than both p and q.

Case 2: p=-3, q=-2

From condition 1 it follows that n <-1, i.e. it is unclear whether n is smaller or larger than p and q.

Unless the question states that p and q are positive (integers) I think the correct solution is E (not C).

I second that! In my attempt to solve it i did a whole bunch of things but this was the easiest!

1. A is insufficient because we know p-q>n. This means p>n but q need not be greater than n. We have no further information on q. e.g. 5-2 > 2 but here q = n. So, rule out A.

2. B is insufficient as no information is given on n. So, we can't compare n to p and q.

Together C: we know that q-p MUST be negative and that makes n negative. Since p and q are positive integers its sufficient to answer the question that BOTH p and Q are greater than n.

I suppose the mistake you made is that you didn't read the key word POSITIVE INTEGERS.