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Re: Bob can read 30 pages and Jane can ready 40 pages in an hour. Bob star [#permalink]
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chetan2u how did you get 5/6?
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Re: Bob can read 30 pages and Jane can ready 40 pages in an hour. Bob star [#permalink]
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Sreejit1234 wrote:
chetan2u
Can we do this by considering the number of pages as distance and their rated as relative speeds?


Yes Sreejit1234, that would be perfect way to read it.
AbhaGanu, 5/6 comes from 50/60, which is to calculate the pages read in 50 minutes.
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Bob can read 30 pages and Jane can ready 40 pages in an hour. Bob star [#permalink]
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rate of Bob ; 30/60 ; .5 page per minute ;1/2
rate of Jane ; 40/60 ; .66 page per minute ; 2/3
total mins ahead Bob is 50 mins
so he has read 50*.5 ; 25 pages
target find at what time will they be reading same page
2x/3=25+x/2
x= 150
x= 2hrs : 30 mins
or say 7:50 PM from 5:20 PM
option D

paU1i wrote:
Bob can read 30 pages and Jane can ready 40 pages in an hour. Bob starts reading a novel at 4.30 pm and Jane starts reading the same novel at 5.20 pm. then at what time will they be reading the same page?

A. 5.45 PM
B. 7.00 PM
C. 7.20 PM
D. 7.50 PM
E. 8.10 PM
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Re: Bob can read 30 pages and Jane can ready 40 pages in an hour. Bob star [#permalink]
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paU1i wrote:
Bob can read 30 pages and Jane can ready 40 pages in an hour. Bob starts reading a novel at 4.30 pm and Jane starts reading the same novel at 5.20 pm. then at what time will they be reading the same page?

A. 5.45 PM
B. 7.00 PM
C. 7.20 PM
D. 7.50 PM
E. 8.10 PM


Let's start with a word equation.
The point when both people begin reading the SAME page, we know that both people have read the same number of pages
So we can write: number of pages Bob has read = number of pages Jane has read

Given: Bob starts reading at 4.30 pm, and Jane starts reading at 5.20 pm
In other words, Bob is given a 50-minute head start (aka a head start of 5/6 hours).
So, if we let t = the amount of time, in hours, Jane spent reading, then....
t + 5/6 = the amount of time, in hours, Bob spent reading (since Bob gets to read for an additional 50 minutes)

Output = (rate)(time)
Substitute values into the original word equation to get: (30)(t + 5/6) = (40)(t)
Expand the left side to get: 30t + 25 = 40t
Subtract 30t from both sides of the equation: 25 = 10t
Solve: t = 25/10 = 2.5

In other words, Jane's reading time = 2.5 hours.
Since Jane began reading at 5:20, the time at which they were both reading the same page = 5:20 + 2.5 hours = 5:20 + (2 hours and 30 minutes) = 7:50 PM

Answer: D
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Re: Bob can read 30 pages and Jane can ready 40 pages in an hour. Bob star [#permalink]
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Re: Bob can read 30 pages and Jane can ready 40 pages in an hour. Bob star [#permalink]
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