During a sale at a store, Richard purchased five t-shirts

Statement 1 - The ratio of the sum of the marked price of the 2 most expensive items to the marked price of the fourth most expensive item was 16:1
Let the sum of marked price of 2 most expensive items be 80, marked price of 4th expensive will be 5.
Sale price of 2 most expensive items will be 80 *.7 * 1.1 = 61.6
Saving = 80-61.6 = 18.4

To get least saving, we have to maximize 5th items and minimize 3rd items.
We can take both as 5
Total cost of 5 items = 95
Saving on 3rd item = 5 *.23 = 1.15

Overall saving on buying 3 most expensive items will be 19.55 greater than 20 % (19.55 of 95)
If we minimize 5th items, percentage will be certainly greater than the previous case

Sufficient

Statement 2 - The ratio of the marked prices of the three most expensive items was 5:3:1
We can assume the 3 most expensive items as 50,30 and 10. Total saving = 90 *.23 = 20.7
We can now maximize the 2 least expensive items and can take them 10 each.
Total saving = 20 *.2 = 4

Total saving percent by buying 3 most expensive items as percentage of total marked price of all tshirt = 20.7*100/110 less than 20 %

Lets minimize the 2 least expensive items and take them as 0 each or 5 (for easy calculation)
Total saving percent by buying 3 most expensive items as percentage of total marked price of all tshirt = 20.7*100/ 100 greater than 20 %

Not Sufficient

Option A