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From a group of three boys and four girls, a line of children arranged [#permalink]
pushpitkc wrote:
There are 3 options to form this line
All boys form this line
3c2 = 3

All girls form this line
4c2 = 6

One boy and one girl form this line
3c1 * 4c1 = 3*4 = 12

Total number of options = 3+6+12 = 21(Option C)


Missed this part of the solution
As there are 2 ways of arranging the people in the line,
the different type of lines that can be formed are 2*21 = 42(Option B)
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From a group of three boys and four girls, a line of children arranged [#permalink]
Basically, I don't care if there are boys or girls in that line. I just see them as 7 people. Gender is not important here.

Plus, the order matters in that case because they said "a line of children arranged from left to right".

So I used the permutation formula: 7! / (7-2)! = 42.

Answer is B
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Re: From a group of three boys and four girls, a line of children arranged [#permalink]
three boys and four girls= 7 people
available 2 spots
1st spot=7 choice
2nd spot=6 choice
total possible arrangement= 7*6=42
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Re: From a group of three boys and four girls, a line of children arranged [#permalink]
People have provided good explanations for solving this sum. I'd like to give the easiest method to solve the given question in less than 20 seconds.

Since we have been asked about "arrangement", we need to consider 2 different arrangements for each pair of students. (If we were asked about number of possible combinations, we could have used 7C2.

However, in the given question, the operative word is Arrangement. In 90% of the cases, we use the formula for Permutations when asked about "Arrangement"

Hence, the answer will be 7P2 = 7!/(7-2)! = 7!/5! = 42.
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Re: From a group of three boys and four girls, a line of children arranged [#permalink]
Order matters, irrespective of gender. So 7 people can be arranged in 7p2 ways... 42.

Posted from GMAT ToolKit
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Re: From a group of three boys and four girls, a line of children arranged [#permalink]
Bunuel wrote:
From a group of three boys and four girls, a line of children arranged from left to right is to be selected to salute the flag. If exactly two children are in the line, how many different such lines can be formed?

A. 76
B. 42
C. 21
D. 12
E. 7


We have select 2 children out of 3 boys & 4 girls & arrange them in a line. Hence order matters.

For the first slot we can select any child, since it doesn't matter whether a boy or girl is selected = 7 ways
For the 2nd slot we can select a child out of the remaining 6 in = 6 ways

Hence Total # of ways to select & arrange 2 children in a line = 7*6 = 42

Answer B.


Thanks,
GyM
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Re: From a group of three boys and four girls, a line of children arranged [#permalink]
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