Bob can read 30 pages and Jane can ready 40 pages in an hour. Bob star

chetan2u how did you get 5/6?

Yes Sreejit1234, that would be perfect way to read it.
AbhaGanu, 5/6 comes from 50/60, which is to calculate the pages read in 50 minutes.

rate of Bob ; 30/60 ; .5 page per minute ;1/2
rate of Jane ; 40/60 ; .66 page per minute ; 2/3
total mins ahead Bob is 50 mins
so he has read 50*.5 ; 25 pages
target find at what time will they be reading same page
2x/3=25+x/2
x= 150
x= 2hrs : 30 mins
or say 7:50 PM from 5:20 PM
option D

Let's start with a word equation.
The point when both people begin reading the SAME page, we know that both people have read the same number of pages
So we can write: number of pages Bob has read = number of pages Jane has read

Given: Bob starts reading at 4.30 pm, and Jane starts reading at 5.20 pm
In other words, Bob is given a 50-minute head start (aka a head start of 5/6 hours).
So, if we let t = the amount of time, in hours, Jane spent reading, then....
t + 5/6 = the amount of time, in hours, Bob spent reading (since Bob gets to read for an additional 50 minutes)

Output = (rate)(time)
Substitute values into the original word equation to get: (30)(t + 5/6) = (40)(t)
Expand the left side to get: 30t + 25 = 40t
Subtract 30t from both sides of the equation: 25 = 10t
Solve: t = 25/10 = 2.5

In other words, Jane's reading time = 2.5 hours.
Since Jane began reading at 5:20, the time at which they were both reading the same page = 5:20 + 2.5 hours = 5:20 + (2 hours and 30 minutes) = 7:50 PM

Answer: D

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